Halogenoalkanes-organic chemistry Flashcards

Nucleophilic substitution, elimination, ozone depletion (17 cards)

1
Q

Why are halogenoalkanes polar molecules?

A

The carbon–halogen bond is polar because halogens are more electronegative than carbon, creating a δ+ on carbon and δ– on the halogen. This makes the carbon susceptible to attack by nucleophiles.

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2
Q

What is a nucleophile?

A

A nucleophile is a species with a lone pair of electrons that is attracted to electron-deficient areas. Examples include:

OH⁻ (hydroxide)

CN⁻ (cyanide)

NH₃ (ammonia)

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3
Q

What happens in a nucleophilic substitution reaction?

A

The nucleophile attacks the δ+ carbon, donates its lone pair, and replaces the halogen atom.
R–X+Nu⁻→R–Nu+X⁻
R–X+Nu⁻→R–Nu+X⁻

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4
Q

What is formed when a halogenoalkane reacts with aqueous OH⁻?

A

An alcohol is formed.
Mechanism:

OH⁻ attacks carbon

C–X bond breaks
Example:
CH₃CH₂Br+OH⁻→CH₃CH₂OH+Br⁻
CH₃CH₂Br+OH⁻→CH₃CH₂OH+Br⁻

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5
Q

What is formed when a halogenoalkane reacts with CN⁻ in ethanol?

A

A nitrile is formed.
Mechanism: nucleophilic substitution
Example:
CH₃CH₂Br+CN⁻→CH₃CH₂CN+Br⁻
CH₃CH₂Br+CN⁻→CH₃CH₂CN+Br⁻
This reaction extends the carbon chain.

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6
Q

What is formed when a halogenoalkane reacts with excess NH₃?

A

A primary amine is formed.
Example:
CH₃CH₂Br+2NH₃→CH₃CH₂NH₂+NH₄Br
CH₃CH₂Br+2NH₃→CH₃CH₂NH₂+NH₄Br
(Note: Excess NH₃ prevents further substitution.)

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7
Q

How does C–X bond enthalpy affect the rate of nucleophilic substitution?

A

The weaker the C–X bond, the faster the reaction. Bond strength trend:
C–F>C–Cl>C–Br>C–I
C–F>C–Cl>C–Br>C–I
So iodoalkanes react the fastest.

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8
Q

How can OH⁻ act as both a nucleophile and a base?

A

As a nucleophile, OH⁻ donates a lone pair to a δ+ carbon in a substitution reaction.

As a base, OH⁻ removes a proton (H⁺) from a β-carbon, leading to elimination of HX and forming an alkene.

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9
Q

What product forms when 2-bromopropane reacts with aqueous KOH?

A

Propan-2-ol
Mechanism: nucleophilic substitution (SN2)

OH⁻ attacks the δ+ carbon bonded to Br

Br⁻ leaves

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10
Q

What product forms when 2-bromopropane reacts with ethanolic KOH?

A

Propene
Mechanism: elimination (E2)

OH⁻ abstracts an H⁺ from a β-carbon

Electrons form a C=C bond

Br⁻ leaves

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11
Q

What conditions favour substitution vs elimination?

A

Substitution (SN2): aqueous KOH, lower temperature

Elimination (E2): ethanolic KOH, higher temperature
These conditions affect whether OH⁻ acts as a nucleophile or base.

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12
Q

Outline the mechanism of elimination (E2) in halogenoalkanes.

A

OH⁻ abstracts a proton from β-carbon

Electrons form a double bond

Leaving group (Br⁻) departs
Mechanism is concerted (one-step).

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13
Q

Why is ozone in the upper atmosphere beneficial?

A

Ozone absorbs harmful ultraviolet radiation, protecting living organisms from its damaging effects, such as skin cancer and cataracts.

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14
Q

How are chlorine atoms formed in the upper atmosphere?

A

Chlorofluorocarbons (CFCs), when exposed to ultraviolet (UV) radiation, undergo photodissociation, breaking C–Cl bonds to release chlorine atoms (Cl*).

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15
Q

How do chlorine atoms catalyse the decomposition of ozone?

A

Chlorine atoms catalyse the breakdown of ozone in a two-step process:

First step:
Cl+O₃→ClO+O₂
Cl+O₃→ClO+O₂
Chlorine reacts with ozone, forming chlorine monoxide (ClO*) and releasing oxygen (O₂).

Second step:
ClO+O₃→2O₂+Cl
ClO+O₃→2O₂+Cl
Chlorine monoxide reacts with another ozone molecule, producing oxygen (O₂) and regenerating chlorine (Cl*), which can repeat the process.

This cycle leads to ozone depletion because each chlorine atom can destroy many ozone molecules.

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16
Q

Outline the catalytic cycle of chlorine in ozone depletion.

A

Cl* + O₃ → ClO* + O₂
Chlorine atom reacts with ozone, forming chlorine monoxide (ClO*) and oxygen (O₂).

ClO* + O₃ → 2O₂ + Cl*
Chlorine monoxide reacts with another ozone molecule, producing oxygen and regenerating chlorine, which can continue the cycle.

Each chlorine atom can destroy thousands of ozone molecules before being deactivated.

17
Q

Why was legislation introduced to ban CFCs, and what alternatives were developed?

A

The harmful effects of CFCs on the ozone layer, demonstrated through scientific research, led to their ban under the Montreal Protocol. Chemists have since developed alternative chlorine-free compounds such as hydrofluorocarbons (HFCs) and hydrofluoroolefins (HFOs).