Lecture 4 Flashcards
DNA strands serve as…
- template
- arrangement and nature of nitrogenous bases allow DNA strands to serve as templates
- complementarity of DNA strands allows each strand to serve as template for synthesis of the other
Semiconservative model of DNA replication
each replicated DNA molecule consists of one old and one new strand
Conservative model of DNA replication
two newly synthesized strands come together and the original helix is conserved
Dispersive model of DNA replication
parental strands are dispersed into 2 new double helices
Meselson and Stahl experiment
- 15N labeled E.coli grown in medium containing 14N
- each new DNA molecule consists of one old and one newly synthesized stand
- provided strong evidence that DNA is semiconservative in prokaryotes
Taylor-Woods-Hughes experiments
- Vicia faba (broad bean) was used to demonstrate DNA replication is semiconservative in eukaryotes
- monitored process of replication with labeled 3H-thymidine and performed autoradiography
Where does DNA replication begin?
At the ORI - origin of replication
What is made at the ORI?
the replication fork which is the product of the unwound helix
How many replication forks are on a strand?
2 because replication is bidirectional
Replicon
length of DNA replicated
How many ORI does bacteria have?
1
- singular circular DNA
- DNA synthesis originates at OriC
- E. Coli replicon consists of entire genome of 4.6 million base pairs
Details about elongation by DNA polymerase I
- occurs in the 5’ to 3’ direction by adding one nucleotide at a time to 3’ end
- nucleotide added, two terminal phosphates cleaved off, providing newly exposed 3’ OH
- 3’ OH can participate in addition of another nucleotide as DNA synthesis proceeds
DNA Pol: I, II, III
- can elongate existing DNA strand
- cannot initiate DNA synthesis without a RNA primer
Exonuclease activity 3’-5’
DNA pol I, II, III all posses 3’-5’ exonuclease activity: proofread newly synthesized DNA, remove/replace incorrect nucleotides
Exonuclease activity 5’-3’
- only DNA polymerase I removes RNA primer
- excises primer - fills in gaps left behind
What are 7 keys issues that need to be resolved during DNA replication?
1) Unwinding of helix
2) Reduce increased coiling generated during unwinding
3) Synthesis of primer for replication
4) Discontinuous synthesis of second strand
5) Removal of RNA primers
6) Joining of gap filling DNA to adjacent strand
7) proofreading
DnaA
- inhibitor protein encoded by gene dnaA
- Binds to ORI causing conformation change
- causes helix to open up and destabilize
- exposed ssDNA
DNA helicase
- made of DnaB polypeptides
- Hexamer of subunits: assembles around exposed ssDNA
- Subsequently recruits holoenzyme to bind replication fork and initiate replication
- Helicases require energy supplied by hydrolysis of A T P—denatures hydrogen bonds and stabilizes double helix
Single-stranded binding proteins (SSBPs)
– Stabilize the open conformation of helix
– Bind specifically to single strands of D N A
DNA Gyrase
– Enzyme relieves coiled tension from unwinding of helix (DNA supercoiling)
– Member of larger enzyme group: DNA topoisomerases
– Makes single- or double-stranded cuts
– Driven by energy released during ATP hydrolysis
Primase: RNA polymerase
– Recruited to replication form by helicase
– Synthesizes R N A primer
– Provides free 3’-O H required by DNA polymerase III for elongation
DNA polymerase I
removes primers and replaces it with DNA
RNA priming
- Universal phenomenon
- found in bacteria, viruses, and several eukaryotic organisms
Double stranded DNA is….
antiparallel
5’-3’
3’-5-