Lysozyme Flashcards

1
Q

name the 2 major forms of lysozymes

A

Human lysozyme in tears
Hens Egg White (HEW) Lysozyme in Eggs

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2
Q

what is the substrate of this enzyme

A

peptidoglycan

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3
Q

what is the non-competitive inhibitor of this enzyme

A

lipopolysaccharide - has highly favoured binding to lysozyme

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4
Q

how does this enzyme act upon peptidoglycan

A

catalytically cleaves peptidoglycan @ active site -> smaller units [E+S-> E+P]

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5
Q

what part of the body does the enzyme effect

A

Hypothalamus

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6
Q

it has a similar mode of action to many other ? enzymes

A

depolymerizing enzymes [breaking down polymerase]

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7
Q

what specifically does the enzyme act upon in the peptidoglycan layer of bacteria

A

catalyzes the hydrolysis of the b(1-4) glycosidic links between N-acetylmuramic acid (NAM) and the N-acetylglucosamine (NAG) residues of the peptidoglycan layer in bacteria.

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8
Q

bacterial cell wall is composed of peptidoglycan which is made of alternating

A

N- acetylglucosamine (NAG or GlcNAc) and
N- acetylmuramic acid (NAM or MurNAc)

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9
Q

the sugar units in peptidoglycan is joined by? and cross-linked by ? which does what

A

β-1-4 glycosidic bond
peptide bridges which stabilises molecules

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10
Q

peptide bridges contain?

A

non-standard L-form and D-form of A.A

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11
Q

how many A.A. does it have

A

129

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12
Q

what word is used -> describe the shape

A

ellipsoid shape [i.e. squashed circle]

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13
Q

what are the 2 domains

A

alpha helical, 3 stranded anti-parallel sheet + 2 helices

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14
Q

what type of bonds are present

A

4 disulphide bonds - 2 in each domain

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15
Q

is NAG3 hydrolyzable

A

non-hydrolyzable- competitive inhibitor i.e. binds -> same site as substrate

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16
Q

the cleft in the enzymes active site van be completely occupied by how many sugar residues

A

6

17
Q

what determines the substrate binding

A

a number of H bonding interactions

18
Q

what was the most abundant product from the catalyzed hydrolysis of a 6 unit substrate using this enzyme- this confirms the cleavage occurs where

A

(ABCD)4 and (EF)2
NAM [D residue] and NAG [E residue]
NAG(A)-NAM(B)-NAG -NAM(D)-NAG(E) –NAM(F)

19
Q

THE PHILIPS MECHANISM
Modelling further showed that two x residues are near hydrolyzed bond (Asp52 and Glu35). [@ Position y and z in the 129 amino acid chain]
At optimum pH for lysozyme (pH q ), Asp52 (pKa x) would be de-protonated, and Glu35 (pKa y) protonated.
NB pKa corresponds to the pH at which the concentration of x and y forms are equal

A

x = acidic
y = 52 and z= 35
q = 5
pka 3.5
pka 6.3
ionised and neutral forms

20
Q

Mechanism of Lysozyme acc-> Philips model
Mechanism (Phillips Model)
1) The x group of Glu 35 donates a H+ to the glycosidic oxygen between the D and E ring.
2) This creates a Y charge on the C1 of the D ring (a carbonium ion).
3) The E and F residues are broken off and hence x away.
4) The carbonium ion intermediate then reacts with y- from the solvent (H2O) and Glu 35 becomes x
The ABC&D residues diffuse leaving the enzyme ready to work again.

Key features of the enzymatic mechanism
a) Acid base catalysis
b) Carbonium ion formation stabilised by Asp 52 (negative charged carboxylate stabilises carbonium group)
c) Distortion and strain on the bound peptidoglycan. Focused between D & E residues

A

x = -COOH
Y = positive
x = diffuse
y = -OH
x = protonated