PHEP 2 Flashcards
(28 cards)
Work Equals?
force times distance
What is velocity?
Rate at which a mass travels in a particular direction
When is velocity variable?
Mass passes over unequal distance in equal intervals of time
Potential energy is most nearly associated with? A) Strain B) Motion C) Force D) Pull
Force
The accomplishment of a force acting through a distance is associated with? A) Power B) Potenial Energy C) Horse Power D) Work
Work
Energy available for future use is called? A) Kinetic B) Electrical C) Potential D) Inertia
Potential
The term Power means? A) Energy B) Voltage C) Rate at which work is done D) Rate of exchange of momentum
The rate at which work is done
Falling water contains? A) Potential energy B) Mechanical energy C) Kinetic Energy D) Electrical energy
Kinetic energy
Accelerations of a freely falling body due to the force of gravity is? A) 32 ft/sec B) 32 ft/sec each second C) 16 ft/sec D) 64 ft/sec
32 ft/sec each second
A foot pound is a unit of? A) force B) power C) work D) momentum
Work (foot lb/sec)
In 5 seconds of fall, a falling body will fall a total of? A) 225 ft B) 532 ft C) 380 ft D) 400 ft
400 ft Distance=(acceleration (g) x time2)/2 D=GT2/2 D=32x52/2
The theoretical Velocity of a falling body is equal to? A) √h/2g B) √2h/g C) (2)(g) D) √2gh
√2GH
If the velocity of a stream of water is doubled, the weight of a material it can suspend and carry is increased by? A) 2 B) 4 C) 8 D) 16
16
A pump raises 200 ft3 of water to a height of 50ft. How much was done to raise this water? A) 249.6 ft lbs B) 4,330 ft lbs C) 10,000 ft lbs D) 624,000 ft lbs
624,000 ft/lbs =200ft3 x 62.4lbs(weight of water) x 50ft
A pump raises 200 ft3 of water to a height of 50ft. How much was done to raise this water. (above question) If the water in the above question is raised 5 minutes, at what rate in horse power is the work done? A) 1.75 B) 2.75 C) 3.75 D) 4.75
3.75 P=W/T = Fd/t. 1HP = 550 ftlbs/sec. (624000/300)/550
Niagra Falls is 160ft high. At the top of the falls each cubic foot of water weight 62.4 pounds has how many foot pounds of potential energy? A) 62.4 B) 160 C) 9,984 D) more than 10,000
9,984 =160ft x 62.4lbs (weight of water)
To transform the kinetic energy contained in falling water to mechanical energy at the blades of a hydrolic turbine involves the application of? A) the first law of motion B) the second law of motion C) the third law of motion D) All three laws
All three laws
Increasing the velocity of falling water will? A) decreases the available kinetic energy B) increases the available kinetic energy C) have no effect on the available kinetic energy D) increases both kinetic and potential energy
increase the available kinetic energy
Disregarding all other losses rate of flow of a liquid in the product of? A) Area x velocity B) diameter x velocity C) velocity x time D) area x velocity x distance
Area x Velocity
If the diameter of a pipe is decreased uniformly at its termination and with no change in pressure head the exit velocity of the liquid? A) is increased B) is decreased C) is not changed D) has no effect on flow characteristics
Is Increased pg 16
With continuous steady flow the total head at any point in a stream is equal to the total head at any downstream point plus the? A) turbulance losses B) frictional losses C) loss of head between the 2 points D) velocity
Loss of head between the 2 points (pg 18)
The sudden transformation within a pipe of the kinetic energy of the moving mass of water into pressure energy is most usually associated with? A) flow measurement B) effective head measurement C) water hammer D) converting kinetic energy to mechanical energy
Water hammer
The damaging effects of water hammer can be controlled by? A) proper valve control B) venting C) priming D) effective application of all three of the above
Effective application of all 3 above
Compute the approximate friction loss in feet of head for a Section of pipe having a diameter of 2’ 1000’ long roughness coefficient of 0.02 and A mean velocity of 10’ per second. A) 5 B) 10 C) 15 D) 20
15 hf = f x L/D x V2/2g *f=coefficient *g=32.2 (constant of gravity) hf = 0.02 x (1000/2) x (100/2(32.2)) hf = 0.02 x 500 x 1.5527