Pharmacology MCQs - ANZCA Flashcards
(235 cards)
GP01 [Mar96] A drug is given at a dose of 50 mg/kg to a 70 kg man. The plasma concentration after giving it is 10 mg/ml. The elimination half-life is 8 hours. Clearance would be: A. 1.3 l/h B. 3 l/hr C. 0.03 l/hr D. 125 l/hr
Vd = dose / concentraion = 3500 mg/10 mg/ml = 350 ml Clearance = 0.693 x Vd / t1/2 = 0.693 x 350 ml / 8 hrs = 30 ml / hr = 0.03 L / hr Therefore answer C is correct —Comment— OK, the maths is fine, but is it possible for a drug to have a VD of 350ml?? Is it possible for any drug to have a VD less than plasma volume?? Help please!
GP02 [Mar96] A drug is given orally and 95% absorbed. Only 25% reaches the general circulation due to hepatic first pass metabolism. If hepatic blood flow is 1500 mls/min, the hepatic clearance is: A. 400 mls/min B. ? C. 1100 mls/min D. ? E. 1425 mls/min
Hepatic clearance = HER x HBF = ( (0.95 – 0.25) / 0.95 ) x 1,500 ml / min = 1,105 mls/min Extraction ratio= conc of inflow-conc outflow/conc of inflow
GP03 [Jul97] Histamine release (no other details) GP03b [Feb12] Histamine when given IV causes: A. Bronchoconstriction B. ?
Bronchoconstriction through activation of H1 receptors - true. Histamine actives H1 receptors to constrict bronchial smooth muscles, whereas stimulation of H2 receptors relaxes bronchial smooth muscles. In normal patients the bronchoconstrictor action of histamine is negligible. Conversely, patients with obstructive lung disease, such as asthma or bronchitis, are more likely to develop increases in airway resistance in response to histamine. References Stoelting 4th ed p431.
GP04 [Jul97] Rectal administration of drugs: A. Gives predictable blood levels B. From lower 1/3rd avoids first pass & upper 2/3rds doesn’t C. None undergoes first pass metabolism D. All of it undergoes first pass metabolism E. ?
Jul97 version: Best answer is B A false - “unpredicatable responses… follow rectal administration of drugs” (Stoelting 3rd Ed. p.9) B best answer - “Drugs administered into the proximal rectum are … transported via the portal venous system to the liver (first pass hepatic effect)… drugs absorbed from a low rectal administration site reach the systemic circulation without first passing through the liver.” (Stoelting 3rd Ed. p.9) C false - beware absolutes like all or none D false - beware absolutes. Also regarding pulmonary first pass below: I’m pretty sure they’re talking about hepatic first pass metabolism and not looking for esoteria like that. This question is basically about effect of rectal administration on first pass metabolism.
GP04b Mar09 Rectal administration of drugs: A. Provides reliable absorption B. Administration in the lower third (below the dentate line) completely avoids hepatic first pass C. Is rapid due to the anastomoses between the superior and inferior haemorrhoid plexuses D. ? E. None of the above
his question is basically about effect of rectal administration on first pass metabolism. Katzung “Basic & Clinical Pharmacology” 7th ed (1998) on p42: The hepatic first-pass effect can be avoided to a great extent by use of sub-lingual tablets and transdermal preparations, and to a lesser extent by use of rectal suppositories. . Sub-lingual absorption provisdes direct access to systemic - not portal - veins. The trandermal route offers the same advantage. . Drugs absorbed from suppositories in the lower rectum enter vessels that drain into the inferior vena cava, thus bypassing the liver. . However, suppositories tend to move upwards in the rectum into a region where veins that lead to the liver, such as the superior hemorrhoidal vein, predominate. . In addition, there are extensive anastomoses between the superior and middle hemorrhoidal veins; thus, only about 50% of a rectal dose can be assumed to bypass the liver. Stoelting (2nd ed p7) also comments that a result of this unpredictable variability in percent of drug absorbed in the lower rectum versus the upper rectum that this explains “‘the unpredictable responses that follow rectal administration of drugs” Related Stuff The liver is NOT the the only organ invloved in a first pass effect. Drugs administered systemically have to pass through the lungs before reaching peripheral capillary beds, and the lung can take up (and even metabolise) some drugs. An example is fentanyl (& also pethidine) where the lungs act as a large inactive storage site. An estimated 75% of the initial fentanyl dose undergoes first-pass pulmonary uptake. Stoelting ( 2nd ed 1991 p85) references the following source: Roerig et al. First pass uptake of fentanyl, meperidine, and morphine in the human lung. Anesthesiology. 1987 Oct;67(4):466-72 . “ . . . . The total uptake (mean +/- SE) during the first pass through the human lung for fentanyl and meperidine was 75.2 +/- 3.2% and 64.7 +/- 7.8% of the injected dose, respectively. The pulmonary uptake of morphine was very small, with 96.5 +/- 7.1% of the injected dose recovered in arterial blood after the first pass through the lung. . . . “ [1] Aug 15- C
GP04c 15B Aug15 version with different options Regarding rectal administration of drugs A. Rectal indomethacin does not cause gastric symptoms B. Rectal administration is predictable and effective. C. Superior haemorrhoidal vein absorption results in hepatic first pass metabolism D. paracetamol cannot be given rectally
