Module 4.2 - Alcohols, Haloalkanes and Analysis Flashcards
(42 cards)
What is the general formula of alcohols?
CnH2n+1OH
What are the 3 groups an alcohol can be classified as?
- primary alcohol
- secondary alcohol
- tertiary alcohol
What is a primary alcohol?
Has the functional group attached to a carbon with no more than one alkyl group
What is a seconday alcohol?
Has the functional group attached to a carbon atom with two alkyl groups
What is a tertiary alcohol?
Has the functional group attached to a carbon atom with three alkyl groups
Explain the trend in boiling point of alcohols as chain length increases.
- bp increases as chain length increases
- more areas of surface contact as higher Mr
- stronger induced dipole dipole intermolecular forces
- more energy to overcome these attractive forces so higher bp
How does the boiling point of alcohols compare to their corresponding alkanes?
- bp of alcohols higher than corresponding alkanes
- H bonds between alcohol molecules
- H bonds stronger than London forxes
- so more energy needed to overcome
- so higher bp
Describe the volatility of alcohols. How does this compare to the corresponding alkane?
- volatile substances evaporate at RTP
- volatility increases as bp decreases
- increases in chain length = decrease in volatility
- less volatile than corresponding alkane from H bonds
Describe the solubility of alcohols in water, and how this is affected by an increase in chain length.
- water molecules are polar as is the alcohol functional group
- methanol, ethanol and propanol are soluble in water as form H bonds w water (sometimes described as miscibility)
- as chain length increases, solubility of alcohol decreases as the aliphatic chain can’t form H bond and this becomes the larger part of the molecule
What are the products when an alcohol burns completely?
- carbon dioxide
- water
Describe the distillation of primary alcohols.
- gently heat
- forms an aldehyde (partial oxidation)
- acidified potassium dichromate (VI) (K2Cr2O7, Cr2O72-) and sulphuric acid (H2SO4, H+) catalysts
C2H5OH + [O] –> C2H3HO + H2O
- aldehyde formed has to be distilled immediately to prevent further reaction
- colour change from orange to green

Describe the reflux of primary alcohols.
- heat strongly
- forms an carboxylic acid (full oxidation)
- acidified potassium dichromate (VI) (K2Cr2O7, Cr2O72-) and sulphuric acid (H2SO4, H+) catalysts
C2H5OH + 2[O] –> C2H3HO + H2O
-colour change from orange to green

Describe the reflux of secondary alcohols.
- heat strongly
- forms an ketone (full oxidation)
- acidified potassium dichromate (VI) (K2Cr2O7, Cr2O72-) and sulphuric acid (H2SO4, H+) catalysts
C2H5OH + [O] –> C2H3HO + H2O
-colour change from orange to green

What is reflux?
The constant boiling and condensing of a reaction mixture. This ensures that the reactions goes to completion as fully as possible without losing reactants or products as vapour goes into the air
How could you use a laboratory test to classify an unknown alcohol?
- heat the test alcohols w excess acidified potassium dichromate (VI) under reflux
- if no colour change to green it’s tertiary
- if colour change to green, distil product and test w Fehling’s solution or Tollen’s reagent
- second colour changes indicates test alcohol is secondary, but no second colour change indicates test alcohol is primary
Describe the dehydration of an alcohol.
- water is lost from organic compound
- elimination reaction
- alcohols heated w strong acid (e.g. H2SO4) water elimintated to make an alkene
- OH group from one C and H from adjacent C lost to form water
- π bond forms between the 2 adjacent C atoms

Describe the halide substitution as a halide ion reacts with an alcohol.
- ROH + HX –> RX + H2O
- forms a haloalkane
- reagant is a hydrogen halide (for bromide, NaBr used which forms HBr in H2SO4)
- conc acid catalyst e.g. conc H2SO4
- with iodide, H3PO4 used as H2SO4 oxidises I- to I2 so yield of iodoalkane would be v low
- mixture warmed to increase rate of reaction

What are primary haloalkanes?
Halogen is at end of chain
Describe and explain the reactivity of haloalkanes.
- large difference in electronegativity between carbon and halogens so polar bond (e- spend more time at X than C in C-X) so 𝛿+ on C atom and 𝛿- on halogen
- 𝛿+ C attacked by atoms, molecules or ions with partial or full negative charge (H2O, OH-, NH3) which are nucleophiles
What factors affect the rate of reaction of haloalkanes?
- strength of C-X bond (going down group halogens get larger so bonding electrons are further form nucleus and have more shielding so lower mean bond enthalpy so C-X easier to break. Higher bond enthalpy = less likely halogen will react to nucleophilic substitution reactions)
- polarity of C-X bond (electronegativity decreases down group so polarity of C-X decreases down group. Most polar molecules are most likely to react)
- bond enthalpy is more important i.e. C-Cl is most polar but as C-Cl have highest bond enthalpy they have the slowest rate of hydrolysis
What is a nucleophile?
Electron pair donor
What is a nuclophilic substitution reaction?
A chemical reaction in which an atom or group of atoms is exchanged for a nucleophile
How does a haloalkane undergo hydrolysis (by nucleophilic substitution)?
- water often used as reactant
- one of the H-O bonds undergoes heterolytic fission producing OH- nucleophile, or can come from an aqueous alkali as has solution of OH- ions. Aqueous alkali is faster than using water
- species attacks electron deficient C atom in haloalkane molecule
- once nucleophile bonded to haloalkane, C-X bond undergoes heterlytic fission to produce a halide ion

How could you measure the rate of hydrolysis of the C-X bond in haloalkanes?
- rate of a chemical reaction is change in conc of a reactant or product over time
- one of the products of this hydrolysis is X- ion, halide ion
- reacts w silver nitrate to form the coloured silver halide ppt
- time to form coloured ppt used to determine rate of hydrolysis

