Questions Flashcards
(98 cards)
Sound waves continue to travel until:
a. they are redirected by material surfaces.
b. they are completely dissipated by the effects of beam divergence.
c. they are transformed into another waveform.
d. all of the energy is converted into positive and negative ions.
a. they are redirected by material surfaces.
- Wavelength may be defined as:
a. frequency divided by velocity.
b. the distance along a wavetrain from peak to trough.
c. the distance from one point to the next identical point along the waveform.
d. the distance along a wavetrain from an area of high particle motion to one of low particle motion.
c. the distance from one point to the next identical point along the waveform.
- To determine wavelength:
a. multiply velocity by frequency.
b. divide velocity by frequency.
c. divide frequency by velocity.
d. multiply frequency by wavelength.
b. divide velocity by frequency.
- The wavelength of a 5 MHz sound wave in water is [VL = 1.483(10)5 cm/s]:
a. 0.297 mm (0.012 in.).
b. 2.54 mm (0.10 in.).
c. 296 mm (11.65 in.).
d. 3.00 mm (0.12 in.).
a. 0.297 mm (0.012 in.).
- Thickness resonance occurs when transducers and test parts are excited at a frequency equal to
(where V = sound velocity and T = item thickness):
a. 2T/V.
b. T/2V.
c. V/2T.
d. 2V/T.
c. V/2T.
- The equations that show VL and VT being dependent on elastic properties suggest that:
a. materials with higher densities will usually have higher acoustic velocities.
b. materials with higher moduli will usually have higher velocities.
c. wave velocities rely mostly upon the ratios of elastic moduli to material density.
d. VT will always be one-half of VL in the same material.
c. wave velocities rely mostly upon the ratios of elastic moduli to material density.
- Velocity measurements in a material revealed that the velocity decreased as frequency increased. This material
is called:
a. dissipated.
b. discontinuous.
c. dispersive.
d. degenerative.
c. dispersive.
- Plate thickness = 25.4 mm (1 in.), pulse-echo straight beam measured elapsed time = 8 µs. What is the most
likely material?
a. carbon steel.
b. lead.
c. titanium.
d. aluminum.
d. aluminum.
- The acoustic energy reflected at a plastic glass-quartz interface is equal to:
a. 64%.
b. 41%.
c. 22%.
d. 52%.
b. 41%.
- It can be deduced from Table 2 that the densities of:
a. plastic glass and water are in the ratio of 1.17:1.
b. steel and aluminum are in the ratio of 2.31:1.
c. quartz and aluminum are in the ratio of 1.05:1.
d. water and quartz are in the ratio of 10.13:1.
a. plastic glass and water are in the ratio of 1.17:1.
- The acoustic energy transmitted through a plastic glass-water interface is equal to:
a. 87%.
b. 36%.
c. 13%.
d. 64%
a. 87%.
- The first critical angle at a water-steel interface will be:
a. 18°.
b. 14.5°.
c. 22°.
d. 35°.
b. 14.5°.
- The second critical angle at a water-aluminum interface will be:
a. 28°.
b. 33°.
c. 67°.
d. 90°.
a. 28°.
- The incident angle needed in immersion testing to develop a 70° shear wave in plastic glass using the
information in Table 2 equals:
a. 83°.
b. 77°.
c. 74°.
d. 65°
b. 77°.
- Figure 2 shows the partition of incident and transmitted waves at a water-aluminum interface. At an
incident angle of 20°, the reflected wave and transmitted waves are respectively:
a. 60% and 40%.
b. 40% and 60%.
c. 1/3 and 2/3.
d. 80% and 20%.
a. 60% and 40%.
- From Figure 2 it is evident that the sum of the incident wave’s partitions (transmitted and reflected) is:
a. highly irregular at low angles, but constant above 30°.
b. lower at angles between 16° and 26°.
c. rarely more than 0.8.
d. always equal to unity.
d. always equal to unity.
- The principal attenuation modes are:
a. absorption, scatter, beam spread.
b. beam spread, collimation, scatter.
c. scatter, absorption, focusing.
d. scatter, beam spread, adhesion.
a. absorption, scatter, beam spread.
- Attenuation caused by scattering:
a. increases with increased frequency and grain size.
b. decreases with increased frequency and grain size.
c. increases with higher frequency and decreases with larger grain size.
d. decreases with higher frequency and decreases with larger grain size.
a. increases with increased frequency and grain size.
- In very fine-grain, isotropic crystalline material, the principal loss mechanism at 2 MHz is:
a. scatter.
b. mechanical hysteresis.
c. beam spread.
d. absorption.
c. beam spread.
- Two plates yield different backwall reflections in pulse-echo testing (18 dB) with their only apparent
difference being in the second material’s void content. The plates are both 75 mm (3 in.) thick. What is the
effective change in acoustic attenuation between the first and second plate based on actual metal path distance?
a. 0.118 dB/mm (3 dB/in.)
b. 0.236 dB/mm (6 dB/in.)
c. 0.709 dB/mm (18 dB/in.)
d. 0.039 dB/mm (1 dB/in.)
a. 0.118 dB/mm (3 dB/in.)
- The equation, sin ϕ = 0.7 λ/D, describes:
a. beam spread angle at 50% decrease in signal from the centerline value.
b. one-half the beam spread angle at 50% decrease in signal from the centerline value.
c. one-half the beam spread angle at 20% decrease in signal from the centerline value.
d. one-half the beam spread angle at 100% decrease in signal from the centerline value.
b. one-half the beam spread angle at 50% decrease in signal from the centerline value.
- The beam spread half-angle in the far field of a 25.4 mm (1 in.) diameter transducer sending 5 MHz longitudinal
waves into a plastic glass block is:
a. 0.5°.
b. 1.5°.
c. 3.1°.
d. 6.2°.
b. 1.5°.
- The near field of a round 12.7 mm (0.5 in.) diameter contact L-wave transducer being used on a steel test
part operating at 3 MHz is:
a. 12.7 mm (0.5 in.).
b. 25.4 mm (1 in.).
c. 9.9 mm (0.39 in.).
d. 20 mm (0.79 in.).
d. 20 mm (0.79 in.).
- The depth of penetration of the sound beam into a material can be increased by:
a. using a higher frequency.
b. using a longer wavelength.
c. using a smaller transducer.
d. using a lower frequency and a larger transducer.
d. using a lower frequency and a larger transducer.