his question is basically about effect of rectal administration on first pass metabolism. Katzung “Basic & Clinical Pharmacology” 7th ed (1998) on p42: The hepatic first-pass effect can be avoided to a great extent by use of sub-lingual tablets and transdermal preparations, and to a lesser extent by use of rectal suppositories. . Sub-lingual absorption provisdes direct access to systemic - not portal - veins. The trandermal route offers the same advantage. . Drugs absorbed from suppositories in the lower rectum enter vessels that drain into the inferior vena cava, thus bypassing the liver. . However, suppositories tend to move upwards in the rectum into a region where veins that lead to the liver, such as the superior hemorrhoidal vein, predominate. . In addition, there are extensive anastomoses between the superior and middle hemorrhoidal veins; thus, only about 50% of a rectal dose can be assumed to bypass the liver. Stoelting (2nd ed p7) also comments that a result of this unpredictable variability in percent of drug absorbed in the lower rectum versus the upper rectum that this explains “‘the unpredictable responses that follow rectal administration of drugs” Related Stuff The liver is NOT the the only organ invloved in a first pass effect. Drugs administered systemically have to pass through the lungs before reaching peripheral capillary beds, and the lung can take up (and even metabolise) some drugs. An example is fentanyl (& also pethidine) where the lungs act as a large inactive storage site. An estimated 75% of the initial fentanyl dose undergoes first-pass pulmonary uptake. Stoelting ( 2nd ed 1991 p85) references the following source: Roerig et al. First pass uptake of fentanyl, meperidine, and morphine in the human lung. Anesthesiology. 1987 Oct;67(4):466-72 . “ . . . . The total uptake (mean +/- SE) during the first pass through the human lung for fentanyl and meperidine was 75.2 +/- 3.2% and 64.7 +/- 7.8% of the injected dose, respectively. The pulmonary uptake of morphine was very small, with 96.5 +/- 7.1% of the injected dose recovered in arterial blood after the first pass through the lung. . . . “ [1] Aug 15- C
GP05 [Mar99] [Jul00] [Apr01] [Jul04] [Feb07] LD50 is: A. Median lethal dose B. Determined in phase I clinical trial C. Determined from log-dose response curve D: Dose causing death in 50% of animals within ?1/?4 hours E. Half the mean lethal dose. F. Best expressed as ratio of lethal dose in 50% of animals to effective dose in 50%
Answer is A I agree A is most correct. But C appears to also be correct? Katzung (7th ed 1998 p29): “The quantal dose-effect curve is often characterised by stating the median effective dose (ED50), the dose at which 50% of individuals exhibit the specified quantal effect. (Note that the abbreviation ED50 has a different meaning in this context from its meaning in relation to graded dose-effect curves.) Similarly the dose required to produce a particular toxic effect in 50% of animals is called the median toxic dose (TD50). If the toxic effect is death of an animal, a median lethal dose (LD50) may be experimentally defined. “ Also: “Quantal dose-effect curves may also be used to generate information regarding the margin of safety to be expected from a particular drug used to produce a specified effect. One measure, which relates the dose of a drug required to produce a desired effect to that which produces an undesired effect, is the therapeutic index. In animal studies, the therapeutic index is usually defined as the ratio of the TD50 to the ED50 for some therapeutrically relevant effect” A few important points to bear in mind: Some candidates start talking about LD50 as though this was something that could be determined for humans! If you are asked what method you would use to determine the LD50 of a new drug in humans be very wary. You should always very quickly remark that such is NEVER done in humans for obvious ethical reasons. The therapeutic index can be not very useful in some cases, for example if there is significant overlap between the effective and toxic curves. OECD countries in 2000 agreed to minimise the use of LD50 testing to minimise the number of animals killed. (The examiners are unlikely to know this - useful info for a viva) As regards the phase 1 clinical trials option: “Phase 1 includes the initial introduction of an investigational new drug into humans. These studies are closely monitored and may be conducted in patients, but are usually conducted in healthy volunteer subjects. . These studies are designed to determine the metabolic and pharmacologic actions of the drug in humans, the side effects associated with increasing doses, and, if possible, to gain early evidence on effectiveness. During Phase 1, sufficient information about the drug’s pharmacokinetics and pharmacological effects should be obtained to permit the design of well-controlled, scientifically valid, Phase 2 studies. “ [1] SO: You NEVER determine a LD50 during phase 1 trials because these trials are done in HUMANS.
