paper 1 stuff i don't know Flashcards

(50 cards)

1
Q

percentage yield equation

A

actual yield in mol/ theoretical yield in mol X 100

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2
Q

atom economy equation

A

sum of Mr of desired products/ sum of Mr of all products X 100

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3
Q

reasons for high atom economy

A
  • produce a large proportion of desired products

- to make reaction more sustainable

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4
Q

hydrogen is an important raw material and is produced from reaction of carbon with steam. work out its equation and atom economy

A

C + H2O -> 2H2 + CO2

(2X 2)/ ((2X2)+44) X 100= 8.3%

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5
Q

dative covalent/ coordinate bond

A

covalent bond in which the shared pair of electrons has been supplied by one of the bond atoms only

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6
Q

tetrahedral bond angle

A

109.5

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7
Q

pyramidal bond angle

A

107

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8
Q

non- linear bond angle

A

104.5

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9
Q

linear bond angle

A

180

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10
Q

trigonal planar bond angle

A

120

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11
Q

octahedral bond angle

A

90

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12
Q

square planar bond angle

A

90

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13
Q

charge on ammonia ligand

A

neutral

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14
Q

charge on water ligand

A

neutral

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15
Q

charge on chloride ion ligand

A

-1

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16
Q

charge on hydroxide ion ligand

A

-1

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17
Q

what is cis also called?

A

z

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18
Q

what is trans also called?

A

E

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19
Q

2 identical groups are opposite to each other

A

trans

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20
Q

2 identical groups are adjacent to each other

A

cis

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21
Q

where does cis- trans isomerism occur in complex ions?

A
  • square planar

- octahedral

22
Q

where does optical isomerism occur in complex ions

23
Q

what is the colour of the solution of [CuCl4]2-

24
Q

Cu2+ with HCl

A

[Cu(H2O)6]2+(aq) +4Cl-(aq) [CuCl4]2-(aq) +6H2O(l)

25
what colour is I2?
brown
26
what colour is Cu(s)?
brown solid
27
sulfate test
add Ba2+ ions Ba2+(aq) + SO42-(aq) -> BaSO4(s) white precipitate
28
carbonate test
add HNO3(aq) effervescence as CO2 CO3^2-(aq) + 2H+(aq) -> CO2(g) + H2O(l)
29
ammonium ion test
add NaOH red pH indicator-> blue pH indicator NH4+(aq) + OH-(aq) -> NH3(g) + H2O(l)
30
trend in alkalinity of group 2 hydroxides down the group
- solubility increases - pH increases - alkalinity increases
31
trend in reactivity of group 2 elements down the group
- nuclear attraction decreases - atomic radius increases - shielding increases - reactivity increases as react by losing electrons
32
trend in reactivity of group 7 elements down the group
- nuclear attraction decreases - atomic radius increases - shielding increases - reactivity decreases - as halogens react by gaining electrons
33
3 halogen- halide displacement reactions
- Cl2(aq) + 2Br-(aq) -> 2Cl-(aq) + Br2(aq) - Cl2(aq) + 2I-(aq) -> 2Cl-(aq) + I2(aq) - Br2(aq) + 2I-(aq) -> 2Br-(aq) + I2(aq)
34
trend in boiling point of the halogens
- more electrons - stronger London forces - more energy required to break the intermolecular forces - boiling point increases
35
trend in first ionisation energy down a group
- atomic radius increases - shielding increases - nuclear attraction decreases - first ionisation energy decreases
36
trend in first ionisation energy across a period
- nuclear charge increases - same shell: similar shielding - nuclear attraction increases - atomic radius decreases - first ionisation energy increases
37
reaction between Cu2+(aq) ions and I-(aq)
2Cu2+(aq) + 4I-(aq) -> 2CuI(aq) + I2(s)
38
how do you reduce Cu2+ to Cu+?
excess iodide ions
39
how do you oxidise Cu+ to Cu2+?
hot dilute sulfuric acid
40
how do you oxidise Cr3+ to CrO42-
hot alkaline hydrogen peroxide
41
how to oxidise Fe2+ to Fe3+?
acidified manganate(VII) ions
42
how do you reduce Fe3+ to Fe2+?
excess iodide ions
43
what colour is MnO4-?
purple
44
oxidation of Fe2+ using MnO4-(aq) equation
MnO4-(aq) + 8H+(aq) + 5Fe2+(aq) -> Mn2+(aq) + 5Fe3+(aq) + 4H2O(l)
45
reduction of Fe3+ using I-(aq) equation
2Fe3+(aq) + 2I-(aq) -> 2Fe2+(aq) + I2(aq)
46
how to reduce Cr2O72- to Cr3+?
Zn solid
47
reduction of CrO72- using Zn equation
Cr2O72-(aq) + 14H+(aq) + 3Zn(s) -> 2Cr3+(aq) + 7H2O(l) + 3Zn3+(aq)
48
how to reduce Cr3+ to Cr2+?
excess Zn(s)
49
reduction of Cr3+ using excess Zn
Zn(s) + 2Cr3+(aq) -> Zn2+(aq) + 2Cr2+(aq)
50
oxidation of Cr3+ using H2O2 equation
3H2O2(aq) + 2Cr3+(aq) + 10OH-(aq) -> 2CrO42-(aq) + 8H2O(l)