PHEP 2 Flashcards

(28 cards)

1
Q

Work Equals?

A

force times distance

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2
Q

What is velocity?

A

Rate at which a mass travels in a particular direction

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3
Q

When is velocity variable?

A

Mass passes over unequal distance in equal intervals of time

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4
Q

Potential energy is most nearly associated with? A) Strain B) Motion C) Force D) Pull

A

Force

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5
Q

The accomplishment of a force acting through a distance is associated with? A) Power B) Potenial Energy C) Horse Power D) Work

A

Work

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6
Q

Energy available for future use is called? A) Kinetic B) Electrical C) Potential D) Inertia

A

Potential

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7
Q

The term Power means? A) Energy B) Voltage C) Rate at which work is done D) Rate of exchange of momentum

A

The rate at which work is done

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8
Q

Falling water contains? A) Potential energy B) Mechanical energy C) Kinetic Energy D) Electrical energy

A

Kinetic energy

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9
Q

Accelerations of a freely falling body due to the force of gravity is? A) 32 ft/sec B) 32 ft/sec each second C) 16 ft/sec D) 64 ft/sec

A

32 ft/sec each second

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10
Q

A foot pound is a unit of? A) force B) power C) work D) momentum

A

Work (foot lb/sec)

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11
Q

In 5 seconds of fall, a falling body will fall a total of? A) 225 ft B) 532 ft C) 380 ft D) 400 ft

A

400 ft Distance=(acceleration (g) x time2)/2 D=GT2/2 D=32x52/2

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12
Q

The theoretical Velocity of a falling body is equal to? A) √h/2g B) √2h/g C) (2)(g) D) √2gh

A

√2GH

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13
Q

If the velocity of a stream of water is doubled, the weight of a material it can suspend and carry is increased by? A) 2 B) 4 C) 8 D) 16

A

16

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14
Q

A pump raises 200 ft3 of water to a height of 50ft. How much was done to raise this water? A) 249.6 ft lbs B) 4,330 ft lbs C) 10,000 ft lbs D) 624,000 ft lbs

A

624,000 ft/lbs =200ft3 x 62.4lbs(weight of water) x 50ft

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15
Q

A pump raises 200 ft3 of water to a height of 50ft. How much was done to raise this water. (above question) If the water in the above question is raised 5 minutes, at what rate in horse power is the work done? A) 1.75 B) 2.75 C) 3.75 D) 4.75

A

3.75 P=W/T = Fd/t. 1HP = 550 ftlbs/sec. (624000/300)/550

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16
Q

Niagra Falls is 160ft high. At the top of the falls each cubic foot of water weight 62.4 pounds has how many foot pounds of potential energy? A) 62.4 B) 160 C) 9,984 D) more than 10,000

A

9,984 =160ft x 62.4lbs (weight of water)

17
Q

To transform the kinetic energy contained in falling water to mechanical energy at the blades of a hydrolic turbine involves the application of? A) the first law of motion B) the second law of motion C) the third law of motion D) All three laws

A

All three laws

18
Q

Increasing the velocity of falling water will? A) decreases the available kinetic energy B) increases the available kinetic energy C) have no effect on the available kinetic energy D) increases both kinetic and potential energy

A

increase the available kinetic energy

19
Q

Disregarding all other losses rate of flow of a liquid in the product of? A) Area x velocity B) diameter x velocity C) velocity x time D) area x velocity x distance

A

Area x Velocity

20
Q

If the diameter of a pipe is decreased uniformly at its termination and with no change in pressure head the exit velocity of the liquid? A) is increased B) is decreased C) is not changed D) has no effect on flow characteristics

A

Is Increased pg 16

21
Q

With continuous steady flow the total head at any point in a stream is equal to the total head at any downstream point plus the? A) turbulance losses B) frictional losses C) loss of head between the 2 points D) velocity

A

Loss of head between the 2 points (pg 18)

22
Q

The sudden transformation within a pipe of the kinetic energy of the moving mass of water into pressure energy is most usually associated with? A) flow measurement B) effective head measurement C) water hammer D) converting kinetic energy to mechanical energy

23
Q

The damaging effects of water hammer can be controlled by? A) proper valve control B) venting C) priming D) effective application of all three of the above

A

Effective application of all 3 above

24
Q

Compute the approximate friction loss in feet of head for a Section of pipe having a diameter of 2’ 1000’ long roughness coefficient of 0.02 and A mean velocity of 10’ per second. A) 5 B) 10 C) 15 D) 20

A

15 hf = f x L/D x V2/2g *f=coefficient *g=32.2 (constant of gravity) hf = 0.02 x (1000/2) x (100/2(32.2)) hf = 0.02 x 500 x 1.5527

25
Compute the approximate loss of head in feet due to turbulence for the above pipe assuming a square edge entry? A) .5 B) .75 C) 1 D) more than 1
0.75 he=0.5 x V2/2g he=0.5 x 102/2x32.2 he=0.5 x 100/64.4 he=0.5 x 1.5527 he=0.77639
26
The head causing flows through a pipe is the difference between the total head at the beginning of the pipe and the? A) frictional losses B) turbulance losses C) atmospheric pressure D) total head at the end of the pipe
Total head at the end of the pipe
27
2 reservoirs have surface elevation of 201' and 100' calculate the approximate flow rate in gallons per minute through the inner connecting pipe. Assume a square edge entry, clean, steal pipe, diameter 1.5' length 600' and a coefficient "f" of 0.02? A) less than 20,000 B) between 20,000 and 21,000 C) between 21,000 and 22,000 D) greater than 22,000
Between 20,000 and 21,000
28
When applied it to a moving liquid mass the expression V2/2G refers to? A) velocity head B) pressure head C) static head D) all of the above
The velocity head