Quark Mixing, CP Violation, Neutrino Oscillations and the Seesaw Mechanism Flashcards Preview

PHYS3543 Theoretical Elementary Particle Physics > Quark Mixing, CP Violation, Neutrino Oscillations and the Seesaw Mechanism > Flashcards

Flashcards in Quark Mixing, CP Violation, Neutrino Oscillations and the Seesaw Mechanism Deck (32)
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1

Where do fermion masses come from?

-fermion masses come from interaction with the scalar field
-allowed interactions must obey Lorentz invariance and gauge invariance

2

Allowed Interactions of Quarks

-quarks are given masses by their interactions with the scalar field
-the allowed interactions do not constrain the quarks to couple just to their own generations
-e.g. the left-chiral down quark could couple with the right-chiral down quark but also with the right-chiral strange quark
-rather than giving a simple mass to each quark, we have managed to couple each left-chiral quark flavour to a complex combination of right chiral quarks

3

Quark Interactions
Matrices

-the left-chiral up quark can couple to the right-chiral up quark:
i∂/ ul = λuu φ ur
-but coupling to right-chiral charm and top quarks is also allowed
i∂/ ul = λuc φ cr
i∂/ ul = λut φ tr
-this can be summarised in a matrix of λij
-after symmetry breaking this matrix becomes a mass matrix

4

Mass Matrix and Physical Quarks

-it doesn't make sense to talk about different masses for the same particle so what does the mass matrix represent?
-physical quarks are eigenstates of the mass matrix: u,c,t
-flavour states: u',c',t' are combinations of mass states

5

Why does the weak interaction violate quark flavours?

-flavour states, which are what the weak interaction see, are combinations of mass state, they themselves are not mass eigenstates

6

How do we find the mass eigenstates?

-diagonalise the mass matrix M by means of a similarity transformation:
M = U† Md U
-where Ms is the diagonalised matrix and U some unitary matrix
-this matrix U transforms between the flavour states d', s', b' seen by the weak interaction and the states of defined mass d, s, b
-since the weak interaction is rare, we generally consider the mass eigenstates, the only physical significance of the flavour states is in weak interactions

7

Flavour-Changing Weak Current

-the flavour changing weak current is coupled to by the W± bosons
-the γ matrix acts in spinor space and U acts in flavour space so they always commute
-introduce the CKM matrix V=Uu†Ud

8

CKM Matrix for 2 Generations of Quark

-in the case of two generations of quark, V is 2x2 and complex-valued so has 8DoF
-V is unitary, V†V=1 which removes 4DoF leaving 4
-can show that there is a three-fold redundancy in V leaving only one 1DoF

9

CKM Matrix for 3 Generations of Quark

-V is 3x3 and unitary so 9DoF
-mixing between 3 up type quarks and 3 down type quarks means a five-fold redundancy leaving 4DoF
-but if we had 3DoF we could think of them as 3 rotations
-but different amounts of mixing between generations leads to 1 extra DoF leading to complex phase in the CKM matrix

10

CP Violation
Outline

-weak interaction violates CP symmetry
-violation comes from the complex phase in the CKM matrix

11

How do we show that complex couplings lead to CP violation?

-consider probability amplitude for some process, M
-then M is complex valued and can be written:
M = |M| e^(iα)
-note that M itself is not measurable, but |M|²=M*M is
-if the process can occur through two different routes then:
M = M1 + M2 = |M1|e^(iα1) + |M2|e^(iα2)
-if CP is not violated then M_, the probability amplitude for the conjugate process should be the same as M
-calculating |M|²-|M_|² find that the difference is only non-zero if the complex phase is non-zero i.e. presence of complex phase leads to CP violation

12

Where can we see CP violation?

-CP violation manifests itself in the decays of neutral mesons
-Ko and Ko_ mesons mix through quark mixing, Ko_ can spontaneously transform into Ko and vice versa
-since the quark flavours need not be conserved, we know that the flavour symmetries are not exact and the Hamiltonian is not invariant under flavour transformations

13

Ko and Ko_ Mixing
Mass Eigenstates

-the mass eigenstates are not the Ko and Ko_, but some linear combination of these flavours states
-if CP was an exact symmetry, then CP would commute with the Hamiltonian and the mass eigenstates and CP eigenstates would be identical
-i.e. we would expect physical states to be eigenstates of CP

14

K1 and K2

-consider the combined action of C and P on the flavour eigenstates of the kaon system:
CP|Ko_⟩ = CP|sd_⟩
= |s_d⟩
= |Ko⟩
-similarly, CP|Ko⟩ =|Ko_⟩
=>
K1 = 1/√2 (|Ko⟩ + |Ko_⟩ )
K2 = 1/√2 (|Ko⟩ - |Ko_⟩ )
-where K1 and K2 are CP eigenstates:
CP|K1⟩ = |K1⟩
CP|K2⟩ = -|K2⟩
-if CP is conserved, we expect these to be the physical states

