quantitative chemistry Flashcards

(36 cards)

1
Q

conservation of mass

A

sum of mass of reactants = sum of mass of products

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2
Q

amu

A

atomic mass unit

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3
Q

2 elements combine

A

-ide

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4
Q

more than 2 elements combine

A

-ate

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5
Q

2 or more atoms of same element

A

no change

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6
Q

what does iron (II) mean

A

indicates charge on transition metal. fe 2+

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7
Q

ionic compounds and charge

A

no overall charge - total positive charge = total negative charge

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8
Q

hydroxide

A

OH-

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9
Q

carbonate

A

CO3 2-

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10
Q

zinc

A

Zn 2+

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11
Q

nitrate

A

NO3 -

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12
Q

ammonium

A

NH4 +

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13
Q

lead

A

Pb 2+

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14
Q

sulfate

A

SO4 2-

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15
Q

copper

A

Cu 2+

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16
Q

silver

17
Q

relative atomic mass

A

mean average mass of an atom of an element expressed in AMU

18
Q

how to calculate relative atomic mass with percentage abundance

A

(M1 * 0.P1) * (M2 * 0.P2) = RMA

19
Q

relative formula mass

A

sum of all atomic masses present in the formula (Mr)

20
Q

relative molecular mass

A

sum of all atomic masses present in the formula (Mr)

21
Q

percentage by mass

A

RFM of wanted element / RFM

22
Q

why are moles used?

A

different chemicals contain different atoms -> mass cannot be used to compare particles easily

23
Q

what is avagadro’s constant

24
Q

what is the equation for moles

A

n = number of particles (mol)
Mr = relative formula/molecular mass
m = mass in g

n * Mr = m

25
how were equations made before the periodic table?
- evidence for a formula had to be worked out using practical methods - ratio between reactants and products could be found by experiment - dalton's atomic weights meant chemists could calculate ratios of particles - moles = numbers of particles (for us)
26
what is an excess of a chemical
having more of a chemical than required for a reaction
27
which is the limiting reactant
the chemical that is completely used up first
28
do you use the mass of the reactant in excess
no - only the mass of the limiting reactant
29
how is the limiting reactant calculated
you have 2.4g of Mg and 2.0g of O2 2mg + 02 -> 2MgO 1) 1 O2 + 2 Mg -> 1 MgO 0.0625 * 2 = 0.125 moles of mg 0.1 moles of Mg and up to 0.125 of O2 present, excess of O2 and Mg is limiting
30
solution
mixture of a solute and solvent
31
solute
a soluble solid that dissolves in a solvent
32
saturated solvent
no more solute can dissolve in the solvent
33
what is concentration
quantity of solute / quantity of liquid
34
what is the measurement of concentration?
1) grams per cubic decimeter g/dm^3 2) mol per cubic decimeter mol/dm^3
35
how do you convert from cubic centimeters to cubic decimeters
divide by 1000
36
how do you convert from cubic decimeters to cubic centimeters
multiply by 1000