organic II Flashcards

(34 cards)

1
Q

What is the Sn2 mechanism?
Draw example mechanism.

A

Nucleophillic substitution with two species involved in the rate determining step and 2nd order.
Includes a transition state.
Page. 174

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2
Q

What is the Sn1 mechanism?
Draw example mechansim.

A

Nucleophillic substitution with one species involved in the rate determining step and first order.
Includes a carbocation with a planar shape.
Equal chance of nucleophile attacking from left or right so 2 products formed: a racemic mixture.
Page. 175

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3
Q

How to form an achohol from an aldehyde or ketone?

A

Reduction of aldehyde/ ketone using LiAlH4 (lithium aluminium hydride) and dry ether solvent.

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4
Q

How can you identify an aldehyde? (4 ways)

A
  • Acidified potassium dichromate (VI) - orange sol to green sol.
  • Fehling’s solution - deep blue sol to red precip
  • Benedict’s solution - deep blue sol to red precip
  • Tollen’s reagent - colourless sol to silver mirror
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5
Q

How can you identify a ketone?

A
  • React with iodine - yellow precip
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6
Q

Reaction of carbonyl compound with KCN and mechanism.

A
  • Nucleophillic addition
  • Produces Hydroxynitrile racemic mixture
    page. 180
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7
Q

How to test for carbonyl compound?

A
  • Brady’s reagent (2,4-DNPH) - forms orange precip
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8
Q

How to form a carboxylic acid by hydrolysis?

A
  • Hydrolysis of nitrile - heat under reflux and dilute acid/ aqueous alkali
  • equation on page. 184
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9
Q

How can you reduce a carboxylic acid?

A
  • LiAlH4 reducing agent and solvent of dry ether
  • Produces a primary alcohol and water
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10
Q

How can you neutralise a carboxylic acid and what is the product?

A
  • mixing with aqueous alkali
  • makes sodium X-oate
  • equation on page. 185
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11
Q

Halogenation of a carboxylic acid.

A
  • PCl5 (phosphorus (V) chloride)
  • Forms an acyl chloride
  • equation on page. 185
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12
Q

Esterification of a carboxylic acid.

A
  • Carboxylic acid is mixed with an alcohol and a small amount of acid catalyst (usually conc. sulfuric acid)
  • Forms an ester and water
  • equation on page. 185
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13
Q

What happens when you react an acyl chloride with water?

A
  • Forms a carboxylic acid and hydrogen chloride gas (misty fumes)
  • equation on page. 186
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14
Q

What happens when you react an acyl chloride with an alcohol?

A
  • Forms an ester and hydrogen chloride gas (misty fumes)
  • equation on page. 186
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15
Q

What happens when you react an acyl chloride with conc. ammonia?

A
  • Forms an amide and hydrogen chloride gas (misty fumes)
  • HCl then reacts with NH3 (as acid and base) to form ammonium chloride
  • equation on page. 187
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16
Q

What happens when you react an acyl chloride with an amine?

A
  • Forms an N-substituted amide and hydrogen chloride gas (misty fumes)
17
Q

Hydrogenation on benzene.

A
  • Mix benzene with hydrogen, heating under pressure and nickel catalyst to form cyclohexane
  • equation on page. 196
18
Q

Combustion of benzene.

A
  • Smoky flame
  • equation on page. 196
19
Q

Bromination of benzene.
Mechanism.

A
  • Bromine and benzene are heated under reflux in the presence of a catalyst: halogen carrier (usually aluminium chloride or bromide) but iron filings in this reaction
  • Forms bromobenzene and HBr
  • equation on page. 196
20
Q

Nitration of benzene
Mechanism.

A
  • Warming benzene with conc. nitric acid and sulfuric acid
  • Forms nitrobenzene and water
  • equation on page. 196
21
Q

Friedel crafts alkylation of benzene.
Mechanism.

A
  • Halogenoalkane with halogen carrier (AlCl3)
  • Forms alkylbenzene and hydrogen halide
  • equation on page. 197
22
Q

Friedel crafts acylation of benzene.
Mechanism.

A
  • Acyl chloride and halogen carrier (AlCl3)
  • Forms ketone and hydrogen halide
  • equation on page. 197
23
Q

Bromination of phenol

A
  • Room temp without catalyst with bromine water
  • bromine water is decolourised to form a white precipitate
  • equation on page. 200
24
Q

How to form an amine from a halogenoalkane?

A
  • heating halogenoalkane with ammonia (nucleophile) under pressure and in a sealed container or mixed with conc. aqueous ammonia
  • forms alkyl amine and hydrogen chloride
  • alkyl amine acts as a nucleophile reacting with halogenoalkane to form a secondary amine and HCl
  • ammonia used in excess to avoid unwanted side-reactions, some of excess ammonia reacts with HCl to form NH4Cl
  • equation on page. 202
25
Reduction of a nitrile.
- Reduction of nitrile using LiAlH4 in dry ether - Forms amine - equation on page. 203
26
Reduction of nitrobenzene.
- Tin as reducing agent mixed with conc. HCl acid and heat under reflux - forms phenylamine and water - equation on page. 203
27
Reaction of amine and ethanoyl chloride and what type of reaction?
- addition-elimination reaction - forms N-...yl ethanamide and HCl
28
How to make a grignard reagent.
- Heat under reflux the chosen halogenoalkane and magnesium in dry ether solvent - organometallic compount containing magnesium e.g. R - Br + Mg ---> R-Mg-Br
29
How to make a carboxylic acid using a grignard reagent.
- RMgBr reacts with CO2 1. form grignard reagent 2. react with CO2 3. hydrolysis using dilute acid - equation on page. 216
30
How to make a primary alcohol using a grignard reagent.
- RMgBr reacts with methanal 1. form grignaard reagent 2. react with methanal 3. hydrolysis using dilute acid - equation on page. 216
31
How to make a secondary alcohol using a grignard reagent.
- RMgBr reacts with aldehyde 1. form grignaard reagent 2. react with aldehyde 3. hydrolysis using dilute acid - equation on page. 217
32
How to make a tertiary alcohol using a grignard reagent.
- RMgBr reacts with ketone 1. form grignaard reagent 2. react with ketone 3. hydrolysis using dilute acid - equation on page. 217
33
3 differences between making esters with ethanoyl chloride and ethanoic acid.
-The reaction is irreversible compared to reversible -Hydrogen chloride is the by-product rather than water -The reaction is very fast/occurs at room temperature so an acid catalyst is not needed
34
Phenylamine can be prepared from nitrobenzene. Butylamine can be prepared from butanenitrile. Compare and contrast these two preparations of amines.
-Both are reduction reactions -Reagents for preparation of phenylamine are tin and conc. hydrochloric acid -Reagents for preparation of butylamine are either Hydrogen gas and nickel catalyst or lithium tetrahydridoaluminate(III) and dry ether