Pure Maths Flashcards
(114 cards)
How would you find the midpoint of 2 coordinates?
xm = (x1 + x2) / 2
ym = (y1 + y2) / 2
How would you find the length between 2 coordinates?
the root of (x2 - x1)^2 + (y2 - y1)^2
What is the formula for the equation of a line?
y - y1 = m(x - x1)
How do you know if 2 lines are perpendicular?
Their gradients multiply to equal -1
What is a perpendicular bisector?
A line passing through the midpoint of AB at a right angle to AB
What is the discriminant?
What does it mean?
b^2 - 4ac of quadratic formula
If discriminant < 0, there are no real roots.
If discriminant = 0, there is one repeated real root
If discriminant > 0, there are two distinct real roots
How would you find x in the equation:
b^x = a?
x = logb(a)
Give the laws of logarithms
- logb(b^x) = x
- logb(1) = 0
- logb(b) = 1
- logc(a) + logc(b) = logc(ab)
- logc(a) - logc(b) = logc(a/b)
- nlog(a) = log(a^n)
- loga(b) = logc(b) / logc(a)
Where would you draw the asymptote and intercepts on the graphs:
- y = 3^x ?
- y = 2^x +2 ?
- asymptote at y = 0, intercept at (0,1)
- asymptote at y = 2, intercept at (0,3)
Where would you draw the asymptote and intercepts on the graph:
- y = ln(x) ?
- asymptote at x = 0, intercept at (1,0)
Where is the intercept of the graph:
- y = root ?
Where does it exist on the axes?
Intercept at (0,0).
Only exists in the positive quadrant
What does it mean if dy/dx is > 0? < 0?
- When dy/dx > 0, graph is increasing
- When dy/dx < 0, graph is decreasing
How would you draw the gradient function of a curve?
Draw a line with the polynomial order -1 of that of the original line.
The line crosses the x axis at the x values of the original turning points
What is the order/degree of a polynomial?
The highest power in the expression
Complete:
(x^3 + 2x^2 + 3x +2) / (x+1)
by inspection
x^2 + x + 2
What is the factor theorem?
If (x-a) is a factor of f(x), f(a) = 0
If (bx-a) is a factor of f(x), f(a/b) = 0
What is the remainder theorem?
When f(x) is divided by (bx-a), the remainder is f(a/b)
What does a triple root mean for the shape of the graph?
The gradient of the line at that point is 0
Where would you draw the asymptotes on the graphs:
- y = 1/x ?
- y = 1/x^2 ?
What is the difference in their shapes?
Both at y = 0, x = 0
Both have one part of the curve in the positive quadrant, but y = 1/x is reflected in the line y = -x, where y = 1/x^2 is reflected in the line x = 0
How would you describe the translations:
- y = f(x-a) ?
- y = f(x+a) ?
And how would you find the new equation?
- Translation by vector (a 0), replace x with (x-a)
- Translation by vector (-a 0), replace x with (x+a)
How would you describe the translations:
- y = f(x) + a ?
- y = f(x) - a ?
And how would you find the new equation?
- Translation by vector (0 a), replace y with (y-a)
- Translation by vector (0 -a), replace y with (y+a)
How would you describe the translations:
- y = -f(x)
- y = f(-x)
And how would you find the new equation?
- Reflection in x axis, replace y with -y
- Reflection in y axis, replace x with -x
How would you describe the translations:
- y = f(1/a x)
- y = f(ax)
And how would you find the new equation?
- Stretch parallel to x axis by scale factor a, replace x with (1/a)x
- Stretch parallel to x axis by scale factor 1/a, replace x with ax
How would you describe the translations:
- y = af(x)
- y = (1/a)f(x)
And how would you find the new equation?
- Stretch parallel to y axis by scale factor a, replace y with (1/a)y
- Stretch parallel to y axis by scale factor 1/a, replace y with ay