GP06 - [Mar99] [Feb00] [Jul02] [Mar03] -Aug15 Which ONE of the following crosses the blood-brain barrier? A. GABA B. Propranolol C. Suxamethonium D. Edrophonium E. Dopamine
Answer is B Propranolol: Yes. From Stoelting 2nd ed p306: “Beta-blockers may cross the blood-brain barrier to produce side effects. For example, fatigue and lethargy are commonly associated with chronic propranolol therapy.” Suxamethonium-No: is charged (and rapidly metabolised). Does not cross BBB but can have indirect effects on brain function (eg apnoea->cerebral hypoxia). Edrophonium-No: It is a quaternary amine so is charged and cannot cross the blood-brain barrier. (In contrast, physostigmine is a tertiary amine anticholinesterase which can cross the BBB). Dopamine-No: From [1]: “Of importance for PD, dopamine, a neurotransmitter that is depleted in PD, does not’ pass the BBB but L-dopa does. In the brain L-dopa is converted to dopamine. This is important for treatment of PD symptoms with levadopa alone or in combination with carbidopa.” Carbidopa is a dopa decarboxylase inhibitor which inhibits the peripheral conversion of L-Dopa to dopamine (but not centrally as it does not cross the BBB). GABA -No. It is a non-essential amino acid and as such can be synthesised in the brain. It has difficulty crossing the BBB. References Bioavailability of Drugs to Brain and Blood brain barrier
GP07 [Jul98] [Jul99] [Apr01] With regard to drug-receptor binding: A. A competitive antagonist has no intrinsic activity B. A partial agonist has less receptor affinity than a full agonist C. KD is maximal intrinsic efficacy
GP07 A - correct B - false C - false - “intrinsic affinity” is a confusing term for “efficacy”. KD relates to “affinity” / “potency” KD is the equilibrium dissociation constant, with units mmol/L. KA is the equilibrium affinity constant and is the reciprocal of KD, with units L/mmol. From Peck and Hill: The potency is determined by a drug’s KD; the lower the KD, the higher the potency. For many drugs, the ED50 (dose producing 50% of maximum response) corresponds to the KD. KD = [ligand] x [receptor] / [ligand-receptor complex] = k2/k1 = 1/KA Katzung 6e p16 says “…partial agonists competitively inhibit the responses produced by full agonists” - but doesn’t say “always” and I agree to be wary of questions with absolutes. A partial agonist at high concentrations may antagonise a full agonist, but at low concentrations they will exert an additive effect together.
GP07b [Feb00] [Feb04] [Jul04] A partial agonist: A. Always antagonises a full agonist B: Can never be used to antagonise a full agonist C: Has a dose response curve similar to that of a full agonist in the presence of a non-competitive antagonist. D. ?
GP07b A - false - beware always B - false - beware never C - correct KD is the equilibrium dissociation constant, with units mmol/L. KA is the equilibrium affinity constant and is the reciprocal of KD, with units L/mmol. From Peck and Hill: The potency is determined by a drug’s KD; the lower the KD, the higher the potency. For many drugs, the ED50 (dose producing 50% of maximum response) corresponds to the KD. KD = [ligand] x [receptor] / [ligand-receptor complex] = k2/k1 = 1/KA Katzung 6e p16 says “…partial agonists competitively inhibit the responses produced by full agonists” - but doesn’t say “always” and I agree to be wary of questions with absolutes. A partial agonist at high concentrations may antagonise a full agonist, but at low concentrations they will exert an additive effect together.
GP08 [Jul98] [Jul01] [Mar02] Placental transfer of drugs: A. Increases in late pregnancy B. Increases late because of decreased albumin C. Do not cross if MW > 600 daltons D. Lipid soluble drugs diffuse through placenta depending on concentration gradient E. Increased diffusion if greater plasma protein binding in fetus
A - no idea B - no idea C - no idea but may not be true (think facilitated transport for larger proteins) D - correct: From first principles (Fick’s law of diffusion, net flux across a semi permeable membrane is proportional to “D”, the diffusion coefficient, the surface area and the concentration gradient; and inversely proportional to the thickness. “D” itself is proportional to the solubility of the substance to the membrane and inversely proportional to the square root of the molecular weight of the substance.) Also Peck, Hill and Williams state that being “phospholipid in nature, the placental membrane is more readily crossed by lipid-soluble than polar molecules” (p.19) E incorrect - “plasma protein binding influences the rate and degree of diffusion of LAs across the placenta. Bupivacaine, which is highly protein bound (approx 95%) has an umbilical vein-maternal arterial concentration ratio of about 0.32 compared