Lect 5 Flashcards

(31 cards)

1
Q

Prokaryotes transcription is catalysed by..
It is complementary to ..and identical to…except

A

RNA polymerase
Template strand/ anti sense
Coding strand /sense
T and U

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2
Q

Upstream
Downstream

A

3’
5’

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3
Q

Promoter is
Start point
Numbers are positive

A

Where RNAP attaches upstrem
+1
Downstream

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4
Q

RNA synthesis phases

A

Template binding and preinitiation complex

Initiation
Elongation
Termination

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5
Q

Termination seq is

A

AAU
AAA

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6
Q

Prokaryotic DNA dependent RNA polymerase does not need

A

Primer
Proofreading

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7
Q

Core RNAP

A

1w
2a
1b
1b’
Can not recognize promoter

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8
Q

Sigma factor

A

Recognizes specific promoter
Released after initiation

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9
Q

Holoenzyme

A

Core enzyme+ sigma factor

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10
Q

Promoter region in 2…..
First is….
Second is….

A

Consensus seq
-35, 5’ TTGACA 3’»> RNAP binds to it determines transcription freq
-10, 5’ TATAAT 3’&raquo_space; TATA box , pribnow,

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11
Q

TATA box function in prokaryotes

A

Facilitates the dissociation bet 2 DNA strands due to many A– T bonds making an open complex

Allows RNAP to gain access to transcription site

Ensures fidelity

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12
Q

A consensus seq is

A

A seq that has the same func in different places in the genome

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13
Q

Preinitiation

Initiation

A

RNAP holoenzyme and promoter region
Goes to +1 and adds complementary nucleotides by removing pyrophosphate and ester bonds

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14
Q

Elongation
After 10 nucleotides…..is released
How DNA unwinds
….supercoils ahead…behind

A

Sigma factor
By helicase activity of RNAP
+Ve, -ve

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15
Q

Positive supercoils relaxed by while negative

A

Gyrase
Topoisomerase 1

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16
Q

During the RNA formation…..forms that is dissociated due to….

A

DNA-RNA hybrid
DNA rewinding

17
Q

Termination rho dependent
What is rho

Binds to

It is

Also …dissociated from the strand

A

A protein that recognizes the termination seq

c- rich strand near the 3’ end of the nascent strand

ATP dependent RNA DNA helicase activity

RNAP

18
Q

Rho independent termination

A

Specific DNA seq known as termination site
40-50 bp
Inverted repeats, palindrome
AT rich then CG rich

19
Q

The transcription of the termination site causes…..due to….

A

Hairpin loop
Being a palindrome, inverted repeat

20
Q

Why a string of U’s at the end of termination site

A

To facilitate unwinding of DNA due to weak attraction of AU

21
Q

Enzymes and their inhibitors
RNA pol Prokaryotic
Mitochondrial RNAP
Eukaryotic Pol II
Eukaryotic pol III

A

Strongly rifampicin
Weakly by rifampicin

Strongly by a- amanitin
Weakly by a- amanitin

22
Q

Eukaryotes transcription have

A

3 nuclear RNAP and 1 mitochondrial
RNA pol I >45 S RNA (18S, 5.8S,28S)
RNA pol II > mrna, snRNA, miRNA
RNA pol III > tRNA, 5S rRna, 1snRna

23
Q

Promoter regions in eukaryotes

A

CAAT box and GC box, -40 to -200 bp, promoter proximal, determine transcription freq

TATA box, hogness box, -20 ,-30 bp
TATAAA
where transcription starts

24
Q

CAAT box func
CG box func

A

CAAT box binding transcription factor CTP

Seq specific DNA binding proteins SP1

25
Factors of RNAPII
A B D E F H
26
TFIID
Only one that directly binds to DNA due to specific high affinity for DNA promoter. TBP,TATA binding proteins 14 TBP associated factors Minor groove
27
TFIIF TFIIH
2nd one to bind and brings RNAPII to promoter site Activates RNAPII BY PHOSPHORYLATION AND KINASE ACRIVITY
28
TFIIH has...activity and...
Kinase, to activate RNAP II Helicase, to separate the 2 DNA strands
29
All the transcription factors leave RNAPII except..
TFIIF Continues to +1 with RNAP forming RNAPII-TFIIF complex
30
Termination in eukaryotes
Very far downstream Consensus seq AAUAAA after passing 1000+ nucleotides RNAPII becomes dephosphorylated and inactivated by phosphatase enzyme
31
At the end of mRNA processing
RNA endonucleases cleave primary mRNA abt 15 bases from consensus seq Pol II - TFIIF complex dissociated