Kinematics

Question 1

Answer 1

Question 4

Skip part c

Answer 4

Question 5

Only part C

Answer 5

Question 6

Do part a and b but picture contains solution for C

Answer 6

Part a = T = u/g

Question 7

Answer 7

Answer for part b = 15.6m
Picture contains solution for part c

Question 8

Sketch an acceleration time graph for a vehicle that accelerates at 15/16 ms^-2 for 16 seconds. Then maintains a speed of 15ms^-1 for 48 seconds. The car then decelerates at 2.5 ms^-2 for 6 seconds

Answer 8

Question 9

Answer 9

Solution is of part c)

Question 10

Answer 10

Tips on graph :
- line must be straight as acceleration is constant
- Ball hits velocity = 0 before T seconds so line must be going straight down

Question 11

Sketch a velocity time graph of a projectile with initial velocity of 14.7, final velocity of -24.5 and 4 seconds to hit ground first time

Answer 11

Question 12

Answer 12

Question 13

Answer 13

Question 14

Direction of i and j

Answer 14

i is horizontal and j is vertically

Question 16

Answer 16

Question 17

Answer 17

You initially got it wrong because you assumed u was the horizontal velocity

Question 18

Answer 18

Question 19

Answer 19

Trick for part b is that initial vertical velocity is zero because it is projected horizontally

Question 20

Answer 20

For vertical velocity, assume that it can be either final vertical velocity can be positive or negative

Question 22

How should you answer when a question asks find direction of motion of a certain point

Answer 22

Find final velocity for both horizontal and vertical, then proceed to use tan^-1 making horizontal adjacent and vertical opposite
Then say direction is angle below the horizontal

Question 23

Answer 23

Theta = 74.6 degrees

Question 24

If sin a = 0.85, what does cos a equal

Answer 24

Question 25

Answer 25

For part c) it is perpendicular so flip sin/cos equation to tan = cos / sin

Question 27

Answer 27

A) 14 B) 17.2 C) 2.5

Question 28

Answer 28

For Part ii) it travels 18m at 3 seconds, at instantaneous rest. When you sub in t=4, s = 12. That means it has travelled another 6m in another direction but they are asking for distance not displacement. So you do 18+6 =24 24

Question 29

Answer 29

Question 30

Answer 30

Question 31

Answer 31

Question 32

Answer 32

Question 33

Answer 33

Question 34

Answer 34

Question 35

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Question 36

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Question 37

Answer 37

Question 38

r = (7-3t) i + (5 - 15t) j Find value of t when r is parallel to 16i + 5j

Answer 38

(5-15t) / (7-3t) = 5/16 t = 0.2 seconds

Question 39

Answer 39

Question 40

If it asks for magnitude should you do Pythagoras

Answer 40

Yes

Question 41

Answer 41

Question 42

Answer 42

Question 43

Answer 43

Question 45

One improvement to model motion of train

Answer 45

Have train accelerating and decelerating at a variable rate

Question 46

Answer 46

Take t=0 into account

Question 47

Show that P will never move along negative x-axis

Answer 47

Question 48

U is referring to the initial velocity

Answer 48

Question 49

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Question 50

Answer 50

Question 51

What should you do if the questions asks Find time for I and j when I) direction is north-east of O Ii) moving in the north east direction

Answer 51

I) make I and j components equal for displacement ii) make equal for velocity

Question 52

Answer part c only

Answer 52

Question 53

Answer 53

Question 54

H is greatest height of original model

Answer 54

Question 55

If the question gives acceleration to 10, what significant figure should you give your answer to

Answer 55

1 significant figure

Question 56

Answer 56

Question 57

Answer 57

Mistake you made, you calculated in your area, t x 22 after calculating triangle when it should have been (t-30) x22, for part c

Question 58

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Question 59

Answer 59

Question 60

Answer 60