with a ratio of 0.73 for lignocaine (approx 70% protein bound) and a ratio of 0.85 for prilocaine (approx 55% protein bound)” (Stoelting 3rd ed. p.163) Whilst I hate to disagree, Peck and Williams p19 states “high protein binding in the foetus increases drug transfer across the placenta since foetal free drug levels are low.” hence I would say E is correct. M2C: I agree E is correct. C is also correct - I think it is Stoelting who says anything greater than around 500da crosses less easily. Whilst the objections to D being correct and the support of E are noted, the numbers quoted in Stoelting would appear to support that E is incorrect. i.e. at least in the case of bupivicaine vs lignocaine, only around 30% is transferred compared with around 75% for lignocaine which has the lower protein binding. Everyone however is free to make their own decision and we won’t really know who is right and who is wrong come exam time. Only the examiners (or the computer marking it) will know. :-) I think the quote from stoelting regarding option E is referring to maternal protein binding, while the question is referring to fetal protein binding. I agree that high protein binding in the mother will decrease diffusion across the placenta, but for 2 drugs with identical maternal protein binding, the one with higher fetal protein binding will have greater placental transfer (assuming pKa, lipid solubility the same for each) I agree - also, just saw in UptoDate that if drugs are unionised/lipid-soluble, they freely cross the placenta if MW 1000 g/mol) do not cross the placental membrane[11]” D and E likely true (as per above)
GP09 [Jul98] [Jul99] Regarding pharmacokinetics: A. ? B. Half-life is inversely proportional to clearance C. ? D. Half-life is proportional to steady-state E. B & D
B definitely correct as clearance = 0.693 x Vd/ half life Discussion about D and E below just a thought, IR (infusion rate) = Cl * Css Cl = ke * Vd Ke = ln2 / T1/2 = 0.693 / T1/2 Hence, rearranging IR/Css = 0.693Vd / T1/2 Css = (IR * T1/2) / 0.693Vd so that steady state concentration is proportional to its half life at a given infusion rate. perhaps E ??? any thoughts?? D would be correct if the word “concentration” was put at the end of the option, to make it less ambiguous. In that case, E would be correct. I’m not entirely sure but i think the algebraic reasoning above may be incorrect…if you expand the terms IR & T1/2 out, everything cancels and you end up with Css=Css.
GP10 [Jul99] [Jul04] An ether bond: A. Formed from condensation of 2 alcohols B. Hydroxyl group on middle bond C. ?
A - maybe right. If you combine two hydroxyls to form an ether, then you produce water (see the Wiki entry below), but is it the same as condensation? B - definitely WRONG Ether - “Any of a class of organic compounds in which two hydrocarbon groups are linked by an oxygen atom.” (“ether.” The American Heritage® Dictionary of the English Language, Fourth Edition. Houghton Mifflin Company, 2004. Answers.com 17 Feb. 2007.) From Wikipedia Ethers can be prepared in the laboratory in several different ways. One of the 3 ways is Dehydration of alcohols: R-OH + R-OH → R-O-R + H2O Is this the same as condensation? Yes! Condensation reactions also include formation of ester bonds from an alcohol and acid, and also forming peptide bonds from two amino acids. I think dehydration is the specific subset of condensation when water is produced. There are other condensation reactions that result in other, non-water, small molecules being formed…can’t think of any examples at present
GP11 [Feb00] [Mar03] The NMDA receptor A. Ketamine is an agonist B. Requires glycine as a modulating protein to have its effect C. Mg+2 blocks the receptor D. Is not permeable to Calcium
C is the best answer Ketamine is an ANTAGONIST Glycine is an AMINO ACID (not a protein) - several persons submitting this question noted the “protein” wording) Mg+2 normally blocks the ion channel in the molecule When open, it is permeable to Na+, K+ and Ca+2 Regarding the NMDA Receptor: “The NMDA receptor gates a cation channel that is permeable to Na+, K+ and Ca+2 and is gated by Mg+2 in a voltage-dependent fashion. Agonists (glutamate, NMDA) and the coagonist glycine, required for full activation, bind to the extracellular domain” (from Hemmings & Hopkins “Foundations of Anesthesia” p250) Opening of the channel in the NMDA receptor requires ALL of the following: partial depolarisation of the cell membrane (to relieve the Mg+2 obstruction of the channel) binding of BOTH glutamate AND glycine (on extracellular side)
GP12 [Feb00] [Jul02] Activated charcoal: A. Should be given with sorbitol B. Is not effective against theophylline C. Should be given with ipecac D. Should be given in a drug:charcoal ratio of 1:10 E. ?
