Homologous recombination: overview Flashcards

(44 cards)

1
Q

What are DSBs? (3)

A
  • Double strand breaks generated when 2 complementary strands of DNA are broken simultaneously at adjacent sites
  • 2 DNA fragments become physically dissociated from each other
  • Transcription and replication can no longer happen as a result
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2
Q

What is the consequence of DSBs? (2)

A
  • If not repaired accurately, can lead to various genomic rearrangements such as DNA deletion, translocations and fusions
  • Genomic rearrangements are common in cancer cells that have defects in homologous recombination (HR) as they can’t repair spontaneous DSBs accurately
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3
Q

What are the 2 types of DSBs generated by random DNA damage events?

A
  • Two ended DSBs
  • One ended DSBs
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4
Q

What are the 2 events which result in DSBs?

A
  • Random DNA damage events (two/one ended DSBs)
  • Programmed DSB formation
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5
Q

What are two ended DSBs? (2)

A
  • Classic break in both strands of the duplex
  • Caused by ionising radiation, radio-mimetic chemicals (e.g. bleomycin), mechanical stress on chromosomes
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6
Q

What are one ended DSBs? (2)

A
  • SSBs or alkylation damage may cause replication fork to collapse resulting in a one ended DSB
  • Depletion of nucleotides, alkylation and UV damage can stall replication forks
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7
Q

When are programmed DSBs required? (2)

A
  • In V(D)J recombination in developing lymphoid cells
  • In meiosis to initiate homologous recombination during crossing over to create genetic diversity
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8
Q

How are one ended DSBs formed by a nick in one DNA strand? (3)

A
  • As the replication fork encounters a nick in one DNA strand, the lagging strand joins up with the broken segment, filling the gap on one strand
  • This leaves the leading strand as a one ended DSB
  • Replication can’t proceed without repair
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9
Q

How are one ended DSBs formed by a lesion in one DNA strand? (3)

A
  • DNA lesion (adduct) blocks the progress of the replication fork
  • The lagging strand can’t continue to be made causing fork reversal and a cruciform ‘chicken foot’ structure with the leading strand pairing with the lagging strand instead of the template strands
  • The cruciform structure is cleaved by holliday junction resolvase resulting in a one ended DSB which requires repair
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10
Q

What are endogenous causes of DSBs? (3)

A
  • ROS
  • Metabolic intermediates
  • Oncogene expression
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11
Q

What are exogenous causes of DSBs? (3)

A
  • Radiation
  • Chemotherapy
  • Environmental toxins
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12
Q

When might mechanical stress cause DSBs?

A

During cell migration

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13
Q

What are the 4 pathways for DSB repair?

A
  • Classical non-homologous end joining (c-NHEJ)
  • Homologous recombination (HR)
  • Alternative end joining (aEJ)
  • Single-strand annealing (SSA)
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14
Q

What is c-NHEJ? (4)

A
  • Direct ligation of 2 DNA fragments
  • Restricted to G1, S and G2 phase
  • Doesn’t require broken ends to contain homology or any resection of the break site
  • Rapid but end processing is typically error prone and may lead to chromosome rearrangements such as deletions and translocations
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15
Q

What is HR? (5)

A
  • Usually error free
  • Limited to S and G2 phase
  • Requires extensive end processing of the DNA breaks (5’-end resection)
  • Requires a homologous DNA template sequence
  • Slow but accurate
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16
Q

What is aEJ? (3)

A
  • Requires resection and microhomology (4-20bp) to base pair within the duplex, forming flaps which are removed and religated to repair
  • Limited to S and G2 phases
  • Error prone
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17
Q

What is SSA? (3)

A
  • Requires resection and more extensive homology than aEJ
  • Limited to S and G2 phase
  • Error prone
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18
Q

What factors determine which DSB repair pathway is going to be used? (2)

A
  • Extent of 5’-end resection
  • Level of homology
19
Q

What are the steps of HR? (5)

A
  • DNA end resection
  • Strand invasion
  • Strand extension and second end capture
  • DNA ligation with original fragments and double Holliday junction formation
  • Resolution of the double Holliday junction resulting in non-crossover or crossover products
20
Q

What are the main principles of DNA replication of the leading strand? (2)

A
  • DNA replication is 5’ to 3’
  • ssDNA must be exposed for extension
21
Q

What is DNA end resection in HR? (2)

A
  • Produces a 3’ ssDNA tail from a DSB
  • Requires nucleolytic degradation of the 5’ terminated strands called 5’-3’ end resection
22
Q

What is strand invasion in HR? (2)

A
  • The generated 3’ ssDNA (invading strand) searches for a homologous region on the 5’-3’ template DNA strand through base pairing
  • The 3’ ssDNA displaces the 3’-5’ like template strand and forms base pairs resulting in a D-loop DNA structure
23
Q

What is strand extension and second end capture in HR? (2)

