Iodine Clock Flashcards

1
Q

what does the continuous monitoring method involve?

A
  1. pipette a sample of a mixture to excess sodium hydrogen carbonate.
  2. start stopwatch.
  3. withdraw samples at regular intervals e.g. 3 minutes. repeating the process.
  4. titrate with sodium thiosulphate adding starch indicator near the end.
  5. use results to plot concentration against time on a graph.
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2
Q

what acts as a catalyst in the continuous monitoring method?

A

H2SO4

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3
Q

why are large excess of H2SO4 and propane used in continuous monitoring?

A

so you can measure the influence of iodine.

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4
Q

why should the continuous monitoring experiment be carried out in a well ventilated room?

A

because sodium thiosulphate releases SO2.

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5
Q

how is rate measured in the iodine clock reaction?

A

by measuring how long it takes to produce a fixed amount of iodine.

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6
Q

what is the equation for the reaction of potassium iodide and potassium persulphate?

A

S2O8 2- + 2I- –> 2SO4 2- + I2

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7
Q

what varies in the iodine clock reaction?

A

the concentration of iodine

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8
Q

what do you calculate the order of in iodine clock?

A

order w.r.t. all reactants

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9
Q

outline the iodine clock method (3):

A
  1. sodium thiosulphate and starch added to an excess of hydrogen peroxide and iodide ions in acid solution.
  2. start a stopwatch.
  3. when solution goes bule/black, stop stopwatch.
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10
Q

continuous monitoring is also known as …?

A

the initial rates method.

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11
Q

what is the rate of reaction proportional to?

A

1/T

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12
Q

Errors in the iodine clock reaction?

A
  1. starch indicator effects concentrations. thus the amount they change over time.
  2. inaccurate timing? two people time simultaneously and take an average.
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13
Q

assumptions in the iodine clock experiment: (3)

A
  1. conc. of each reactant doesn’t change significantly over the time period.
  2. temperature stays constant.
  3. when the end point is seen the reaction hasn’t proceeded too far.
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14
Q

what can cause an increase in rate of reaction throughout an experiment?

A

the reaction is exothermic.

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