Answer is D What is Activated charcoal? Chemically it is just pure carbon, but the way it is produced gives it a HUGE surface area. A tennis court has a SA of about 260m2 so just one gram has an average of more than TWICE that. Ref [1]. “Activated charcoal is used in water filters, medicines that selectively remove toxins, and chemical purification processes. Activated charcoal is carbon that has been treated with oxygen. The treatment results in a highly porous charcoal. These tiny holes give the charcoal a surface area of 300-2,000 m2/g, allowing liquids or gases to pass through the charcoal and interact with the exposed carbon.” (from [2]) Activated charcoal is a fine, black, odorless, and tasteless powder. It is made from wood or other materials that have been exposed to very high temperatures in an airless environment. It is then treated, or activated, to increase its ability to adsorb by reheating with oxidizing gas or other chemicals to break it into a very fine powder. Activated charcoal is pure carbon specially processed to make it highly adsorbent of particles and gases in the body’s digestive system. . Activated charcoal has often been used since ancient times to cure a variety of ailments including poisoning. Its healing effects have been well documented since as early as 1550 B.C. by the Egyptians. However, charcoal was almost forgotten until 15 years ago when it was rediscovered as a wonderful oral agent to treat most overdoses and toxins. (from [3]) ??15 years The sorbitol option Some activated charcoal products contain sorbitol. Sorbitol is a sweetener. It also works as a laxative, for the elimination of the poison from the body. Products that contain sorbitol should be given only under the direct supervision of a doctor because severe diarrhea and vomiting may result. - from Medline plus Regarding Sorbitol, In AMH (July 2008) there are two types of Activated Charcoal mentioned that are thus Available in Australia: “oral liquid, 50 g, in 46% sucrose, 250 mL, Carbosorb X (PL) oral liquid, 50 g, in 40% sorbitol, 250 mL, Carbosorb XS (PL)” But in “practice points” it mentions: “Sorbitol provides no additional benefit to charcoal in most poisonings and may result in diarrhoea and volume depletion.” Regarding 1st dose: “1 g/kg to a maximum of 50–100 g for each dose of activated charcoal.” So you can use it with sorbitol, but it is just one option. The theophylline option Consider this abstract: Effect of the surface area of activated charcoal on theophylline clearance GD Park et al. Journal of Clinical Pharmacology, 1984; 24:289-292 . The effect of the surface area of activated charcoal on theophylline clearance was studied. Eight fasting, healthy men received intravenous infusions of either aminophylline (6 mg/kg, N = 3) or theophylline (5 mg/kg, N = 5) over 1 hour followed by either 5 Gm standard activated charcoal every 2 hours, 20 Gm every 2 hours, or 5 Gm PX-21 activated charcoal (with 3.6 times the surface area) every 2 hours. …..(some content deleted) … . We conclude that the clearance of theophylline is related to the surface area of activated charcoal administered and that PX-21 may be a more potent activated charcoal product for enhancing theophylline removal. and this from a page about treatment of theophylline overdose: Gastrointestinal decontamination . To block absorption, administer oral activated charcoal (1 mg/kg, not to exceed 20 g) every 2 hours until the serum theophylline level has fallen to less than 20-25 mcg/mL. . For vomiting, administer metoclopramide, droperidol, or ondansetron. Avoid ipecac because it does not reduce absorption. Avoid phenothiazine antiemetics (eg, prochlorperazine, perphenazine) because they lower the seizure threshold from [4]. The ipecac option What’s the sense of giving something (charcoal) only to give another drug (ipecac) to vomit it up? However, the two can be used together IF ipecac is given first, then activated charcoal after a period of time: Activated charcoal is available without prescription. However, in case of accidental poisoning or drug overdose an emergency poison control center, hospital emergency room, or doctor’s office should be called for advice. In case that both syrup of ipecac and charcoal are recommended for treatment of the poison, ipecac should be given first. Charcoal should not be given for at least 30 minutes after ipecac or until vomiting from ipecac stops. Activated charcoal is often mixed with a liquid before being swallowed or put into the tube leading to the stomach.” (from [5]. The drug:charcoal ratio option For those (?rare) occasions when the dose of ingested drug/toxin is known, there is a recommendation on a drug:charcoal ratio: Give 10 times as much charcoal BY WEIGHT as drug ingested. Initial dose, 1 g per kg of body weight or 25 to 100 g orally or via gastric tube (as a slurry in water) or if the quantity of toxin ingested is known, 10 times the amount of ingested toxin by weight is given. Repeat-dose, 0.25 to 0.5 g per kg of body weight (15 to 30 g) every 2 to 4 hours is given orally or by gastric tube. Following administration of activated charcoal, it is recommended that a cathartic be administered to enhance removal of the drug-charcoal complex since failure to excrete the drug-charcoal complex promptly may result in enhanced toxicity. When multiple doses of activated charcoal are required, administration of a small dose of cathartic with every second or third charcoal dose is recommended. Do not use cathartic with every activated charcoal dose. Warning 1. It should be used with caution in patients with absence of bowel sounds. 2. It may cause swelling of abdomen or pain and black stools. 3. The effectiveness of oral acetylcysteine and other oral medications may be decreased when used concurrently with activated charcoal. 