Proteins: Terry & Paul G v.1 Flashcards
(153 cards)
Define: Gibbs free energy (ΔG)
Free energy change for a reaction:
ΔG = Gproducts - Greactants
What is the equation to find the activation energy for a reaction?
ΔG‡ = Gtransition state - Greactant
Gibbs Free Energy, Enthalpy and Entropy equation
ΔG = ΔH - TΔS
ΔG: change in Gibbs free energy
ΔH: change in enthalpy (heat)
T: absolute temperature (K)
ΔS: change in entropy (disorder)
How do spontaneous reactions occur?
Negative ΔG, which can be given by:
- Big negative ΔH (exothermic)
- OR Big positive ΔS (increase in entropy)
What is the first law of thermodynamics?
Law of Conservation of Energy, states that energy can neither be created nor destroyed; energy can only be transferred or changed from one form to another.
ΔE=q+w
- ΔE: change in internal energy
- q: heat
- w: work
What is the second law of thermodynamics?
The entropy of an isolated system always increases
What is the third law of thermodynamics?
The entropy of a system approaches a constant value as the temperature approaches absolute zero.
Define: exergonic
- ΔG is negative
- Free energy released
- Favourable: Spontaneous
Define: endergonic
- ΔG is positive
- Free energy absorbed
- Unfavourable: not spontaneous
Define: exothermic
- ΔH is negative
- Heat absorbed
Define: endothermic
- ΔH is positive
- Heat absorbed
How do you calculate the thermodynamic equilibrium constant from aA + bB ⇌ cC + dD?
[X]eq=concentration of substrate X at equilibrium
Calculating ΔG from ΔG°:
ΔG = ΔG° + RT ln Qi
Qi: where Q is calculated with initial concentrations of the reactants and products
Relating free energy with the equilibrium constant:
ΔG° = -RT ln K
What are the CHEMISTRY and PHYSICS standard conditions? ΔG°
- 298K
- Gases at partial pressure of 101.3 kPa (1 atm)
- Reactants & products at 1M
- [H+] = 1 M ⇒ pH=0
What are the BIOCHEMISTRY standard conditions? ΔG’°
- 298K
- Gases at partial pressure of 101.3 kPa (1 atm)
- Reactions occur at well-buffered aqueous solution at pH 7 e.g. [H+] & Mg2+
- [H+] = 10-7
- Mg2+ = 1 mM
Why are we interested in free energy?
It has predictive power. If we know standard free energy, we know:
- Under what initial conditions can the reaction occur spontaneously?
- Does reaction require coupling with a favoured reaction?
- What is the position of reaction at equilibrium?
- Theoretically, how much work can it do?
Making “unfavourable” reactions go: relating to Q/K
*the measure of whether a reaction will proceed spontaneously is ΔG, not ΔG’°
- If ΔG’° is positive, ΔG can be negative by altering initial conditions.
- For RT ln Q to be negative: Q < 1, therefore ln Q would be negative
- The concentration of products must be kept much lower than reactants:
- Removing products faster than it’s produced
- Replenishing/adding reactants faster than it’s being used up
Making “unfavourable” reactions go: coupling
- (Think story about Terry and his wife)
- Couple unfavourable with highly favourable reaction (in the active site of an enzyme)
- Must have a shared components (reactions and products)
Give 3 examples of how ‘unfavourable’ reactions are made ‘favourable’
- Reaction couplings
- Constant replenishing of reactants at a faster rate than they are being used
- Constant removal of products at a faster rate than they are being produced
Define: nucleotide
base + sugar + phosphate
Define: nucleoside
base + sugar
Explain why ATP is an energy-rich molecule

- Energy is released upon hydrolysis of phosphoanhydride bonds (uses energy)
- breakdown of ATP to:
- ADP + Pi (inorganic phosphate)
- AMP + PPi (pyrophosphate)
- breakdown of ATP to:
- Molecules at the start are less stable than the molecules that are formed
- Strong bonds are formed: creates a lot of energy
- Less negative charge (and repulsion) in ADP (or AMP) than ATP ⇒ more stable
- Pi ⇒ bonds in the inorganic phosphate are a lot stronger than the phosphoanhydride bonds (resonance forms)
- Substantially more energy is created from the formation of strong bonds than the breaking of weak bonds
Breaking a bond…
A. Releases energy
B. Absorbs energy
B
Bonds are happy places for atoms, as in it’s more stable, therefore energy must be put into the system to break bonds


























