NUCLEAR INSTABILITY Flashcards

(19 cards)

1
Q

what are the four reasons nucleis will be unstable

A
  • too many protons
  • too many neutrons
  • too many nucleons
  • too much energy
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2
Q

what emmision do neutron rich nuclei under go

A

beta minus emission
n > p

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3
Q

what emissions do proton rich nuclei undergo

A

beta plus and electron capture
p > n

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4
Q

what emissions do nuclei with too many nucleons undergo

A

alpha decay

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5
Q

what is the imbalance of stability of a nucleus

A
  • nucleus is bound together by SNF
  • more protons causes more electrostatic repulsion
  • more neutrons are needed to balance this
  • neutrons dont repel, they add to SNF
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6
Q

what is meant by a metastable nucleus

A
  • nucleus that exists in a particularly stable excited state
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7
Q

on an N - Z graph which direction is arrow of beta minus

A

south - east

N - 1
Z + 1

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8
Q

on an N - Z graph what direction is beta plus and electron capture

A

north - west

N+1
Z-1

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9
Q

on an N - Z graph what direction is alpha decay

A

south - west

N - 2
Z - 2

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10
Q

for a beta minus energy diagram how can we determine
1. max KE
2. number of lambdas possible
3. longest lambda

A
  1. Eoriginal - Elargest energy gap
  2. count the possible outcomes
  3. shortest energy gap
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11
Q

in closest approach how do we calculate the radius

A

Ek = Electric potential energy

r = Qq / 4pieoEk

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12
Q

what are advantages of closest approach

A
  1. gives a good estimate to upper limit of radius
  2. alpha particles are only scatted by protons
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13
Q

what are disadvantages of closest approach

A
  1. will always be an overestimate, measures seperation not radius
  2. alpha particles contain hadrons which are affected by SNF
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14
Q

what is electron scattering

A
  • use the wavelength of an electron to determine the radius of a nucleus by measuring the first minimum intensity angle

sin theta = 1.22 lambda / d

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15
Q

advantages of electron scattering

A
  1. electrons are leptons not affected by SNF
  2. much more accurate than closest approach
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16
Q

disadvantages of electron scattering

A
  1. electrons must be accelerated to high speeds, because significant diffraction occurs when lambda is gap size
  2. electrons can be scattered by neutrons difficult to determine intensity
17
Q

whats the nuclear radius equation

18
Q

how can we plot the radius equation

A

ln R = ln Ro + 1/3lnA

19
Q

how can we derive nuclear density

A

v = 4/3pir^3 ( assuming spherical nucleus )

v = 4/3pi (RoA^1/3 ) ^3 = 4/3piRo^3A

p = m / v so m = pv

Au / 4/3piRo^3A = 3u / 4piRo^3