15

Decay of K1

-since the K1 has positive 'CP-parity', it can only decay to CP=1 states
-the dominant decay mode is:
K1 -> π+ + π-

16

Decay of K2

-K2 can only decay to CP=-1 states
-the dominant decay mode is:
K2 -> π+ + π- + πo

17

Ks and Kl

-since the mass of the kaon is only slightly larger than the mass of three pions, the phase space of available states is much smaller for K2 decay than it is for K1 decay
-this pushes the decay rate for the K2 up
-experiments confirm there is a short-lived and a long-lived neutral kaon, Ks and Kl
-we assume:
Ks=K1 and Kl=K2
-however careful experimentation shows that if a beam of neutral kaons is left to travel through empty space such that the K2 component decays away, there are still CP=+1 decays demonstrating CP cannot be conserved
-this CP-violation could take place in the kaon mixing or the decay processes themselves
-if it is the kaon mixing then the assignments of Ks and Kl are no longer correct
-we instead find that Ks is only MOSTLY K1 but has a little K2 mixed in and vice versa for Kl

18

T Symmetry

-time reversal, essentially the replacement of a set of particles with the same particles moving in the opposite direction, denoted T

19

Properties of T

-while C and P are both unitary operators (U† = U^(-1)), T is anti-unitary:
T† = -T^(-1)
-a consequence of this is that, whereas P and C symmetry imply the conservation of parity and C-parity, there is no conserved quantity associated with T

20

Physical Consequences of T Symmetry

-the principle of detailed balance: essentially, the statement that transition amplitudes between a set of initial and final states should be equal if the initial and final states are interchanged
-as with C, P and CP, T symmetry is found to be violated by weak interactions, the laws of physics are not the same when run in reverse
-however the physical laws governing the universe are typically time-reversal symmetric, it is only the initial conditions that typically lead to an obvious arrow of time through the second law of thermodynamics

21

The CPT Theorem

-when it was discovered that C and P individually violated, it was originally suggested that CP may still be respected, until CP violation was discvoered
-what about CPT?
-there is no evidence that this combined symmetry is violated
-if it is found to be violated, it will also mean violation of Lorentz invariance
-i.e. CPT violation would imply that special relativity is incorrect and that spacetime itself is not symmetrical as we imagine
-there are ongoing searches for CPT violation

22

Neutrinos in the Standard Model

-in the standard model, neutrinos are massless particles
-this means the mass eigenvalues for neutrinos are all zero
-this would allow for no mixing between lepton flavours as the flavour states for leptons could always be identified with mass eigenstates

23

Evidence for Neutrino Mass

-in the 1990s, it was discovered experimentally that neutrino flavours oscillate
-i.e. in a beam of neutrinos, the probability of measuring neutrinos of a particular flavour fluctuates over time, there is a mixing between lepton flavours
-this is only possible if the mass eigenstates are different from the flavour states
-this requires a similar mixing matrix for leptons as we had for quarks known as the PMNS matrix
-so now we know neutrinos must have mass even if no direct measurement has ever been made

24

Solar Neutrino Problem

-we don't measure enough νe's from the sun for the amount produced in beta decay
-solution: the νe's are changing into νμ and ντ, mixing
-this is where the PMNS matrix comes in
-neutrino masses must be VERY small as they have never been measured
-can experimentally determine that the sum of all three neutrino masses must be <0.3eV
-note that one could still be massless as then there would still be no degeneracy, but at least two must have mass

25

The See-Saw Mechanism
Allowed Mass Terms

-allowed mass terms take the form:
i∂/ fl = m fr
-these are the only terms that obey both Lorentz and gauge invariance

26

The See-Saw Mechanism
No Allowed Mass Terms

-we said that:
i∂/ fl = m fl
-is Lorentz invariant but not gauge invariant as they have different charges
-there is one exception, can have this kind of mass if the particle in question has no charges
-the only candidate is the right chiral neutrino

27

The See-Saw Mechanism
Equation of Motion for Neutrinos

-the new kind of mass term is not allowed for LH neutrinos so the RHS of the equation of motion is:
A (vl vr)^t
-where A is a 2x2 matrix with entries 0, md, md, mm

28

The See-Saw Mechanism
Natural Scales

-natural scale for md ~ electroweak breaking scale
-natural scale for mm unknown, but must be mm>>md

29

The See-Saw Mechanism
Physical Masses

-the eigenvalues of the matrix:
λ ≈ mm
λ ≈ - md²/mm² << 1

30

The See-Saw Mechanism
Eigenstates

λ ≈ mm -> (0 1)^t
λ ≈ - md²/mm² -> (1 0)^t
-every neutrino ever observed has been LC with very small mass
-the RH state with high mass and no interactions has been suggested to be dark matter