Hooke law Flashcards
(17 cards)
Q: What is Hooke’s Law?
A: Hooke’s Law states that the force (F) required to stretch or compress a spring is directly proportional to the displacement (x), expressed as
𝐹=𝑘𝑥
where
𝑘 is the spring constant
Q: What is the elastic limit of a spring?
A: The elastic limit is the maximum force or stress a spring can endure and still return to its original shape. Beyond this point, the spring is permanently deformed.
Q: How does force relate to elongation in Hooke’s Law?
A: The force applied to stretch or compress a spring is proportional to the elongation. As force increases, elongation increases proportionally (until the elastic limit is reached).
Q: What is the spring constant (k)?
A: The spring constant
k is a measure of the stiffness of the spring, representing the force required to stretch or compress the spring by one meter. Its units are N/m (Newtons per meter).
Q: What does the slope of the F vs. x graph represent?
A: The slope of the F vs. x graph represents the spring constant (k), which indicates the stiffness of the spring. A steeper slope means a stiffer spring.
Q: What are the units of the spring constant (k)?
A: The units of the spring constant are Newtons per meter (N/m).
Q: What is the relationship between the slope of F vs. x and x vs. F graphs?
.
A: The slopes of these two graphs are reciprocals. The slope of the F vs. x graph is
𝑘 and the slope of the x vs. F graph is
1/k
Q: How does the number of coils in a spring affect the spring constant?
A: More coils in a spring decrease the spring constant, making the spring easier to stretch. Fewer coils increase the spring constant, making the spring stiffer.
Q: What happens when a spring is stretched beyond its elastic limit?
A: When a spring is stretched beyond its elastic limit, it no longer returns to its original shape and becomes permanently deformed. Hooke’s Law no longer applies.
Q: What characteristics of a spring affect its spring constant?
A:
Material: Stiffer materials result in a higher spring constant (k).
Coil diameter: Thicker coils increase k.
Length: Shorter springs typically have a higher spring constant.
Number of coils: More coils reduce k, making the spring less stiff.
Q: Will the slope be constant if the spring is compressed instead of stretched?
A: Yes, as long as the spring is compressed within its elastic limit, the slope (spring constant k) should remain constant, as Hooke’s Law applies symmetrically to both compression and elongation.
Q: How do you calculate the elongation of a spring given force and spring constant?
A: The elongation (x) can be calculated using the formula:x=f/k ( f is applied force k is spring constant)
Q: How does the spring constant change when the number of coils in the spring is doubled?
A: Doubling the number of coils makes the spring easier to stretch, reducing the spring constant k, which makes the spring less stiff.
Q: How does the spring constant change with a thicker or thinner wire?
A: Thicker wire increases the spring constant k, making the spring stiffer. Thinner wire results in a lower spring constant, making the spring more flexible.
Q: What do the x vs. F and F vs. x graphs look like for a spring that obeys Hooke’s Law?
A: f vs x: straight line with slope k
x vs f: straight line with slope of 1/k
Stiffer the spring =
larger value of k
What is the relationship between force and elongation for a spring within its elastic limit?
A: The force is directly proportional to the elongation, meaning as the force increases, the elongation increases at a consistent rate, as long as the spring has not reached its elastic limit.
