Molec and Cell 5 Flashcards

(125 cards)

1
Q

The role of DNA in heredity was first discovered by studying what?

A

bacteria and the viruses that infect them

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2
Q

Frederick Griffith

A

1928: worked with two strains of a bacterium, one pathogenic and one harmless

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3
Q

transformation

A

a change in genotype and phenotype due to assimilation of foreign DNA

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4
Q

Griffith’s experimental process

A

When he mixed heat-killed remains of the pathogenic strain with living cells of the harmless strain, some living cells became pathogenic

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5
Q

Oswald Avery, Maclyn McCarty, and Colin MacLeod

A

1944: announced that the transforming substance was DNA based on experimental evidence that only DNA worked in transforming harmless bacteria into pathogenic bacteria

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6
Q

bacteriophages (or phages)

A

viruses that infect bacteria

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7
Q

Alfred Hershey and Martha Chase

A

1952: experiments showing that DNA is the genetic material of a phage known as T2

they designed an experiment showing that only one of the two components of T2 (DNA or protein) enters an E. coli cell during infection

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8
Q

Erwin Chargaff

A

1950: DNA is a polymer of nucleotides, each consisting of a nitrogenous base, a sugar, and a phosphate group

DNA composition varies from one species to the next

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9
Q

Chargaff’s rules

A

that in any species there is an equal number of A and T bases, and an equal number of G and C bases

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10
Q

Maurice Wilkins and Rosalind Franklin

A

X-ray crystallography to study molecular structure

Franklin produced a picture of the DNA molecule using this technique

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11
Q

Franklin’s X-ray crystallographic images of DNA did what?

A

enabled Watson to deduce that DNA was helical

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12
Q

DNA shape and X-ray advantage

A

The X-ray images also enabled Watson to deduce the width of the helix and the spacing of the nitrogenous bases

The width suggested that the DNA molecule was made up of two strands, forming a double helix

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13
Q

Franklin’s conclusion

A

two antiparallel sugar-phosphate backbones, with the nitrogenous bases paired in the molecule’s interior

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14
Q

Watson and Crick

A

Determined pairing a purine with a pyrimidine resulted in a uniform width consistent with the X-ray

adenine (A) paired only with thymine (T), and guanine (G) paired only with cytosine (C) (Consistent with Chargaff’s rule)

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15
Q

Watson and Crick also suggested what?

A

that the specific base pairing suggested a possible copying mechanism for genetic material

Since the two strands of DNA are complementary, each strand acts as a template for building a new strand in replication

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16
Q

Watson and Crick’s semiconservative model of replication

A

when a double helix replicates, each daughter molecule will have one old strand (derived or “conserved” from the parent molecule) and one newly made strand

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17
Q

Matthew Meselson and Franklin Stahl

A

supported the semiconservative model

They labeled the nucleotides of the old strands with a heavy isotope of nitrogen, while any new nucleotides were labeled with a lighter isotope

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18
Q

origins of replication

A

where the two DNA strands are separated, opening up a replication “bubble”

A eukaryotic chromosome may have hundreds or even thousands of origins of replication

Replication proceeds in both directions from each origin, until the entire molecule is copied

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19
Q

replication fork

A

At the end of each replication bubble is a Y-shaped region where new DNA strands are elongating

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20
Q

Helicases

A

enzymes that untwist the double helix at the replication forks

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21
Q

Single-strand binding protein

A

binds to and stabilizes single-stranded DNA until it can be used as a template

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22
Q

Topoisomerase

A

corrects “overwinding” ahead of replication forks by breaking, swiveling, and rejoining DNA strands

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23
Q

Where are nucleotides added to DNA elongation?

