Gravitational Field (DONE) Flashcards
Gravitational field equation
g=f/m
Gravitational field units
Nkg^-1
What is a field
A region where an object experiences a force
What other units can a gravitational field have?
Ms^-2 (acceleration due to gravity)
What kind of quantity is a gravitational field?
- vector quantity
How to draw radial gravitational field diagram
- straight lines towards centre of mass
- with arrows (towards centre of mass)
Types of gravitational field
- radial (drawn from centre point, the field is stronger nearer the centre of mass)
- uniform (field lines are parallel, even field strength throughout field)
Where are gravitational fields found
- around any object with a mass
How do gravitational fields of different objects interact in space
- attractive forces would eventually pull objects together
What is the relationship between the size of attractive force and mass
Force is directly proportional to mass
What does Newton’s third law show when talking about the attractive forces of 2 objects
- the attractive force of object A on object B, is equal to the force of object B on object A.
What is the relationship between attractive force and distance between 2 centre of masses?
F is directly proportional to 1/(r^2)
- meaning if r (distance between centre of masses) doubles the force will quarter.
By bringing all 3 gravitational field equations together, what is newtons law of gravitation?
F is directly proportional to Mm/(r^2)
Therefore:
F = -GMm/(r^2)
What s the value of constant G?
6.67 x 10^-11
What are the units of the constant G?
Nm^2kg^-2
Why is the force of a gravitational field negative?
- because the force is attractive towards centre of mass
What is newtons law of gravitation
F=-GMm/(r^2)
Summarise newtons law of gravitation
- the force between 2 objects is proportional to the product of the masses and inversely proportional to their separation squared.
What is the equation for gravitational field strength
g=-GM/(r^2)
How do you derive the equation for gravitational field strength
1. Sub F=-GMm/(r^2) into g=f/m Therefore: g=-GMm/(r^2)m 2. Cancel terms So: g= -Gm/(r^2)
gravitational field strengths relationship with mass is…
Directly proportional to mass
What is gravitational field strengths relationship with radius
g is inversely proportional to r
G is proportional to 1/(r^2)
How can gravitational field strength and radius be represented on a graph
r on x axis
g on y axis
- from r0 1/(r^2) relationship, line never touches x axis but gets closer and closer
- linear relationship from surface of mass towards centre of mass, gravitational field strength is zero at centre of mass
What is the gravitational field strength at the centre of mass
Zero