Mechanisms Flashcards

nucleophilic substitution, electrophilic addition (26 cards)

1
Q

nucleophilic substitution of bromoethane and aqueous alkali NaOH

A

forms ethanol (an alcohol) + Bromide ion

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2
Q

Nucleophilic substitution of bromoethane reacting with ethanolic (concentrated) potassium cyanide (KCN in ethanol) when heated under reflux.

A

forms PROPANENITRILE

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3
Q

Nucleophilic substitution reaction with the ammonia NH3 - Bromoethane (halogenoalkane) reacts with an ethanolic solution of excess (concentrated) ammonia (NH3 in ethanol) is heated under pressure.

A

forms ETHYLAMMONIUM

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4
Q

second step: an ammonia molecule may remove one of the hydrogens on the -NH3+.

A

forms a ETHYLAMINE (primary amine)

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5
Q

Nucleophiles have lone pairs.

A

They can form a dative bond with H+. They are bases.

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6
Q

Under different conditions OH- will act as a base. what will it divert from the expected and what is the mechanism called?

A

Different conditions result in different results. Remove H+ ions from halogenoalkanes. Elimination

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7
Q

Conditions of elimination

A

Heat
Ethanol as solvent (no water present)
concentrated potassium hydroxide

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8
Q

In an elimination reaction

A

An organic molecule lose a molecule.

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9
Q

What is the small molecule lost by organic molecule?

A

Hydrogen halide (HX)

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10
Q

The halogenoalkanes are HEATED with ETHANOLIC KOH causing the C–X bond to break heterolytically forming an X- ion.

A

Forms an ALKENE as the organic product.

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11
Q

Elimination Mechanism

A
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12
Q

Alkenes are susceptible to attack by electrophile (lone pair acceptors)

A

the C=C double bond is very rich due to the electron cloud of the pi bond.

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13
Q

In addition reaction, the C=C bond open up

A

an atom or group atoms joins onto each C of the C=C double bond.

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14
Q

What does electrophilic addition reaction include the addition of:

A

Steam
Hydrogen Halide (HX)
Halogens

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15
Q

Hydrogen Halide (HBr)

A

polar molecule due to the hydrogen and halide having different electronegativity.

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16
Q

HBr

A

The bromine atom has stronger pull on the electrons in H - Br bond.
Br atom has a partial negative (delta negative) and the H atom a partial positive

17
Q

Electrophilic addition But-2-ene + H-Br
the H atom acts as an electrophile and accepts a pair of electrons from the C=C bond in the alkene.

A

The H-Br bond breaks heterolytically forming a Br- ion.
This results in the formation of a highly reactive cation intermediate which reacts with the Br-.
2 Bromobutane

18
Q

Br2

A

Non polar molecule as both atoms have similar electronegativity and therefore share equally the electrons in the covalent bond.

19
Q

Electrophilic addition: ethene + Br2

A

when a bromine molecule gets closer to the double bond of an alkene, the high electron density repels the electron pair in the Br-Br away from the closest Br atom.

20
Q

Electrophilic addition reaction with (cold) concentrated H2SO4: The partially positive (δ+) hydrogen atom acts as an electrophile. It is attracted to the high electron density of the c=c double bond in the alkene and accepts a pair of electrons. δ

A

The H-O breaks heterolytically, forming a hydrogen sulfate ion, HSO4-.
A highly reactive carbocation intermediate is formed which reacts with the HSO4-.
Produces Ethyl (alkyl) hydrogen sulfate

21
Q

What is the name that refers to the positively charged ion H3O+?

A

A hydroxonium ion

22
Q

How is a hydroxonium formed?

A

Formed when an acid molecule dissolves in water and donates a hydrogen ion (proton) to a water molecule.
This is how H+ ions exist in aqueous solutions.

23
Q

water is a weak electrophile. what is the exception to this?

A

Unless it undergoes (electrophilic) addition reactions with alkenes in the presence of a strong acid which acts a catalyst.

24
Q

What are the strong acids that could be used?

25
The first reaction step:
The pi bonds in the c=c double bonds are attracted to the H3O+, Heterolytic fission occurs and a carbocation is formed
26
water acts as a nucleophile: donates a pair of electrons to the positive carbon atom forming the C-O bond
An Equilibrium is established between the positive product and the deprotonated product (alcohol)