Gases Ch 6 Flashcards

(55 cards)

1
Q

Elements that exist as gases at 25 degrees Celsius and 1 atmosphere

A
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2
Q

Some substances found as gases at 1atm and 25degrees Celsius

A

H N O F Cl He Ne Ar Kr Xe Rn

H N O F Cl He Ne Ar Kr Xe Rn
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3
Q

Name some physical Characteristics of Gases

A
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4
Q

What is air made up of?

A

N2 78%
O2 21%

CO2—->
H2O — > these 3 total to 1% trace amnts
Ar——->^

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5
Q

Gas Pressure Unit Conversions

A

760mm Hg (Mercury) =

760 torr =

1 atmosphere =

1.01x10^5 Pascals

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6
Q

What is the pressure in atm if the barometer reading is 688 mm Hg?

A

688mm Hg
————————— = .905 atmospheres
760 mm Hg (per atm)

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7
Q

Who invented the barometer and what year?

A

Evangelists Torricelli in 1643

—Mercury always rose to
760mm at sea level

— Defined standard atmospheric pressure: 760mm High at 0 deg C at sea
level

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8
Q

Pressure of a Gas in Barometer

A
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9
Q

Another example of atmospheric pressure in play would be:

A

Drinking through a straw:
— suck out air
— pressure in straw is lowered
— atmospheric pressure remains
constant
— a vacuum is created and the liquid rushes into the straw to replace air sucked out & to equalize the pressure

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10
Q

What is used to measure pressure of a gas > or = to atmospheric pressure?

A

An OPEN-TUBE Manometer

h + atm pressure = pressure of gas

— the difference in height (h) of the 2 levels plus the atm pressure = pressure of the gas

Open-Tube Manometer
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11
Q

What is used to measure the PRESSURE of a GAS other than atmospheric pressure?

For PRESSURES < Atmospheric Pressure

A

CLOSED-TUBE Manometer

h = the pressure of the gas

H is the difference in height between the 2 levels on the closed-tube manometer

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12
Q

Boyle’s Law

A

Pressure = 1/Volume X K

P proportional to 1/V

Or P = 1/V*k

PV=k

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13
Q

Apparatus for studying the relationship between Pressure & Volume of a Gas

Add mercury, gas volume decreases

A

The J-Tube
As
P(h)-(mercury level) {on right} increases,
Volume of gas {on left} decreases
{inside the J Tube}

Inversely related
As 1 increases,
the other decreases

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14
Q

Boyle’s Law

A

P1V1=P2V2

Pressure “proportional to” 1/Volume

Pressure x Volume= a constant rate of change

0.6atm x 2L volume = 1.2
0.3atm x 4L volume = 1.2 constant rate

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15
Q

Pressure x Volume = Constant

So Boyle’s Law States

A

P1V1=P2V2

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16
Q

A sample of chlorine gas occupies a volume of 946 mL at a pressure of
726mm Hg, what is the pressure of the gas (in mm Hg) if the volume is reduced at constant temperature to 154 mL?

A

4460 mm Hg

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17
Q

The Temp-Vol relationship was created by ?

A

Jacques Charles & Joseph Gay Lussac

It is called Charle’s Law

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18
Q

What does Charles Law State?

A

Volume increases@constant rate of temp
V/T=V/T
Direct Relationship Temp ^ Volume ^

“The volume of a fixed amount of gas at constant pressure is directly proportional to the absolute temperature (in Kelvin) of a gas”

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19
Q

As Gas temperature increases, gas Volume increases proportionally as stated by ?

A

Charles & Gay-Lussac’s Law

The amount of mercury (shows constant pressure amount) which gets pushed up as the volume increases raising the temp reading a direct proportional amount to the increase in volume so if volume goes up 75%, temp goes up 75%

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20
Q

Charles’s and Gay-Lussac’s Law

A

Volume =k+temp (where k is constant)

Volume proportional to temp
V1 = V2
—- —— Temp must be in Kelvin
T1 T2 T (k)= T(Celsius)+273.15

The slope = the slope

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21
Q

What is the lowest theoretically attained temperature?

Who invented it and what year?

A

-273 degrees Celsius

Lord Kelvin called it absolute zero in 1848

Each gas converged at the same -273C=0K —- regardless of pressure

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22
Q

A sample of carbon monoxide Gas occupies 3.20 L at 125°C, at what temperature will the gas occupy a volume of 1.54 L if the pressure remains constant?

A

First convert Celsius to Kelvin!

V1/T1=V2/T2 use Kelvin temp c+273

3.20L/398.15k = 1.54L/?

1.54L x 398.15/3.20L=192K

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23
Q

Volume-Amount Relationship :

Avogadro’s Law states?

A

“At constant temperature and pressure, the volume of gas is directly proportional to the amount (moles) of gas”

TP=held constant
Volume & # of moles chng proportionally
n^v^

24
Q

Avogadro’s Law

A

Volume proportional to moles (n)

V= constant x n (constant = k = slope)

