Option Module - Turning Points in Physics (Paper 3) Flashcards
3.12.1 - The discovery of the electron.
3.12.1.1 - Cathode Rays
What is an electrode?
A conductor, through which electricity passes.
What is a cathode?
Negatively
charged electrode.
What is an anode?
Positively
charged electrode.
What are discharge tubes?
Glass chambers with:
- low pressure gas.
- An anode and cathode at opposite ends of the tube.
- High p.d. (voltage) supply.
Are cathode rays made from positive or negatively charged particles?
Negative.
Explain how the discharge tube works.
- electric field between electrodes.
- electric field ionises gas particles.
- Atoms separated to electrons and positive ions.
- Electrons attracted to anode, Positive ions attracted to cathode.
- Beam of electrons emitted from cathode (attracted to anode).
In the discharge tube, why do we have a low pressure gas in the chamber?
Allows charged particles to travel more freely.
Why does the gas glow in discharge tubes?
- electrons and ions travel in opposite directions.
- low pressure = space for particles to gain large amounts of KE.
- collision occurs and they recombine in excited state.
- electrons in atoms de-excite and emit visible light photons.
3.12.1.2 - Thermionic emission of electrons
How can formation of a cathode ray be made easier?
By heating the cathode (thermionic emission).
Why does thermionic emission work?
- Electrons in heated cathode have more KE.
- This is enough energy to leave cathode surface & move to anode.
What are cathode ray tubes designed to do?
Fire the emitted electrons from cathode to anode target.
How do we get a tight beam of electrons (cathode ray)?
electrons are emitted towards the anode.
What equation can we use to calculate the speed of the electrons in the cathode ray?
The equation is derived and explained in notes.
eV = 1/2 x m(e) x v^2.
m(e) = mass of electron.
v = speed of electron.
e = charge of electron.
V = potential difference in the discharge tube.
3.12.1.3 Specific charge of the electron (A-level only)
What are the two different methods in determining the specific charge of an electron?
- Fine beam tube.
- Thomson’s crossed fields.
How is a fine beam tube used to determine the specific charge of an electron?
- electrons accelerated using electron gun.
- magnetic force on electron acts perpendicular to motion = centripetal force.
- electrons move through fine beam tube, become excited, then de-excite.
- Visible light photons are released making path visible, and radius measurable.
Using the fine beam tube experiment to determine specific charge of an electron, what is the equation to calculate the electron specific charge?
e/m(e) = 2V / B^2 r^2.
e/m(e) = specific charge.
B = magnetic flux density (in T).
r = radius of path of electron motion.
V = p.d. applied.
How is the Thomson’s crossed fields method used to determine the specific charge of an electron?
- electrons accelerated using electron gun.
- electrons enter perpendicular to both B field and E field.
- electrons deflection occurs.
- Strength of E and B fields adjusted until electron beam passes undeflected.
In the Thomson crossed fields experiment, what is the equation used to determine the specific charge of an electron?
In notes.
Why was Thomson’s determination of specific charge significant?
He showed that specific charge was constant.
Compare the specific charge of an electron to that of a hydrogen ion?
specific charge of electron is approx 1800 times larger than a proton (hydrogen ion).
3.12.1.4 Principle of Millikan’s determination of the electronic charge, e (A-level only)
What was Millikan’s oil drop experiment used to determine?
The value of the fundamental or elementary charge, e.
What was the method for Millikan’s Oil drop experiment?
- Atomised oil drops sprayed into chamber.
- Drops are ionised by X-rays.
- Drops pass into region between two metal plates (viewed by microscope).
Why are oil drops used instead of water droplets?
Oil drops don’t evaporate as quickly.
So mass of drops = constant.
What equation represents the condition necessary for stationary oil drops?
QV/d = mg.
How do we get terminal velocity for the falling motion of oil droplets?
Turning off the electric field produced.
What are the conditions or assumptions required for the Stokes’ law equation?
Object is small.
Object is spherical (with radius r)
Low speed
What is the equation for viscous drag force, F?
This is given on data sheet.
What do we equate the equation for the viscous drag force, F, equal to?
mg, when at terminal velocity.
When can we use the density?
If the mass and radius are unknown, for the sphere.
What was the significance of Millikan’s results?
This includes the quantisation of charge.
Each charge droplet had a charge with a value of an integer multiple of 1.6 x 10^-19 C.
This meant charge was quantised and that this was the magnitude of the charge of an electron.