A

they can only add nucleotides to the 3’ end

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24
Q

primer

A

short RNA initial nucleotide strand for DNA elongation

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25
primase
An enzyme that can start an RNA chain from scratch and adds RNA nucleotides one at a time using the parental DNA as a template
26
DNA polymerases
catalyze the elongation of new DNA at a replication fork Most DNA polymerases require a primer and a DNA template strand
27
Rate of elongation
The rate of elongation is about 500 nucleotides per second in bacteria and 50 per second in human cells
28
Where DNA begins elongation?
a new DNA strand can elongate only in the 5' to 3' direction
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leading strand
where the DNA polymerase synthesizes a leading strand continuously, moving toward the replication fork
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lagging strand
The opposite strand of the leading strand which is replicated
31
Elongation of the leading strand
synthesized as a series of segments called Okazaki fragments, which are joined together by DNA ligase
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DNA ligase
Joins the 3' end of DNA that replaces primer to rest of leading strand and joins Okazaki fragments of lagging strand
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“DNA replication machine”
The proteins that participate in DNA replication form a large complex probably stationary during the replication process Recent studies support a model in which DNA polymerase molecules “reel in” parental DNA and “extrude” newly made daughter DNA molecules
34
DNA polymerases second function
proofread newly made DNA, replacing any incorrect nucleotides
35
Proofreading and Repairing DNA
In mismatch repair of DNA, repair enzymes correct errors in base pairing DNA can be damaged by chemicals, radioactive emissions, X-rays, UV light, and certain molecules (in cigarette smoke for example) In nucleotide excision repair, a nuclease cuts out and replaces damaged stretches of DNA
36
Replicating the Ends of DNA Molecules
The usual replication machinery provides no way to complete the 5' ends, so repeated rounds of replication produce shorter DNA molecules
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telomeres
Eukaryotic chromosomal DNA molecules have at their ends nucleotide sequences Telomeres do not prevent the shortening of DNA molecules, but they do postpone the erosion of genes near the ends of DNA molecules
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telomerase
catalyzes the lengthening of telomeres in germ cells If chromosomes of germ cells became shorter in every cell cycle, essential genes would eventually be missing from the gametes they produce
39
Telomere potential focus
The shortening of telomeres might protect cells from cancerous growth by limiting the number of cell divisions
40
Proteins are the links between what?
genotype and phenotype
41
Gene expression
process by which DNA directs protein synthesis, includes two stages: transcription and translation
42
Archibald Garrod
1902: Suggested that genes dictate phenotypes through enzymes that catalyze specific chemical reactions He thought symptoms of an inherited disease reflect an inability to synthesize a certain enzyme
43
George Beadle and Edward Tatum
exposed bread mold to X-rays, creating mutants that were unable to survive on minimal media one gene–one enzyme/protein/polypeptide hypothesis
44
Adrian Srb and Norman Horowitz
Identified three classes of arginine-deficient mutants Each lacked a different enzyme necessary for synthesizing arginine
45
Point of RNA
RNA is the bridge between genes and protein synthesis
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Transcription
the synthesis of RNA using information in DNA
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Translation
the synthesis of a polypeptide, using information in the mRNA
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Ribosomes
the sites of translation
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Transcription and translation in prokaryotes.
translation of mRNA can begin before transcription has finished
50
Transcription and translation in eukaryotes.
the nuclear envelope separates transcription from translation Eukaryotic RNA transcripts are modified through RNA processing to yield the finished mRNA
51
primary transcript
the initial RNA transcript from any gene prior to processing The central dogma is the concept that cells are governed by a cellular chain of command: DNA → RNA → protein
52
The Genetic Code
20 amino acids, but there are only four nucleotide bases in DNA
53
triplet code
a series of nonoverlapping, three-nucleotide words These words are then translated into a chain of amino acids, forming a polypeptide
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the template strand
One of the two DNA strands provides a template for ordering the sequence of complementary nucleotides in an RNA transcript. The template strand is always the same strand for a given gene However, further along the chromosome, the opposite strand may be the template strand for a different gene
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codons reading order
the mRNA base triplets are read in the 5′ → 3′ direction
56
coding strand
the non-template strand because the nucleotides of this strand are identical to the codons, except that T is present in the DNA in place of U in the RNA
57
64 codons
deciphered by the mid-1960s 61 code for amino acids; 3 triplets are “stop” signals to end translation Codons must be read in the correct reading frame (correct groupings) in order
58
Evolution of the Genetic Code
