Mech Vent Equations Flashcards

1
Q

Cycle time =

A

(60 sec/min)/RR
AND
Ti + Te

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2
Q

Ti =

A

(cycle time)/(I + E)

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3
Q

Tidal Volume (VT) =

A

Flow x Ti

*flow in L/sec

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4
Q

Minute Ventilation (VE) =

A

RR x VT

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5
Q

Flow (l/min) =

A

(I + E ratio) x MV

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6
Q

Compliance =

A

VT/(Pplat - PEEP)

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7
Q

what are the units for compliance?

A

L/cmH2O

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8
Q

Resistance =

A

(Ppeak - Pplat)/flow

*flow in L/sec

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9
Q

what are the units for resistance?

A

cmH2O/Lsec

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10
Q

DO2 =

A

CO x CaO2

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11
Q

CaO2 =

A

([Hb] x 1.34 ml O2/g Hb x SaO2) + (PaO2 x 0.003)

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12
Q

CvO2 =

A

([Hb] x 1.34 ml O2/g Hb x SvO2) + (PvO2 x0.003)

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13
Q

VT goal, RR goal, Ve goal =

A

(PaCO2 now - PaCO2 goal)/PaCO2 goal
**is VT safe? –> < 8 ml/kg?
** is RR safe? –> < 35 bpm
Also NOTE: Pplat less than or equal to 30 cmH2O and driving pressure less than or equal to 15 cmH2O

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14
Q

FiO2 goal =

A

(FiO2 now/PaO2 now) = x/PaO2 goal

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15
Q

Time Constant (TC) =

A

Resistance (cmH2OL/sec) x Compliance (cmH2O/L)

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16
Q

What are the set parameters in volume control?

A

VT and flow

Ti is determined by the flow and VT settings

17
Q

If you increase VT in VCAC, how will Ti change?

A

In VCAC, Ti is influenced by VT and flow.
VT = Ti x flow –> Ti = VT/flow
So if you increase VT, Ti will increase.

18
Q

How will increasing RR affect Te?

A

Increased RR will decrease the amount of time for Te

19
Q

In VCAC, how will a change in compliance change VT?

A

VT will stay the same because in VCAC, VT is set

20
Q

in VCAC, how will an increased VT change Pplat and Ppeak?

A

Pplat will increase, and thus Ppeak will increase because Ppeak is built on top of Pplat

21
Q

How will decreased compliance change Pplat and Ppeak in VCAC?

A

C = VT/(Pplat-PEEP)

So if C decreases and VT is set, then Pplat will increase and Ppeak will increase (since Ppeak is built on top of Pplat)

22
Q

How will Pplat change with increased resistance in VCAC?

A

stays the same

23
Q

In VCAC. the patient’s resistance increases, what will happen to flow?

A

Flow is a set parameter in VCAC, thus it will no change.

24
Q

How will the I:E ratio change with increased RR?

A

the I:E ratio will decrease

25
Q

In PCAC, the patient’s resistance increased, what affect will this have on VT?

A

If they are still meeting 3TCs (i.e. Ti > 3 TCs) then the pressure still has time to equalize so the delivered volume doesn’t change.
If Ti < 3 TCs (i.e. they are not meeting 3TCs) due to the increased R then VT would decrease (because increased R would increase 1 TC, and thus increase 3 TCs)

26
Q

In PCAC, how would increased resistance affect flow?

A

remember R = (Ppeak - Pplat)/Flow
With increased R, flow would decrease because a smaller diameter is more resistance to flow. Its more difficult to deliver the volume because the resistance has decreased the flow.

27
Q

In PCAC, the patient’s resistance decreased, what affect will this have on VT?

A

If they are still meeting 3TCs (i.e. Ti > 3TC) then the pressure still has time to equalize and so the volume will not change.
if they are not meeting 3TCs (i.e. Ti < 3TCs) due to the decreased resistance then VT would increase (because there is less resistance for VT to flow)

28
Q

In PCAC, the patient’s compliance increased, what affect will this have on VT?

A

Increased compliance means it will take more time for pressure to equalize because more volume is needed. .
Thus volume will increase, whether they are meeting 3 TCs or not.
*VT = C/P, and P is constant!

29
Q

In PCAC, the patient’s compliance decreased, what affect will this have on VT?

A

Decreased compliance means it will take less time for pressure to equalize because less volume is needed.
Thus, volume will decrease whether they are meeting 3 TCs or not.
*VT = C/P, and P is constant!

30
Q

In PCAC, how could a change in compliance or resistance affect Ti?

A

Ti is set in PCAC, so there would be no change to Ti.

31
Q

T/F: square waveform has a short Ti than decelerating waveform

A

True!

32
Q

T/F: decelerating waveform has a lower peak pressure than square waveform

A

True!

33
Q

T/F: there is better distribution of ventilation with square waveform

A

False! There is better distribution of ventilation with decelerating waveform - as long as you increase the flow to maintain the same Ti.
This is because 1/2 way through the breath a larger % of the volume will be delivered compared to square.

34
Q

T/F: the I:E ratio decreases when you switch to decelerating

A

False, it increases!