4. Chocolate syrup or ice cream or sherbet should not be used as vehicles for the administration of activated charcoal since they will decrease the adsorptive capacity of the activated charcoal. from p29 [6] When NOT to use activated charcoal Just in case this is an option in future versions of this question. Activated charcoal is used in the emergency treatment of certain kinds of poisoning. It helps prevent the poison from being absorbed from the stomach into the body. Sometimes, several doses of activated charcoal are needed to treat severe poisoning. Ordinarily, this medicine is not effective and should NOT be used in poisoning if - Corrosive agents such as alkalis (lye) and strong acids, - Alcohols or - Miscellaneous: boric acid, iron, lithium, - Petroleum products (e.g., cleaning fluid, coal oil, fuel oil, gasoline, kerosene, paint thinner), have been swallowed, since it will not prevent these poisons from being absorbed into the body. from [7] Mnemonic: Avoid if CAMP BAIL - where the BAIL coverrs the miscellaneous ones My notes: a. Teik Ok ICU book p.948 says don’t give with sorbitol. Found an A&E book which stated there was no evidence that it does any good. b. G&G 11e p1748 says “serial doses enhance elimination of theophylline” and other sources list theophylline as one of the few intoxications where a.c. is definitely recommended. c. no advantage over charcoal alone and charcoal can adsorb the emetic agent and reduce it’s effect - think this was also from G&G d. this is definitely true as above G&G: 11e p.1748
GP13 [Apr01] [Jul04] Therapeutic index: A. Easy to determine in humans B. ? C. D. E. Derived from LD50/ED50
From Yentis: Therapeutic index is defined experimentally as the ratio of median lethal dose to median effective dose -therefore answer is E THERAPEUTIC INDEX “The ratio of the drug dose which produces an undesired effect to the dose which causes the desired effects is a therapeutic index and indicates the selectivity of the drug and consequently its usability. It should be noted that a single drug can have many therapeutic indices, one for each of its undesirable effects relative to a desired drug action, and one for each of its desired effects if the drug has more than one action. “ An alternative more general definition: “Therapeutic index can be evaluated as the relative position of the dose-efficacy and the dose-side effect curves.” The “position” of each curve is determined from its 50% response position, and the “relative” aspect is determined by taking the ratio of the 2 curve positions - with the undesired effect in the numerator and the desired effect in the denominator. The point of getting this ratio is that it provides some information about the “margin of safety” with use of the druug.
GP14 [Apr01] [Jul04] (A Basic drug with a pKa of 8.7) A. ? B. ? C. Will be predominantly ionised at plasma pH
A basic drug will be predominantly ionised at a pH below its pKa For a drug with a pKa of 8.7 undegoing the reaction: B + H+ BH+: At pH = pKa we can calculate the following: pH = pKa + log([B]/[BH+]) (Henderson-Hasselbalch equation) If pH = pKa then this simplifies to pKa = pKa + log([B]/[BH+]) log([B]/[BH+]) = 0 Thus, taking anti-logs (easy as log 1 = 0): ([B]/[BH+]) = 1 so [B] = [BH+] -> 50% ionised & 50% unionised By doing similar calculations using the Henderson-Hasselbalch equation, the ratio B/BH+ can be determined at any pH value. For example: For pH = pKa + 1 -> 10% ionised & 90% unionised (approx) For pH = pKa -> 50% ionised & 50% unionised For pH = pKa - 1 -> 90% ionised & 10% unionised For pH = pKa - 2 -> 99% ionised & 1% unionised “Bases ionised Below, Acids ionised Above”
GP15 [Apr01] [Jul02] [Mar03] Oxygen toxicity A. Causes convulsions at less than 100 kPa B. Causes lipid peroxidation at less than 100 kPa C. ? D. ? E. ?
A is incorrect. CNS toxicity occurs at > 200 kPa B. correct In general, “hazards” associated with oxygen use include hypoventilation, i.e. in pts with CPOD who are chronic CO2 retainers Absorption Atelectasis ( alveolar collapse)- high oxygen concentrations can cause atelectasis in areas of low ventilation relative to perfusion. VC can be decreased by 500-800ml as a consequence Retinopathy of prematurity ( previously called retrolental fibroplasia) - FIO2 > 0.50 to neonates can encourage “disorganized vascular proliferation and fibrosis”.. which can make the retina opaque, .” as well as retinal detachment” Bronchopulmonary dypasia - in neonates Fire hazard Pulmonary toxicity In the acute situation, use of 100% O2 ( PaO2 > 600mm Hg,) is not associated with toxicity. Dose time toxicity curves state that 100% O2 administered longer than 12 hours are associated with toxic effects, namely tracheobroncial irritation ( manifested as coughing, retrosternal burning, chest tightness, “substernal distress”). The pathophysiology of oxygen toxicity may arise from several mechanisms, such as: inactivation of enzymes, release of inflammatory mediators, action of dioxygen moecule as a free radical, formation of a superoxide free radicals, formation of hydrogen peroxide. Ultimately oxygen derived free radicals act on DNA, lipids ( disrupts alveolar capillary membrane), and sulphydryl contatining proteins. With regards to hyperbaric O2 therapy, the degree of toxicity is related to the pressures used as well as duration of usage. At > 2 atmospheres ( > 200 KPA) the risk of CNS toxicity emerges, i.e. convulsions, muscular twitches, behavior changes. From my reading, B appears to be true, assuming they are referring to “100 kPa” as alveolar PO2. “ Chronic O2 administration of 100% O2 at 1atm results in PO2 of 713 mm Hg/ 95 kPa, which can lead to lipid peroxidation”. References Faunce - ANZ Intensive care & Primary exam, 9th ed. p 60, Lange- Clinical Anaesthesiology 4th ed p. 1028-9
GP16 [Jul01] With regard to log/dose response curves: A. The response is fairly linear over the 20-80% range. B. The Dose is fairly linear over the 20-80% range C. The ED50 and slope are characteristic for each drug D. ? E. ?