The genetic code is nearly universal, shared by the simplest bacteria and the most complex animals Genes can be transcribed and translated after being transplanted from one species to another
59
the first stage of gene expression
Transcription
60
RNA synthesis is catalyzed by what?
RNA polymerase
61
RNA polymerase
pries the DNA strands apart and joins together the RNA nucleotides does not need primer
62
promoter
The DNA sequence where RNA polymerase attaches
63
terminator
In bacteria, the sequence signaling the end of transcription
64
transcription unit
The stretch of DNA that is transcribed
65
The three stages of transcription:
Initiation Elongation Termination
66
Initiation
Promoters signal the transcription start point and usually extend several dozen nucleotide pairs upstream of the start point
67
Transcription factors
help guide the binding of RNA polymerase and the initiation of transcription
68
transcription initiation complex
The completed assembly of transcription factors and RNA polymerase II bound to a promoter
69
TATA box
promotor crucial in forming the initiation complex in eukaryotes
70
Elongation
As RNA polymerase moves along the DNA, it untwists the double helix, 10–20 nucleotides at a time Nucleotides are added to the 3′ end of the growing RNA molecule Transcription progresses at a rate of 40 nucleotides per second in eukaryotes A gene can be transcribed simultaneously by several RNA polymerases
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Termination in bacteria
the polymerase stops transcription at the end of the terminator and the mRNA can be translated without further modification
72
Termination in eukaryotes
RNA polymerase II transcribes the polyadenylation signal sequence; the RNA transcript is released 10–35 nucleotides past this polyadenylation sequence
73
After transcription in eukaryotes
Enzymes in the eukaryotic nucleus modify pre-mRNA (RNA processing) before the genetic messages are dispatched to the cytoplasm
74
RNA processing
both ends of the primary transcript are altered Also, in most cases, certain interior sections of the molecule are cut out and the remaining parts spliced together
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Each end of a pre-mRNA molecule is modified in a particular way
The 5′ end receives a modified nucleotide 5′ cap The 3′ end gets a poly-A tail
76
Purpose of pre-mRNA molecules caps
They seem to facilitate the export of mRNA to the cytoplasm They protect mRNA from hydrolytic enzymes They help ribosomes attach to the 5′ end
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RNA splicing
Removing eukaryotic genes and their RNA transcripts that are long noncoding stretches of nucleotides that lie between coding regions
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introns
The noncoding segments in a gene are called intervening sequences
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exons
coding sections that are eventually expressed, usually translated into amino acid sequences
80
The removal of introns is accomplished by what?
Spliceosomes that consist of a variety of proteins and several small RNAs that recognize the splice sites The RNAs of the spliceosome also catalyze the splicing reaction
81
Ribozymes
catalytic RNA molecules that function as enzymes and can splice RNA
82
Three properties of RNA that enable Ribozymes to function as an enzyme
It can form a three-dimensional structure because of its ability to base-pair with itself Some bases in RNA contain functional groups that may participate in catalysis RNA may hydrogen-bond with other nucleic acid molecules
83
alternative RNA splicing
Some genes can encode more than one kind of polypeptide, depending on which segments are treated as exons during splicing
84
domains
Proteins often have a modular architecture consisting of discrete regions different exons code for the different domains in a protein
85
Exon shuffling
may result in the evolution of new proteins by mixing and matching exons between different genes
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A cell translates an mRNA message into protein with the help of what?
transfer RNA (tRNA) tRNAs transfer amino acids to the growing polypeptide in a ribosome
87
tRNA specificity
enables translation of a given mRNA codon into a certain amino acid
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tRNA 2-D structure
Each carries a specific amino acid on one end Each has an anticodon on the other end; the anticodon base-pairs with a complementary codon on mRNA consists of a single RNA strand that is only about 80 nucleotides long
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tRNA 3-D structure
twists and folds into a three-dimensional molecule tRNA is roughly L-shaped with the 5′ and 3′ ends both located near one end of the structure The protruding 3′ end acts as an attachment site for an amino acid
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Accurate translation requires two instances of molecular recognition
First: a correct match between a tRNA and an amino acid, done by the enzyme aminoacyl-tRNA synthetase Second: a correct match between the tRNA anticodon and an mRNA codon
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wobble
Flexible pairing at the third base of a codon allows some tRNAs to bind to more than one codon
92
ribosomal RNAs (rRNAs)
two ribosomal subunits (large and small) are made of proteins
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ribosome has three binding sites for tRNA
P site A site E site
94
P site
holds the tRNA that carries the growing polypeptide chain
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A site
holds the tRNA that carries the next amino acid to be added to the chain
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E site
