physics flashcards 1
(89 cards)
kinematics equations
vf2=vi2+2ax x=vit+½at2 v=vo+at vavg=(vo+v)/2 x=vt=((vo+v)/2)*t
Newton’s Laws
1st: Law of inertia - objects in motion (or at rest) will stay in motion (or at rest) unless acted on by a nonzero net force 2nd: F=ma 3rd: Fa=-Fb Every action has an equal and opposite reaction
Friction equations
force of friction opposes motion kinetic: ff=μkFN static fs<μsFN
Gravitation
two masses will exert an attractive force on one another inversely proportional to the square of the distance b/w them. F=(Gm1m2)/r2
mnemonic for trig values
sin0=√0/2=0 sin30=√1/2=½ sin45=√2/2 sin60=√3/2 sin90=√4/2=1 cos0=√4/2=1 cos30=√3/2 cos45=√2/2 cos60=√1/2=½ cos90=√0/2=0
centripetal motion
net force on an object at a constant speed on a circular path points toward center of circle Fc=(mv2)/r ac=v2/r
torque
always greatest at 90o to object trying to move τ=rFsinΘ units: N*m
Work
W=FdcosΘ units: N*m=Joules
Kinetic energy
KE=½mv2 units: J
Work energy theorem
Wnet=∆KE and W=∆PE
Gravitational potential energy
U=mgh units: J
Average Power
P=W/t = ∆E/∆t units: Watts
momentum
p=mv
types of collisions
elastic collisions: KE and momentum conserved inelastic collisions: KE not conserved, momentum conserved totally inelastic collisions: KE not conserved, momentum conserved
Impulse
force applied to an object over time I=∆p=Fav∆t units: N*s
Hooke’s Law
F=-kx x=displacement of spring from unstrained length k=proportionality constant units: N/m - = restoring force always opposite to displacement of spring amplitude is max displacement from equilibrium
period in SHM
time required to complete one cycle
angular frequency
ω=2π/t = 2πf=√(k/m) frequency at which object at mass m vibrates on a string units: radians
frequency
f=1/T units: Hz = 1/s the number of cycles of motion per second
Elastic Potential energy
-energy a spring has because of being stretched or compressed. -at max displacement from equilibrium, potential energy of spring is at max and KE is 0 PEelastic=½ kx2 units: J = kg*m2/s2
Total mechanical energy
½mv2+mgh+½kx2
angular frequency of pendulum
ω=2πf=√(g/L) L=length (m)
restoring force of pendulum
F=-mgsin
properties of electromagnetic waves
-transverse, can trave through vacuum -all move through vacuum at speed of light (c)=3.0*108 m/s