FORCES! Flashcards

Question

What is the symbol for directly proportional?

Answer 1

The weight of an object may be considered to act at a single point referred to as the object’s ‘centre of mass’

Answer 2

A number of forces acting on an object may be replaced by a single force that has the same effect as all the original forces acting together.

Answer 3

F resultant =F larger−F smaller

Answer 4

Work= When a force is used to move an object, energy is transferred

Answer 5

work done = force × distance moved along the line of action of the force W = F s work done, W, in joules, J force, F, in newtons, N distance, s, in metres

Answer 6

When a force of 1N moves an object by 1m, then 1J of work is done

Answer 7

1 newton-metre of work = 1 joule

Answer 8

Distance must be in the line of action of the force.

Answer 9

Elastic materials will always return to their original length or shape if we take away the forces acting on them.

Answer 10

a When we stretch inelastic materials, they do not return to their original length when the forces are removed

Answer 11

an elastic object? a force = spring constant × extension F = k e force, F, in newtons, N spring constant, k, in newtons per metre, N/m extension, e, in metres, m

Answer 12

Once a material has gone past its elastic limit

Answer 13

investigate the relationship between force and extension for a spring

Answer 14

1. Set up the apparatus: But a clamp stand with a heavy weight on it to stop it from falling. On the rod of the clamp stand put 2 bosses with 2 clamps. We attach a metre ruler vertically to one of the clamps and a spring (attached with a wooden splint horizontally as a pointer) on the other clamp. Ensure the top of the spring is at the zero point on the ruler 2. Read the position of the ruler on the metre ruler (this is the unstretched length with no force attached) 3. We then add a 1N weight on the spring and read the new position of the pointer on the metre ruler 4. We repeat this continuing adding to add 1N weights to the spring and reading the position of the pointer 5. We need to work out the extension produced by adding each weight. To do that we subtract the length of the unstretched spring from each reading

Answer 15

a linear relationship (directly proportional (straight line) )

Answer 16

exceed the limit of proportionality

Answer 17

speed (m/s) = distance (m) / time (s) SVT DISTANCE-SPEED-TIME

Answer 18

On warmer days sound travels faster compared to cooler days

Answer 19

The velocity of an object is its speed in a given direction. Velocity is a vector quantity.

Answer 20

then it's velocity is constantly changing even though the speed is constant

Answer 21

The acceleration of an object tells us the change in it's velocity over a given time.

Answer 22

v2-u2=2as Final velocity (m/s) - initial velocity (m/s) = 2 x acceleration (m/s2) x distance (m)

Answer 23

When the object stopped accelerating and moves at a constant velocity

Answer 24

If the result force acting on a stationary object is zero then the object will remain stationary If the resultant force acting on a moving object is zero then the object will continue moving in the same direction at the same speed . (save velocity.)

Answer 25

When object is moving out of constant speed, there must be an equal force acting on the opposite side

Answer 26

Acceleration of an object is proportional to the resultant force acting on it and is inversely proportional to the mass of the object

Answer 27

Force = mass * acceleration FMA

Answer 28

An object for main stationary or constantly move at the same speed and direction unless a resultant force is applied.

Answer 29

The inertia mass is a measure of how difficult it is to change the velocity of an object

Answer 30

When two objects interact, the forces they exert on each other is equal and opposite

Answer 31

Steps: 1. Set up the apparatus: Place a trolley on a ramp, connected to a string that runs over a pulley with hanging masses at the other end. 2. Measure mass: Record the mass of the trolley and the hanging weights. 3. Mark starting point: Ensure the trolley starts from the same position each time. 4. Release the trolley: Let go of the trolley and allow it to accelerate as the hanging masses pull it forward. 5. Measure acceleration: Use light gates and a data logger to measure the acceleration of the trolley. Alternatively, use a stopwatch and measure the time taken to travel a known distance, then calculate acceleration using: \text{Acceleration} = \frac{\text{Change in velocity}}{\text{Time taken}} 6. Repeat the experiment: Change the force by adding more masses to the string while keeping the trolley’s mass constant. Record the acceleration for each force applied. 7. Investigate mass variation (optional): Keep the force constant and change the mass of the trolley to see how it affects acceleration.

Answer 32

What Should the Student Find Out? • Acceleration increases as the force increases, confirming Newton’s Second Law: F = ma • Acceleration decreases when the mass of the trolley increases, if force is kept constant. • The results should show a direct proportionality between force and acceleration, meaning doubling the force should roughly double the acceleration.

Answer 33

Ek = 1/2 m v2

Answer 34

All moving objects have a momentum. But if an object is not moving, then the momentum is zero.

Answer 35

Momentum (kg m/s) = mass (kg) x velocity (m/s)

FORCES! Flashcards

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