FORMULAS

Question 1

Trip fuel

Answer 1

Distance / speed X fuel flow

Question 2

ISA temp

Answer 2

15 - (FL or alt X 2)

Question 3

ISA deviation

Answer 3

OAT - ISA temp

Question 4

True Altitude

Answer 4

.004 X ISA deviation X indicated altitude

Question 5

Bearing Change

Answer 5

Degrees of longitude travelled X convergence factor (n)

Question 6

Convergence factor (n)

Answer 6

Bearing change / longitude change

Question 7

Longitude change required

Answer 7

Bearing change / n factor

Question 8

Longitudinal change to produce bearing change

Answer 8

Deg that bearing change occurred / total change X total longitude change

OR

n X longitude change required in degrees

Question 9

Compute TAS of Mach no.

Answer 9

1.00M = 39[OAT kelvin

Question 10

Convert C to Kelvin

Answer 10

Add 273 to the Celsius temp

Question 11

Compute TAS of Mno other than 1.00M

Answer 11

39[OAT kelvin X Mno

Question 12

Distance to ETP (CP)

Answer 12

(Total distance X GSH) / (GSH X GSO)

Question 13

Wind vector length

Answer 13

Distance to nil wind ETP / TAS X wind speed

Question 14

Time to PNR

Answer 14

(Safe endurance mins X GSH) /
(GSH + GSO)

Question 15

Distance to PNR

Answer 15

(Time to PNR X GSO) / 60

Question 16

Distance to NDB/VOR (in minutes)

Answer 16

(Distance flown X 60) / bearing change angle

Question 17

Distance to NDB/VOR (in miles)

Answer 17

(Time to aid X GS) / 60

Question 18

One in 60

Answer 18

60 / track error X rated coverage

OR

distance X track error / 60

Question 19

ADF relative bearing

Answer 19

Difference between aircraft hdg and track

Question 20

Track displacement on an equilateral triangle diversion with wind

Answer 20

Avg. track for diversion, crosswind on said track, time spent diverting

time / 60 X avg crosswind = distance displacement nm

Question 21

HATS

Answer 21

Heading + ADF relative bearing = Track to the station
(Then convert to radial if required when asking from)

Question 22

One nautical mile in feet

Answer 22

6080 ft

Question 23

INS max allowable radial error permitted before maintenance action required (miles)

Answer 23

3 + (3t)

Question 24

Max theoretical range of a VOR

Answer 24

1.23 x height of transmitter sq + 1.23 x height of receiver sq

Question 25

Time conversion

Answer 25

Deg of long. / 15 = hours, every 15 minutes of longitude = 1 minute

Question 26

Distance to NDB/VOR

Answer 26

(Distance flown (nm or min) X 60) / bearing change = nm or min as per equation