L10 - lab tools for DNA manipulation Flashcards

(22 cards)

1
Q

what are the 5 basic steps in gene cloning

A
  1. contruction of recombinant DNA molecule/plasmid
  2. Transport into the host cell
  3. multiplication of plasmid/DNA molceule in bacteria
  4. division/proliferation of bacterium host cell
  5. produces clones with identical copies of the recombinant DNA

= bacteria is essentially used as a factory to replicate the DNA

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2
Q

is the contruction of the recombinant DNA plasmid in vivo or in vitro

A

in vitro

= outside of the cell in a test tube

CRISPR is in vivo on the other hand as it happens inside the cells

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3
Q

what are the functions of these key enzymes:
1. exonuclease
2. restriction endonuclease
3. phosphatase
4. ligase
5. DNA polymerase

A

exonuclease. = shortening

restriction endonuclease = cutting

phosphatase = modifying

ligase = joining

DNA polymerase = lengthening

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4
Q

compare the effets of DNase 1 and a restriction endonuclease

A

DNase cuts both aingle and doub;e-stranded DNA at non-specific locations with a PREFERENCE of C and T bases

Restriction endonuclease cuts double stranded DNA at specific locations (restriction site)

= one produces lots of random cuts and one can only can at certain/specific locations

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5
Q

what are the components of the restriction/m0dification defence system obf bacyteria against phages

A

Endponuclease = cleaves and cuts foreign DNA inserted

methyltransferase = methylates host DNA preventing endonucleases acting on itself

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6
Q

which TYPE of restriction endonucleases do we mostly use for gene editing and how do they work

A

Type 2 REs

cuts DNA at defined positions close to or within their recognition sequnces

= simple to use

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7
Q

what determines the name given to a Restriction endonuclease

A

which microorganism the enzyme was discovered in

classed into different TYPES according to enzytmatic behavior

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8
Q

what type of sequnces do type 2P REs recognise

A

palindromic sequences 4-8bps in length

= same sequnce in one direcetion as it is on the other strand in the opposite direction

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9
Q
A
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10
Q

what comformation do type 2 REs form to bind and cleave double stranded DNA

A

homodimer

2 identical proteins bind togther prior to binding to DNA

bind in opposite directions to allow the palindromic sequnce on both strands to be recognised and cleaved

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11
Q

what occors when the homodimer type 2P restriction endonuclease binds to DNA

A

bends the DNA 50° , widens minor groove and compresses major groove

= causes unstacking of the bases

unstacking is when the base pairs come apart and the ‘stacked coin’ formation of the base apir on top of one another come apart to reveal areas of DNA for editing

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12
Q

what does widening of the minor groove when a T2P RE binds allow/cause

A

brings phosphodiester bonds/linkages ckoser to the active site of each monomer enzyme

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13
Q

what is the only T2 RE to cause major bending when it binds to DNA

A

EcoRV

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14
Q

what type of ends (sticky or blunt) are created from EcoRV

A

blunt ends

= both monomers cut at the same point on each strand

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15
Q

what is an ‘ambigious’ sequence

A

simiular but not identical sequence

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16
Q

what is ‘Star’ activity of some restriction enzymes

A

cut similiar/ambigious sequnces but not identiocal to their recogntion sequence

17
Q

how large are type 2S restriction endonucleases

A

400-600 amino acids in length

= slightly larger than Type 2p

18
Q

what do type 2S RE recognise and compare this to Type 2P

A

asymetric DNA sequences

= do not read the same forwards and backwards
= each strand is a different sequnence

this is compared to the palindromix sequnces recognised by T2P

19
Q

how do Type 2S RE bind and cleave

A

bind as a monomer and form ‘transient homodimers’

have seperate recognition and cleavage sites unlike T2P

the 2 monomers can bind to sequnces far apart from one another

briefly dimerise causing a loop to form of the inbetween DNA and allowing cleavage (as a homodimer) to occor

20
Q

what is a key point about Type 2S REs that seperates them from T2P

A

seperate recogntion and cleavage domnains

linked togther by a short polypeptiude connector

= causes ‘shifted cleavage’ to one side of the recognised sequence

21
Q

what do the sticky ends produced by Type 2s redsult from - 3 points

A

the sequnce of the overhang depnds on whatever DNA bases are downstream from where the cleavage occurs

Different Type IIS enzymes cut different distances away from the recognition site depending on the ‘reach’ of the enzyme

Because of the helical shape and flexibility of DNA, the exact cut site might shift by a base or two.

22
Q

summarise differences between Type 2P and 2S enzymes

A

2P:
recongition and clevagae domain are the same = cuts within the target sequnce

blunt ends

palindromic sequnces

binds as a homodimer pre-formed

2P:
recognition and clevage domains are seperate held togther by ‘connector’= cuts outside the target sequnce

sticky ends depnding on enzymes ‘reach’

binds as monomers do DNA and forms ‘transient homodimers’

causes DNA looping

asymmetrical sequences