Lecture 3: Heat Engines Flashcards

(16 cards)

1
Q

carnot engine

A

an idealised, reversible heat engine of maximal efficiency operating on a working substance between two thermal reservoirs to convert heat, Q, into mechanical energy, W.

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2
Q

greatest efficiency comes from

A

greatest temperature differences – but materials melting form a practical limit.

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3
Q

carnot cycle breakdown

A

ab: isothermal heat absorption, taking heat Q1 at constant T1

bc: adiabatic expansion with no heat exchange

cd: isothermal heat loss at temperature T2 (<T1)

da: adiabatic compression with no heat exchange

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4
Q

cycle

A

a series of processes that (eventually) return a system to its initial state

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5
Q

heat engine

A

a device operating on a working substance between two thermal reservoirs to convert heat, Q, into mechanical energy, W.

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6
Q

heat engine process

A

extract heat Q1 from hot reservoir: isothermal heating

perform work W using cyclic process: isentropic work out

lose some heat, Q2, to cold reservoir: isothermal cooling

compress fluid again to return to start: isentropic work in

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7
Q

efficiency of engine

A

n = work out of engine / heat into engine

=W/Q1 = Q1-Q2/Q1 = 1-Q2/Q1

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8
Q

conceptual four-stage heat engine

A

hot body, heat in to heat exchanger

turbine - work out

heat exchanger, heat out into cold body

compressor - work in

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9
Q

Kelvin-Planck statement

A

“It is impossible to construct a device that, operating in a cycle, will produce no other effect than the conversion of heat into work.”

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10
Q

implications of Kelvin-Planck statement

A

ie. W < Q1
in essence, 100% efficiency is not possible
implications for power generators, engines, etc.

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11
Q

calusius statement

A

“It is impossible to construct a device that, operating in a cycle, produces no other effect than the transfer of heat from a colder body to a hotter body.”

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12
Q

implications of Clausius statement

A

ie. Q1, ≠ Q2 in fig to left and must have some W
from experience, heat can flow hot to cold but Clausius statement implies that the reverse isn’t spontaneous: it takes work to run a fridge

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13
Q

equivalence of kelvin-planck and clausius forms (1)

A
  1. Consider a heat engine that violates the Clausius statement, transferring heat Q2 from a cold body at T2 to a hot body at T1.
    2.Let it run in parallel with a normal heat engine that extracts Q1 from the hot body, transfers Q2 to the cold body and does work W = Q1 - Q2.
    3.The net result:extraction of heat Q1-Q2 from the hot body, no change to the cold body, work done W = Q1 – Q2.

ie claus violated –> kp violated

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14
Q

equivalence of KP and Claus forms (2)

A

1.Consider a heat engine that violates the Kelvin-Planck statement, extracting heat Q1 from a hot body at T1 to perform work W = Q1
2.Let it run in parallel with a normal heat engine (operating in reverse) that extracts Q2 from a cold body and transfers heat Q3 to the hot body.
3.Energy conservation gives Q3 = Q2+W = Q2+Q1
4.The net result is a transfer of heat from the cold body to the hot body.

both violated both ways round

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15
Q

carnot’s theorem

A

“No engine operating between two thermal reservoirs can be more efficient than a reversible engine operating between those reservoirs.”

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