Best answer is probably A From Aitkenhead 4th p. 21: “Conventionally, log-dose is plotted against effect, resulting in a sigmoid curve which is approximately linear between 20 and 80% of maximum effect” Could they all be right? C sounds right, as does B (although this does not mention response) or is it not B because it is not really linear if you have to use a logarithmic scale to get that shape graph? I think A is most correct. B seems incorrect - the dose is not linear on a logarithmic scale C could be true also Stoelting page 17 4th Ed cover it faily well with regard to C and seems to indicate this is correct. Slope influenced by number of receptors drug must ocupy to have effect, and ED50 measure of potency which shouldn’t change for each drug. I haven’t found anything regarding the 20-80% thing though
GP18 [Jul01] With regards to diffusion through a membrane: A. Directly proportional to thickness B. Inversely proportional to thickness C. Inversely proportional to Surface area D. Inversely proportional to concentration difference E. ?
Fick’s Law of Diffusion: A - False B - True C - False D - False Law is: . v_gas ~ A.D.(p1-p2) / T where D ~ solubility / sqrt (MW) See: West, p.26
GP19 [Mar02] [Mar03] [Mar08] Which of the following has it’s action related to a ligand gated ion channel? A. Metoclopramide B. Phenylephrine C. Morphine D. Vecuronium E. Salbutamol
Answer D. Vecuronium Lengthy notes Sorry about my lengthy notes here (mainly to convince myself I know it, but also, this is core stuff that didn’t leap out when I first read about these drugs). First part is unreferenced and my interpretation of the action of drugs at the Nicotinc Ach receptor. The second part on opioids is a cut and past from wiki on opioid receptors. Good luck. NMJ nACh Receptor The Nicotinic Ach receptor is a ligand gated ion channel (2 alphas beta gamma and delta or epsilon). To activate the channel two Acetylcholine molecules bind to each of the alpha subunits and open the channel, then dissociate and are quickly metabolised by acetylcholinestarase in the NMJ. Because the enzyme is in the NMJ there is a gradient rapidly for Ach to dissociate from the receptor back into the NMJ. Suxamethonium binds both alphas and activates the channel –> action potential spread –> fasciculation. Sux is not metabolised in the NMJ as the Plasmacholinesterase is in the – yep you guessed – plasma. So there is no rapid gradient to dissociate from the receptor until some sux begins to diffuse out of the NMJ into the plasma then the bound sux can dissociate. So receptors are held open for much longer by sux than Ach. Non-depolarizers all have a molecular structure which includes an-Ach like portion. This binds to a single alpha subunit and the bulky molecule blocks the receptor. As it only binds a single alpha subunit the channel is not opened and no depolarisation occurs. Opioid receptors Opioid receptors: G protein linked with opioids as ligands (but no channel). The endogenous opioids are dynorphins, enkephalins and endorphins. The opioid receptors are ~40% identical to somatostatin receptors (SSTRs). There are three major subtypes of opioid receptors: [1] delta opioid receptor (δ) OP1 δ1, δ2 kappa opioid receptor (κ) OP2 κ1, κ2, κ3 mu opioid receptor (μ) OP3 μ1, μ2 (Sigma receptors (σ) were once considered to be opioid receptors, but are not usually currently classified as such.) The receptors were named using the first letter of the first ligand that was found to bind to them. Morphine was the first chemical shown to bind to mu receptors. The first letter of the drug morphine is `m’. But in biochemistry there is a tendency to use Greek letters so they converted the ‘m’ to μ. Similarly a drug known as ketocyclazocine was first shown to attach itself to kappa receptors.[2] The opioid receptor types are ~70% identical with differences located at N and C termini. The μ receptor (the μ represents morphine) is perhaps the most important. It is thought that the G protein binds to the third intracellular loop of the opioid receptors. Both in mice and humans the genes for the various receptor subtypes are located on different chromosomes. Separate subtypes have been identified in human tissue. Research has so far failed to identify the genetic evidence of the subtypes, and it is thought that they arise from post-translational modification of cloned receptor types.[3] An additional opioid receptor has been identified and cloned based on homology with the cDNA. This receptor is known as the nociceptin receptor or ORL 1 receptor. From Stoelting 4th Ed: pg 89. “All 3 receptor classes couple to G proteins and subsequently inhibit adenylyl cyclase, decrease the conductance at voltage gated calcium channels, or open inward flowing potassium channels.” Suggests that opioid act via ligand gated ion channel and hence C correct. I think you have looked into it a bit too deeply. potassium channels are most likely activated in a similar way to those related to M2 muscarinic receptors in the AV node. ie Beta and delta (rather than usual Alpha subunit) of G protein activated ion channel (ie Still ligand activating G protein which THEN activates ion channel). Prob the same for Calcium channel but not sure. Would have to go for D Vec is a competitive antagonist for ligand gated ion channel. ::Agreed. A G-protein-coupled-receptor is a metabotropic receptor and IS NOT an ionotropic receptor (ligand-gated ion channel). References 1. Corbett AD, Henderson G, McKnight AT, Paterson SJ (2006).75 years of opioid research: the exciting but vain quest for the Holy Grail. Brit. J. Pharmacol.147, S153–S162 2. [1] 3. Fries, DS (2002). Opioid Analgesics. In Williams DA, Lemke TL. Foye’s Principles of Medicinal Chemistry (5 ed.). Philadelphia: Lippincott Williams & Wilkins. ISBN 0-683-30737-1.