Volume/moles=volume/moles

Constant temp constant pressure

25
Ammonia burns in oxygen to form nitric oxide (NO) and water vapor. How many volumes of NO are obtained from one volume of ammonia at the same temperature and pressure?
1 mole NH3 —-> 1 mole NO At constant T & P 1Volume NH3—> 1 Volume NO 4NH3 + 5O2—-> 4NO + 6H2O
26
Boyle’s Law= + or - gas volume at CT (constant temp)
P= (nRT)*1/v (nRT is constant) INVERSE pressure and volume, V-up, P-down
27
Charles’s Law- heating & cooling a Gas at CONSTANT PRESSURE
Charles’s Law —> V=(nR/p)*T where nR/p is constant
28
Charles’s Law- heating & cooling a Gas at CONSTANT VOLUME
Charles’s Law —>P=(nR/V)*T where nR/V is constant
29
Avogadro’s Law - VAM@ TP (Volume - Avogadro’s - Moles) @ constant temperature & pressure
VOLUME proportional to MOLES of gas @ Constant Temp & Pressure Volume1/Moles1=Volume2/Moles2 V= (RT/p)n where RT/p =constant k Pressure, moles, & volume decrease together Add gas moles, V & P increases
30
Ideal Gas Equations Avogadro’s Law= Boyle’s Law= Charles’s Law=
Avogadro’s Law= V{~n (constant P & T) Boyle’s Law= V{~1/p (constant n & T) Charles’s Law= V{~T (constant n & P) Volume is proportional to: moles, 1/pressure, & temperature V {< (n*T)/P V=constant x nT/p = R*(nT/p) R= the gas constant PV=nRT
31
Ideal Gas =
Hypothetical Gas Who’s PVT behavior can be accounted for by: the ideal gas equation
32
2 INCORRECT assumptions are made to assume a gas is ideal:
Molecules do not attract or repel 1 another (they do attract & repel!) The volume of a gas is negligible compared to the volume of the container (INCORRECT bc the volume of gas is the volume of the container)
33
0 degrees Celsius and 1atm are called
Standard temperature and pressure(STP)
34
Experiments show that at STP, one mole of an ideal gas occupies ?
22.414 Liters R= PV/nT = (1atm)*(22.414L)/(1mol)*(273.15K) The value of R=0.082057 L*atm/mol*K
35
What is the volume (in liters) occupied by 49.8 g of HCl at STP?
Divide the grams by grams in 1 mole = 49.8g HCl / 36.45g HCl = 1.37 mol PV=nRT 1atm(V?)=(1.37mol)*(0.082057k)*(273.15) Volume= 30.7L
36
Argon is an inert Gas used in lightbulbs to retard the vaporization of the filament. A certain lightbulb containing argon at 1.20 ATM and 18°C is heated to 85°C at constant volume. What is the final pressure of argon in the lightbulb (in ATM)?
P1/T1=P2/T2 use Kelvin 18+273.15=291.15 85+274.15=359.15 1.20/291.15=?/359.15 359.15*1.20=430.98/291.15=1.48 atm
37
Ideal Gas Law and Density Moles= n =? PV=? So N/v=? n=M so ? m/VM=? So (m/V=density) Density = ?
Moles= n = g/molar mass g PV=nRT, So N/v=P/RT n=M, so m/VM= P/RT So (m/V=density) so: Density = PM/RT
38
Density calculations where m= mass of gas in grams M= molar mass # of gas D=? Which =?
m/v = mass in grams / volume Which = m/v=pm/RT
39
Molar mass (M) of a gaseous substance M=
M= dRT/P where d=density of gas in g/L
40
A 2.10L vessel contains 4.65g of a gas at 1.00 atm and 27.0°C. What is the molar mass of the gas?
M=dRT/P d=m/v = 4.65/2.10=2.214 T=27+273.15=300.15 2.214*(0.0821 )*300.15/1atm =54.558 g/mol Which could be Mn
41
Gas Stoichiometry Grams or volume of reactant—> Moles of Reactant —>Moles of product ->amount of product (grams or volume) What is the volume of CO2 produced at 37°C and 1.00 ATM when 5.60g of glucose are used up in the reaction C6H12O6 + 6O2–> 6CO2(g)+ 6H2O(l)
5.60g C6H12O6x
42
Dalton’s Law of Partial Pressures when V&T are constant
Ptotal=P1+P2 The total pressure of a mixture of gases is the sum of the individual pressure that each gas exerts
43
Mole Fraction
44
A sample of a natural gas contains 8.24 moles of CH4, 0.421 moles of C2H6, 0.116 moles of C3H8. If the total pressure of the gas is is 1.37 ATM, what is the partial pressure of propane (C3H8)?
Take the total moles of what you’re looking for and divide it by the total of all three moles added together. Then multiply that number by the total pressure of the gases and get your partial pressure atms
45
1848 Lord Kelvin
0K =-273.15 °C ABSOLUTE 0 0 Kelvin The lowest theoretically attainable temperature
46
List some deviations from ideal behavior
 ideal, gas law assumes that molecules in a gas do not exert any force - Ideal gas law also assumes that the volume of the molecules is negligible -
47
Under what conditions do real gases not act like ideal gases? 
—Changes at high pressure >5ATMs, attractive or repulsive forces when molecules are close — changes at low temperature (decreases kinetic energy, so hard to break attractions)
48
Effect of intermolecular forces on the pressure exerted by a gas
49
50
Ideal Gas Law vs. Van der Waals Equation Calculate the pressure of 1.0 mole of CH4 in a 2 L container at 273 Kelvin using the ideal gas law and the Van der Waals equation
Ideal Gas Law P= nRT/V Van der Waals an^2/v^2=
51
The Ideal Gas Law
@ means PROPORTIONAL TO V@1/p @ T @ n VBP= Boyle Volume @ 1/pressure VAM= Avogadro volume @ Moles CVT= Charles Volume @ Temp Volume is proportional to 1/Pressure which is proportional to Temperature which is proportional to Moles
52
Ideal Gas Law
PV=nRT V@1/p (Volume proportional to 1/P) V@T (Volume proportional to Temp) V@n (Volume proportional to moles) R= proportionality ideal gas constant
53
The volume of a fixed amount of gas at constant temperature is inversely proportional to?
Volume is the inverse so the answer is pressure bc P=1/V Volume is inversely proportional to pressure
54
Two assumptions of ideal gases
Molecules don’t exert force on each other The volume of molecules is negligible compared to the container
55
Viscosity
Measure of a fluids resistance to flow