New: DNA Repair and Recombination Flashcards

(55 cards)

1
Q

holoenzme responsible for the majority of DA synthesis in E.coli

A

DNA pol 3

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2
Q

highly processive polymerase that once it begins catalysis it rarely releases the DNA substrate (due to beta subunit grabbing on)

A

DNA polymerase 3

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3
Q

Okazaki fragments are joined by

A

DNA polymerase 1 and DNA ligase

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4
Q

Okazaki fragments are joined to produce a continuos strand of DNA in these 3 steps:

A
  1. removal of the RNA primer: the 5’ –> 3’ exonuclease activity of DNA pol 1
  2. Synthesis of replacement DNA - polymerase activity of DNA pol 1 synthesizes DNA in place of RNA
  3. sealing of adjacent DNA fragments - DNA ligase
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5
Q

Problem with joining of Okazaki fragments by DNA pol 1 and DNA ligase

A

after Okazaki fragment synthesis is complete, have a gap between end of Okazaki fragment and RNA primer (need to replace RNA primer)

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6
Q

nick translation

A

When DNA pol 1 extends the Okazaki fragment while its 5’–>3’ exonuclease activity removes the RNA primer

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7
Q

DNA ligase binds to the ____ when repairing gaps in DNA

A

nick

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8
Q

DNA ligase then catalyzes the formation of a _______ _______ between 3’ hydroxyl and 5’ phosphate of adjacent Okazaki fragments - then it dissociated from DNA

A

phosphodiester linkage

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9
Q

why cant DNA pol fill in the gap?

A

no free 3’ end

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10
Q

describe eukaryotic chromosomes

A

large linear, double stranded DNA molecules

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11
Q

replication of eukaryotic chromosomes is in what direction

A

bidirectional

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12
Q

compared to E.coli, eukaryotic replication has _____ sets of initiation of DNA synthesis

A

multiple

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13
Q

unique structures at the ends of linear chromosomes (the free end of linear DNA)

A

telomeres

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14
Q

what 2 problems do telomeres have

A
  1. they are susceptible to damage by nucleases

2. due to the nature of DNA synthesis, one strand will shorten upon each round of DNA Synthesis

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15
Q

telomeres have the job of

A

protecting the end from degradation by forming a loop from the guanine rich single stranded DNA - protects end of chromosome from nuclease

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16
Q

this enzyme can reverse transcribe DNA from RNA template; has DNA activity but is dependent on RNA

A

telomerase

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17
Q

telomerase unusual hairpin structure forms new primer to make

A

double stranded DNA

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18
Q

_____ of hairpin yields lengthened telomere

A

cleavage

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19
Q

why is telomerase called a reverse transcriptase when it is adding deoxynucleotides?

A

b/c it is a RNA-dependent DNA polymerase; it has its own RNA template complementary to the telomeric repeat sequence so, it REVERSE transcribes DNA from the RNA template

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20
Q

short telomeres cause

A

premature aging; bone marrow diseases; secondary hit + telomeres cause idiopathic pulmonary fibrosis

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21
Q

DNA pol 3 holoenzyme also

A

fixes mistakes

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22
Q

possesses 3’ –> 5’ exonuclease activity - “proofreading”

A

DNA polymerase 3 holoenzyme

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23
Q

pol 3 can catalyze both chain

A

elongation and degradation

24
Q

exonuclease activity removes mispaired nucleotide before

A

polymerization continues

25
*most uncorrected replication errors are subsequently corrected by
the DNA repair enzymes
26
____ is the only cellular macromolecule that can be repaired
DNA
27
specific _____ ____ scan DNA to detect any alterations - recognize mismatched bases, modified nucleotides
repair enzymes
28
repair that does not require breaking the phosphodiester backbone of DNA
direct repair
29
mechanisms that do involve breaking the DNA backbone to repair
mismatch; base-excision; and nucleotide-excision
30
repair of thymine dimers is done by
DNA photolyase - photoreactivation
31
double-helical DNA is very sensitive to damage by
UV light; dimerization of adjacent pyrimidines in a DNA strand is common
32
repair after photodimerization is _____ repair
direct
33
mismatch-repair system corrects errors that
were not corrected by proofreading that cannot be directly repaired
34
in Ecoli, MutS recongnizes the error, MutL reruits MutH to
cleave the DNA and the exonuclease activity of MutH excises the bases MISMATCH-REPAIR
35
parent strand may be marked by methylation or adenines so that repair machinery can
recognize the correct base
36
_______ synthesizes new strand in mismatch repair and ____ ligates the pieces together
DNA pol 3; DNA ligase
37
nucleotide deamination
*hydrolytic deamination* of C to U or G to A; DNA glycosylases hydrolyze base-sugar N glycosidic bonds; deaminated bases are then removed and replaced
38
AlkA glycosylase does what?
hydrolyzes the glycosidic bond leaving an AP site | base -excision repair
39
AP endonuclease detects AP site and
nicks the sugar-phosphate backbone (base excision repair)
40
deoxyribose phosphodiesterase excises the
deoxyribose phosphate (base-excision repair)
41
DNA pol 1 fills gap and DNA ligase
seals the nick
42
what happens when excision repair does not function?
extreme sensitivity to the sun, greater risk of skin cancer, cancer growth, xeroderma pigmentosum
43
carcinogens are detected using bacteria via what test
ames test
44
simple, sensitive means of determining if a chemical is mutagenic
Ames test
45
3 steps of the Ames test
1. Salmonella bacteria that require histidine because of a mutation in its biosynthetic pathway are treated with the chemicals 2. salmonella are plated on a plate lacking histidine 3. salmonella growth suggest that the chemical caused a mutation which restored histidine synthesis
46
exchange or transfer of pieces of DNA from on chromosome to another or within a chromosome
recombination
47
occurs between pieces of DNA tat have closely related sequences (exchange between paired chromosomes during meiosis)
homologous recombination
48
non-homologous recombination occurs between
unrelated sequences
49
site specific recombination
recombination at a specific location
50
why is recombination needed?
mutation gives new genetic variation; recombination created different combinations of mutations within a genome.
51
recombination also plays an important role in the
repair of DNA
52
how can recombination be used in repair
severe lesions in DNA can be repaired by strand exchange from intact daughter chromosome to defective daughter
53
RAD51
key protein in double strand breaks repaired by recombination
54
know steps of double strand breaks repaired by recombination!
1. break recognized, 5' end digested, single-strand regions are bound by RAD51 2. strand inversion occurs-single strand form damaged DNA replaces a strand in undamaged DNA. This 3 stranded structure is called a DISPLACEMENT LOOP 3. DNA synthesis occurs, using the undamaed DNA as a template 4. a second strand invasion occurs to complete the repair, forming a HOLLIDAY JUNCTION 5 cleavage and ligation yield two intact helices
55
what happens when ds break repair doesn't function?
human BRACA1 and BRACA2 - human breast cancer genes BRC repeats of BRACA2 interact directly with Rad51 BRCA2 may serve to deliver Rad51 to the site of DNA damage conserved C-terminus appears to bind ssDNA and dsDNA