GP20 [Jul02] Zero order kinetics means: A. ? B. ? C. Drug is eliminated at a constant rate regardless of dose. D. Elimination half time will vary according to dose. E. ?
Most correct answer is C, but would be better if worded “drug is eliminated at a constant rate regardless of plasma concentration” Zero-order kinetics (also referred to as saturation kinetics): the rate of elimination of a drug from the plasma is constant irrespective of the plasma concentration this differs from the exponential patterns of elimination seen in first-order kinetics A good example of this is ethanol, which is cleared from plasma at approx 4mmol/L/hour regardless of plasma concentration. The underlying reason for this constant rate of elimination is that the rate of oxidation by the enzyme alcohol dehydrogenase reaches a maximum at low ethanol concentrations (due to limited cofactor availability). Consequences of zero-order kinetics: duration of action is strongly dependent on drug dose the relationship between steady-state plasma concentration and dose is unpredictable D is also correct I think; elimination half-life is constant for first order processes, but varies with dose (and is thus a half-time) for zero order processes. in relation to D it is explained n wikipedia [1] t1/2 = initial conc/(2k) where k = r which is the constant rate of elimination. So increasing the dose or initial concentration will proprtionally increase the T1/2. D also seems correct.
GP21 [Feb04] All exist as racemic mixtures except: A. Thiopentone B. Lignocaine C. Bupivacaine D. Isoflurane E. Enflurane
Answer is B. Lignocaine is achiral and therefore does not have enantiomeric forms. A racemic mixture contains equal amounts of two enantiomers (non-superimposable mirror image molecules) of a chiral molecule; polarized light can be pass through a solution of these without being rotated. (Things get more complicated when the molecule has more than one chiral centre.) NB I think sodium thiopentone exists as a mixture of tautomers, which by definition have different connections between the same atoms, and therefore can’t be enantiomers and can’t give rise to a racemic mixture. (Stoelting p.127 implies, and Hemmings/Hopkins p.299 clearly states that thiopental is a racemic mixture - given both are texts I’d be happy to accept that thiopental is a racemic mixture and the answer is “B”). Furthermore, the tautomerism confers asymmetry to the barbituric ring thus making the C2 carbon chiral. NO - the C2 carbon has a double bond in the enol AND keto form. No carbon with a double bond can be chiral (ever, anywhere). If you meant the C5 carbon, it is not chiral either. Why? Because keto-enol (or in the case of thiopentone, thial-thioketone) tautomerism is a rapidly reversible process, in the supposedly asymetric form (thial) the double bond can point toward C4 or C6, those electrons are delocalised between C4 and C6 thus removing any asymmetry. The C5 carbon is never chiral in thiopentone. It only has 1 chiral centre which is the carbon attached to C5 in the longer of the 2 chains on C5. PS I’d disagree with that definition of a racemic mixture being only composed of enantiomers. Mivacurium is a unequal racemic mixture of diastereoisomers (geometric).
GP22 [Feb04] Clearance of a drug with a high hepatic extraction will be: A. Decreased in shock ??? B. Increased in high output states ??? C. ? D. ? E. ?
The clearance of drugs with a high hepatic extraction ratio are highly dependent on the flow through the liver. For example, a drug with a hepatic extraction ratio of 1.0 will have twice the clearance when the hepatic blood flow is doubled. Conversely a drug with a low hepatic extraction ratio will have its clearance minimally affected by doubling the hepatic blood flow. Therefore: A - correct as shock will decrease hepatic blood flow and hence clearance B - correct as increased cardiac output will increase hepatic blood flow and hence clearance Both are true I think. The clearance of drugs with a low extraction ratio (ER) is minimally affected in absolute terms by changes in blood flow (a 50 % increase or decrease of very little is still very little), whereas it will have a much larger (in absolute terms) impact for drugs with a high ER. Clearance = ER x blood flow. I think A is more correct because high output does not always correlate to higher hepatic blood flow whereas in shock, hepatic blood flow will definitely decrease.
