Mod 2 Flashcards by JAKE GORDON

Electric Field

E=k*(Q/r² )

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Electric field at point P on the rod option 1

E= -λ/4πε * (1/L+a - 1/a)

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electric field point P on the rod option 2

E=Q/4πεa(L+a)

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If flux comes out at an angle

EAcosθ

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E inside a sphere a is radius of sphere a radius r to point inside (uniform density positive charge)

E=Qr/4πεa³

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E outside a sphere, a is radius of sphere a radius r to point outside (uniform density, positive charge)

E=Q/4πεr²

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line of positive charge, infinite length, constant density

E=2k*(λ/r)

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electric field to an infinte plane of positive charge uniform density (both directions)

E= σ/2ε

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Force

F=q*E

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ΔU

-qEd

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potential energy of a system with two charges

k(Qq/d)

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ke(q/r) add for a group of charges

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ΔU of the system when a new charge comes from infinity

ΔU=newq * V tot

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Ex , y ,z

-dV/dx, y ,z

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V at a point far from dipole on the axis

V=-pke/x²

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Ex at a point far from dipole on the x axis

Ex=2pke/x³

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ΔV between any points on the surface of a charged conductor in equilibrium

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capacitance of a spherical conductor

4πεr

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capacitance of coaxial cylinders large radius b small radius a

C=ℓ/(2keln(b/a))

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Work to transfer a charge from one plate to another

W=Q²/ 2C

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The work in charging a capacitor shows up as electric potential energy

U=1/2 C (ΔV)²

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ΔV with a dielectric

ΔV= oldΔV/κ

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C with a dielectric

C=κ*OldC

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Parallel plate capacitor with dielectric

C=κ*(εA/d)

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ΔQ through a conductor A is cross sectional area | n is charge carriers per unit volume

ΔQ=(n*A*Δx)q

Drift speed

ΔQ=(n*A*velo*Δt)q

Iavg in another way

n*q*drift speed* A

Resistance

ΔV/I

conductivity

R=ℓ/σA

Rate of loss of electric PE also gain of internal energy by resister

IΔV

alternate power equations

P=ΔU/t

voltage drop in series

I1R1+I2R2

parallel voltage change is

equal

for a diplole max ΔU

ΔU=-p* E where p is 2aq a is distance between the charges

total F=

qE+qv * B

qBr=

2πr/v

because ΔKE +ΔU = 0

v=√-2qΔV /m

velocity for a particle to stay going exactly straight

v=E/B

mass spec double field

m/q=rB1B2/E

biot savart with a loop

B=μIr²/(2(r²+x²)^3/2

solenoid

B=μ*(loops/length)*I

amperes force on wire one

F=I1*ℓ*B2

Fb is

IL x B really (qv x B)number of charges* crosssection area* Length

maximum torque

I*Area*B

ε for going through a loop

-d/dt (BAcosθ)

Φb for moving

Bℓx x is distance traveled

ΔV=

Eℓ=Bℓv ℓ lis length of the bar

-Bℓvelo

IεI/R = Bℓv/R

vi*e^(-t/τ) . where τ=mass*R/B²ℓ²

ΦB=BAcosθ =

BAcoswt

circular electric loop E=

ε/2πr = -r/2 * dB/dt

Imax =coswt

magnetic field in solenoid with max current

B=μnImax coswt

E in a solenoid with changing mag field

E=(μnImaxw)/2 all times rsinwt

w/k =λf

E or B

EorBmax cos(kx-wt)

Emax/Bmax =E/B

Pointying I=Savg=

cB²max /2μ or E²max/2μc or EmaxBmax/2μ

I for polarization

I=Imaxcos²θ . maximumwhen θ=0 or 180 0 when θ=90

sinθ2/sinθ1

v2/v1

c/v or λvacuum/λin medium

λ1n1=

λ2n2

velo=

f*λ

sinθ critical =

n2/n1 n1 must be bigger than n2

Mag=

image height over object heihgt hprime/h

n1/p

-n2q

Power in diopters = 1/f

f must be negative for a diverging lens (cures nearsightedness)

ybright= . y dark

Ltanθbright . Ltanθdark

small angles ybright

L(mλ/d)

small angles ydark

L(m+.5)λ all over d

phase difference Esin(wt+phi)

phi=2π/λ all times dsinθ

I= time averaged light intensity

Imaxcos²(πdsinθ/λ) I max is the intensity at point O

n1>n2 n1

no phase change, phase change 180

constructive

2nt=(m+.5)λ

destructive

2nt=mλ

to be resolved the angles subtended must be bigger than

θmin=λ/a

when theta is small

d=Lθmin

inverse of grooves per cm

if wavelength is bigger than λc

no photoelectrons ejected

momentum of a photon

E/c = h/ λ

group speed of the wave packet is identical

to the speed of the particle that it is modled to represent

uncertainty way #2

ΔEΔt≥ ℏ/2

angular momentum of an electron

L=mvr

bohr model angular momentum of electron

L=nℏ

for other elements energies

En equation but add Z^2 on the numerator where Z is protons in nucleus

express mass as

MeV/c^2

electric field just outside a charged conductor is perpendicular to the surface and has a magnitude of

E= σ/ε

energy stored in a capacitor

.5(εAd)E^2

mag flux

Delta BA

qB/m

λ allowed wavelengh corresponds to a quantum state

2L/n

magnification

-n1q/n2p

E of laser / energy of photon

photons per second

Mod 2 Flashcards

A (95 cards)