Orbitals and Mechanism Flashcards

(37 cards)

1
Q

What type of solvents stabilise ions?

A

Polar solvents stabilise cations and anions
Polar protic solvents stabilise anions via hydrogen bonding

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2
Q

What type of compound is the best for solvation and why?

A

Where the charge is spread out, e.g lots of EWGs
This is because solvation is entropically unfavourable, so spreading out the charges makes it easier for the substance to solvated and stabilised

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3
Q

What is PkAH and how can it be useful?

A

pkA of a conjugate acid, used to assess base strength
e.g pkAH= NH4+ ⇌ NH3 + H+
High pkAH suggests a weaker conjugate acid, so a stronger base

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4
Q

Why is 2-methyl-N,N-dimethylphenyl amine more basic than expected?

A

Steric clash between the methyl groups of the amines and the methyl on the carbon adjacent
Therefore, sp3 nitrogen to reduce steric hindrance, prevents delocalisation of the lone pair, increasing electron density on the nitrogen and so increases basicity

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5
Q

What does the Gibbs/reaction coordinate graph look like for Sn2? Describe all details

A

Reactants at higher energy than the products
Curve starting from reactants to products with peak halfway
Peak=Transition state
From A to B = ∆ G, driving force
From A to TS= ∆G‡, free energy of activation

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6
Q

How does the transition state link to rate of reaction?

A

Molecules must have sufficient energy to overcome the free energy of activation
Lower energy transition states will have a greater rate of reaction

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7
Q

What does the Gibbs/reaction coordinate graph look like for Sn1? Describe all details

A

Reactants at higher energy than the products
Intermediate at higher energy than reactants and products
Curve starting from reactants to intermediate with peak halfway
Curve starting from intermediate to products with peak halfway
Peak=Transition state
From A to B = ∆ G, driving force
From A to TS1= ∆G‡1
From intermediate to TS2= ∆G‡2

Whichever ∆G‡ is larger is the rate determining step

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8
Q

What is Hammond’s postulate? Why is it useful?

A

For consecutive species, closer in energy implies close in structure
This means for most reactions, the transition states are closer in energy to the intermediate than reactants or products, so closer in structure to these
Factors which stabilise the intermediate will tend to stabilise the TS, increasing the rate of reaction

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9
Q

What does the Gibbs/reaction coordinate graph look like for a divergent reaction?

A

From the reactants, two paths, each with a different product
Two products- B higher in energy than C
2 curves starting from reactants to B or C, the peak for C is larger
so ∆G‡AB<∆G‡AC
but also ∆G AB < ∆G AC

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10
Q

How can the products of a divergent be controlled?

A

Kinetic Control- typically using lower temperatures to give the higher energy (less stable) , but lower activation energy product which is formed faster, irreversible
Thermodynamic Control- typically using higher temperatures to give the lower energy (more stable), but higher activation energy product which is formed more slowly, reversible

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11
Q

What are nucleophiles and give examples of each type?

A

Electron rich, electron pair donors
Either as lone pairs or filled orbitals

LP= NH3, OH-
π bond= Alkenes
σ bond= BH4-

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12
Q

What are electrophiles and give examples of each type?

A

Electron deficient, electron pair acceptors, containing unoccupied orbitals

P0= BH3, CH3+
π= carbonyls
σ
=Br2, alkyl halides

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13
Q

Why types of HOMO/LUMO interaction is best and why? What is the order of energy for each type of orbital?

A

Where there is a small energy gap between the HOMO of the nucleophile and LUMO of the electrophile
Leads to the greatest stabilisation

σ>non-bonding lp>π >σ

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14
Q

What are the best types of electrophiles/nucleophiles?
Why do you need to take care with formal charges?

A

Low energy LUMO of electrophiles, and high energy HOMO of nucleophile to minimise the energy gap

Formal charges do not align with empty orbtials
e.g H3O+, but nucleophiles cannot attack the oxygen as already has a full octet, instead a base

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15
Q

How is the π nucleophile similar to the empty p orbital electrophile?

A

Both can have attacks from above or below as planar

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16
Q

How does the nucleophile attack a σ* and π*?

A

σ*= attacks from behind the leaving group so their is maximum HOMO/LUMO overlap, leading to inversion of stereochemistry

π*= attacks at the burgi-dunitz angle of 105-107 degrees between trajectory and C=O. Also to maximise HOMO-LUMO overlap whilst minimising steric repulsion

17
Q

How are carbocations and carbanions stabilised?

A

Carbocations- more alkyl groups and electron donating groups , inductive effects
Carbanions- less alkyl groups and more EWGs via inductive

Both are stabilised by conjugation

18
Q

What is the shape of carbon-based radicals? How can these radicals be stabilised?

A

CH3· = trigonal planar like the carbocation, but CF3·= pyramidal, so depends
Stabilised by alkyls like cation, and can also exhibit resonance

19
Q

What are carbenes?

A

R2C:
Either exist as a diradical where 1 unpaired electron is in an Sp2 and the other p = triplet
Or as a lone pair in an Sp2 with an empty p orbital= singlet

20
Q

How does a polar solvent affect a compound?