the exit site, where discharged tRNAs leave the ribosome
97
The three stages of translation:
Initiation Elongation Termination
98
Translation Initiation
When the small ribosomal subunit binds with mRNA and a special initiator tRNA The initiator tRNA carries the amino acid methionine Then the small subunit moves along the mRNA until it reaches the start codon (AUG) Proteins called initiation factors bring in the large subunit that completes the translation initiation complex
99
Translation Elongation
amino acids are added one by one to the C-terminus of the growing chain Each addition involves proteins called elongation factors Translation proceeds along the mRNA in a 5′ → 3′ direction The ribosome and mRNA move relative to each other, codon by codon
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Translation Termination
Elongation continues until a stop codon in the mRNA reaches the A site The A site accepts a protein called a release factor The release factor causes the addition of a water molecule instead of an amino acid This reaction releases the polypeptide, and the translation assembly comes apart
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Translation Elongation 3 Steps
codon recognition, peptide bond formation, and translocation Energy expenditure occurs in the first and third steps Empty tRNAs released from the E site return to the cytoplasm, where they will be reloaded with the appropriate amino acid
102
Often translation is not sufficient to make a functional protein so what happens?
Polypeptide chains are modified after translation or targeted to specific sites in the cell
103
Post-Translational Modifications
a polypeptide chain begins to coil and fold spontaneously into a specific shape: a three-dimensional molecule with secondary and tertiary structure
104
Two populations of ribosomes are evident in cells
Free ribosomes mostly synthesize proteins that function in the cytosol Bound ribosomes make proteins of the endomembrane system and proteins that are secreted from the cell Ribosomes are identical and can switch from free to bound
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Polypeptide synthesis always begins where?
in the cytosol
106
Synthesis finishes in the cytosol unless what?
unless the polypeptide signals the ribosome to attach to the ER
107
signal peptide
Polypeptides destined for the ER or for secretion are marked by this. It is a sequence of about 20 amino acids at or near the leading end of the polypeptide
108
signal-recognition particle (SRP)
binds to the signal peptide The SRP escorts the ribosome to a receptor protein built into the ER membrane The signal peptide is removed by an enzyme
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polyribosome (or polysome)
Multiple ribosomes can translate a single mRNA simultaneously enable a cell to make many copies of a polypeptide very quickly
110
coupling transcription and translation
bacterial cell streamlined process newly made protein can quickly diffuse to its site of function
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Mutations
changes in the genetic information of a cell
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Point mutations
changes in just one nucleotide pair of a gene
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change of a single nucleotide a DNA template strand
can lead to the production of an abnormal protein
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Point mutations within a gene can be divided into two general categories:
Single nucleotide-pair substitutions Nucleotide-pair insertions or deletions
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nucleotide-pair substitution
replaces one nucleotide and its partner with another pair of nucleotides
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Three types of nucleotide-pair substitution
Silent mutations Missense mutations Nonsense mutations
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Silent mutations
have no effect on the amino acid produced by a codon because of redundancy in the genetic code
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Missense mutations
still code for an amino acid, but not the correct amino acid
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Nonsense mutations
Nonsense mutations change an amino acid codon into a stop codon; most lead to a nonfunctional protein
120
Insertions and deletions
additions or losses of nucleotide pairs in a gene These mutations have a disastrous effect on the resulting protein more often than substitutions do
121
frameshift mutation
may alter the reading frame which could affect how the gene is expressed
122
Spontaneous mutations
can occur during errors in DNA replication or recombination
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Mutagens
physical or chemical agents that can cause mutations Chemical mutagens fall into a variety of categories Most carcinogens (cancer-causing chemicals) are mutagens, and most mutagens are carcinogenic
124
CRISPR-Cas9
In bacteria, the protein Cas9 acts together with a guide RNA to help defend bacteria from viral infection Cas9 protein will cut any sequence to which it is targeted Scientists can introduce a Cas9–guide RNA complex into a cell they wish to alter The guide RNA is engineered to target a gene Cas9 cuts both strands of the targeted gene The broken ends trigger a DNA repair system The repair enzymes remove or add some random nucleotides while joining the broken ends This is a way for researchers to “knock out” (disable) a given gene, to study what the gene does in an organism They can introduce a template with a normal (functional) copy of the gene to be corrected In this way, the CRISPR-Cas9 system edits the defective gene and corrects it
125
gene editing
altering genes in a specific way