A
  • Extension of the invading strand in the D loop is called first end synthesis and is similar to leading strand synthesis in DNA replication
  • The displaced template 3’-5’ strand pairs with the other 3’ ssDNA end in the broken duplex (second end capture) which is then extended by DNA synthesis
24
Q

What is the role of strand invasion? (2)

A
  • To establish the replication fork-like structure and prepare for DNA synthesis
  • D loop structure is similar to a leading strand replication fork but lacking a lagging strand
25
What is DNA ligation and double Holliday junction formation in HR?
After synthesis, the ends of the 2 DNA fragments are ligated by a DNA ligase and a double Holliday junction is formed
26
What is a Holliday junction?
A branched nucleic acid structure that contains four double-stranded arms joined together
27
How are single Holliday junctions resolved? (2)
- 2/4 of the strands in the structure are nicked by a resolvase enzyme and then religated - Whether the structure cuts horizontally or vertically determines the outcome of the DNA products
28
How does nicking the single Holliday junction horizontally impact the resulting DNA duplexes? (2)
- Parental DNA segments remain covalently linked and are not exchanged resulting in non-recombinant products - Resulting duplex contains some regions of heteroduplex
29
How does nicking the Holliday junction vertically impact the resulting DNA duplexes? (2)
- Parental segments are exchanged resulting in recombinant products - Resulting duplex contains some regions of heteroduplex
30
What are the ways in which a double Holliday junction can be resolved in HR? (2)
- Nicks in the same DNA strands (i.e. the 3'-5' strand of each duplex which are actively tangled in each junction) results in repair without crossover - Nicks in different DNA strands (i.e. one junction is nicked horizontally at the tangled stands and the other vertically at the non-tangled strands) results in crossover products
31
What is chromosomal crossover?
The exchange of genetic material between the damaged and template chromosomes that results in a homologous recombinant
32
What is the alternative to double Holliday junction resolution in HR?
Dissolution of double Holliday junctions
33
What is dissolution of double Holliday junctions? (3)
- The 2 Holliday junctions migrate towards each other - Hemi-catenation occurs where the 2 strands from separate duplexes are wound around each other - Enzymes decatenate the DNA resulting in separation of the duplexes and repair without crossover
34
What are the potential sources of homologous template in HR? (3)
- Usually uses sister chromatids which are formed during DNA replication which is why HR takes place in late S/G2 phase of the cell cycle - Can use homologous chromosomes e.g. crossing over during meiosis - Rarely HR can happen with a non-homologous chromosome resulting in translocations e.g. cancer
35
What are sister chromatids vs homologous chromosomes? (2)
- Sister chromatids are identical copies formed during DNA replication, are joined by the centromere and are separated in anaphase and then called chromosomes - Homologous chromosomes have the same genes but different alleles as one is maternal and the other paternal
36
What are the genetic consequences of HR? (3)
- Crossover with gene conversion (lost gene is replaced with the allele from the homologous chromosome AND the resulting products are recombinant) - Non-crossover with gene conversion (lost gene is replaced with the allele from the homologous chromosome but the products are non-recombinant) - Non-crossover
37
What is gene conversion? (3)
- An event in which a gene in a heterozygous diploid appears to have taken on the identity of its allele - If the alleles were different this causes loss of heterozygosity (LOH) - Distinguished from crossing-over by its nonreciprocal nature
38
What is usually the result of HR in mitotic cells?
Natural bias towards dissolution and non-crossover to limit genomic instability
39
How do mitotic cells limit the effects of gene conversion? (2)
- Use sister chromatids as the template which means HR is restricted to S and G2 phase of the cell cycle - The cohesin complex maintains tight association of sister chromatids, therefore improving genome stability maintenance
40
What are the subpathways of HR? (4)
- 2 ended HR - Synthesis dependent strand annealing - Break induced repair - All result in non-crossover events
41
What is synthesis-dependent strand annealing? (4)
- Same resection and strand invasion as normal HR - NO second end capture, the invading strand is extended and anneals to the other resected end of the DSB - Gap on the other strand is filled and ligated using its original strand (newly repaired) as the template - Result is non-crossover gene conversion
42
What is break induced repair? (6)
- Repair of one ended DSBs caused by replication fork collapse - 5'-3' end resection of break site and ligation of lagging strand with template - Template switching occurs followed by 3' strand invasion forming a Holliday junction - Lagging strand is reprimed and the replication fork is re-established - Single Holliday junction is resolved horizontally or vertically - Results in gene conversion with no crossing over
43
What is the impact of using homologous chromosomes as the template for HR in mitosis vs meiosis? (2)
- High frequency in meiosis to generate genetic diversity - Low frequency in mitosis to prevent loss of heterozygosity which would lead to cancer/disease
44
What is the impact of using sequence from a different chromosome for the HR template in mitosis or meiosis?
Chromosomal translocation which can cause cancer, infertility and inherited disorders