A

Increases the stability of ions of the compound
e.g stabilises a charged conjugate base
promotes ionisation of an alkyl halide

20
Q

What is the mechanism for Sn1? And the rate equation?

A
  • leaving group leaves, forming a carbocation
  • nucleophile attacks the carbocation, from above or below, racemic mixture

rate= k [alkyl halide]
not dependent on the nucleophile

20
Q

What conditions support Sn1 and why?

A

Polar, protic solvent to stabilise the carbocation by solvation
Tertiary alkyls so the carbocation can be stabilised via hyperconjugation
Must be planar to enable hyperconjugation, so no bridgeheads
Generally weak nucleophiles

21
Q

What is the mechanism for Sn2 and the rate equation?

A
  • nucleophilic attack behind the leaving group to maximise overlap with σ*
  • TS with a trigonal bipyramidal structure
    -LG leaves, inversion of stereochemistry

rate= k [alkyl halide] [nucleophile]

22
Q

What does the TS for Sn2 look like?

A

Trigonal bipyramidal with R groups planar around the centre
Partial (dashed bonds) between nu and LG
Partial negatives on LG and nu, partial positive on carbon
Double dagger sign around square brackets

23
What is the mechanism and rate equation for E1?
- leaving group leaves, forming a carbocation - base removes an adjacent proton, forming a double bond rate = k [alkyl halide]
24
What conditions support E1? What is the selectivity for E1 and why?
When no good nucleophile is present Normally a strong acid, conjugate base not very nucleophilic Tertiary alkyl halides to stabilise hyperconjugation Regioselective- generally forms alkenes with more alkyl groups attached as more stable TS and alkene Stereoselective- normally trans to reduce steric hindrance in TS and alkene
25
What is the mechanism and rate equation for E2?
- Alkyl halide in antiperiplanar or synperiplanar - Antiperiplanar preferable to enable maximum overlap between C-X σ* and C-Hσ - base removes proton, double bond forms, C-X bond broken rate= k [alkyl halide] [nucleophile] same type of wedge bond in the antiperiplanar position will be on the same side of the alkene
26
What conditions support E2?
A strong bulky base such as t-butyloxide
27
What is the E1cB mechanism and when does it normally take place?
-Takes place when carbanion can be stabilised as next to a stabilising group, normally a carbonyl -So when protons are additionally acidic adjacent - base removes the proton, forming a carbanion, usually resonance delocalised to form an enolate - elimination to reform carbonyl/form alkene double bond and break C-X bond
28
What is the mechanism for electrophilic addition of HX to an alkene? What is the selectivity?
-Alkene double bond to H, break C-X -X- attacks the carbocation Markovnikov's rule- major product will form via the more stable carbocation intermediate So positive charge on the carbon attacked to more alkyl groups, which is where the halide will attack
29
What is the mechanism for electrophilic addition of Br2 to an alkene? What is the selectivity?
- alkene double bond to a bromine, whilst the bromine lone pair attack the carbon, and the Br-Br bond breaks - bromonium intermediate where the bonds have the same type of wedge - Br- attacks the carbon, breaking one of the C-Br bonds in Sn2, so inversion If a trans alkene, ends up facing the same side, Cis on the opposite side, but draw the steroechem out
30
What is the mechanism for electrophilic aromatic substitution?
Needs a lewis acid most of the time Double bond attacks Br, Br-Br bond to a lewis acid Carbocation intermediate, Base removes a proton, reforming the pi system
31
What is a pericyclic reaction? How would you draw a Diels Alders reaction and what factors increase rate?
Pericyclic- all bond breaking/making in the same step Alkene + conjugated diene, from diene ene from ene to diene, and diene to central Forms a ring and alkene Nucleophile=diene, sped up by EDG Electrophile= ene, sped up by EWG
32
What is cycloproponation?
Reaction between an alkene and carbene Lone pair to C of C=C, and C=C to carbene Forms a ring, 3 membered
33
What is the reaction conditions and mechanism for addition of HBr to an alkene so an opposite addition of Br can occur?
(CH3)2C=CH2 + HBr + Ph(CO2)2 cat, UV Ph(CO2)2 → 2PhCO2· (Of O-O) PhCO2· + HBr → PhCOOH + Br· Br· + (CH3)2C=CH2 → (CH3)2C·-CH2Br (CH3)2C·-CH2Br + HBr → (CH3)2CHCH2Br + Br· (as radical stabilised by more alkyls, and bromine added first)
34
What is oxidation/reduction? Give an agent for each
Oxidation= loss of electrons, loss of hydrogen, gain of oxygen e.g PCC Reduction= aon of electrons, gain of hydrogen, loss of oxygen e.g LiAlH4
35
What is the oxidation level of a carbon? Why might this be useful?
The number of bonds carbon has to heteroatoms e.g Lv2= HCHO, CH2Br2 For synthesis, imagine all bonds to heteroatoms= C-O, eliminate water Results in either alkane, alcohol, ketone, or carboxylic acid level Helps with synthesis