Review Flashcards
(103 cards)
What is the moist inspired Pio2 of a normal healthy dog in Denver, Colorado where the barometric pressure is 640 mmHg? Assume a body temperature of 37 oC.
PIO2= (PB-PH2O)*FIO2 PIO2= (640-47)*0.21 = 124.53
Define: Ventilation
movement of gas from the environment to gas exchange space; i.e. the lung
What is the driving force behind gas movement?
pressure gradient
What are the goals of ventilation?
provide oxygen (for metabolism) and remove carbon dioxide
What is the oxygens source/sink?
source- environment sink- mitochondria
What is carbon dioxides source/sink?
source- mitochondria sink- environment
How is ventilation measured?
breathing frequency times tidal volume
You are asked to assist in monitoring the respiratory function of an anesthetized horse. Part of the protocol involves monitoring the CO2 concentration of the expired gas using a CO2 analyzer. What is the estimated PCO2 of the alveolar gas if the analyzer reads 5% CO2 end-tidal sample? Assume you are in the VMTH and the barometric pressure is 765 mmHg, the body temp. of the horse is 38oC and you are measuring dry gas as it enters the analyzer.
PCO2= FCO2*(PB) PCO2= (0.05)*(765)= 38.25 mmHg
You are going scuba diving in the Bahamas for spring break. You will be using a Heli-Ox gas mixture containing 20% oxygen and 80% helium. You will be diving at depths equivalent to 3 atmospheric pressures. What will be the moist inspired PO2 at that depth?
PIO2= (3PB-PH2O)*0.20 PIO2= ((3*760)-47)*0.20 PIO2= 446.6
Why is intrapleural pressure generally less than atmospheric. What happens to intrapleural pressure during deep inspiration and during a Valsalva maneuver?
Two pleural membranes are stuck together with an unexpandable layer of water between them (pleural fluid). The pulling force of the chest wall wanting to expand outward acts against the collapsing force of the lung to create a negative pressure inside the pleural space (-5 cmH2O @ rest = PPL). At rest, pressure in the alveolus is the same as atmospheric, which is zero. However, during inspiration, PA becomes negative allowing atmospheric air to flow into the lungs down the pressure gradient. During deep inspiration pleural pressure becomes more negative as the chest wall expands Valsalva maneuver involves forced expiratory effort with a closed glottis.
What happens to the volume of the lungs and thorax during pneumothorax?
lungs collapse (decrease volume), chest volume increases (barrel chested)
What determines the elastic recoil of the lung?
lung is a meshwork of connective tissue that is composed of elastic fibers; stretching these elastic fibers from their resting position will create a retracting force; surfactant also contributes
What determines the resting position of the lung-thoracic cavity system?
resting position of the lung-thoracic cavity is determined by the balance of the expanding forces of the chest wall and the collapsing forces of the lung (FRC=40)
What happens to this position when there is a decrease in lung elastic recoil such as with emphysema?
lungs are less able to contract back to their normal resting position due to an increase in compliance, so resting position of the lungs would be more extended than normal (higher FRC at rest)
Differentiate between anatomical dead space and physiological dead space.
Anatomical: volume of all space of the respiratory system besides the alveoli and their closely related gas exchange areas Physiological: when alveoli themselves are non or partially functional because of absent or poor blood flow through adjacent pulmonary capillaries
Use: VT= 450 mL RR= 20 bpm Dead space = 45 mL to determine a) Minute ventilation b) Alveolar ventilation c) Dead space/Tidal volume ratio
a) VE= VT*f = (450)(20) = 9000 mL/min = 9 L/min b) VA= (VT-VD)*f = (450-45)*20 = 8100 mL/min = 8.1 L/min c) VD/VT = 45/450 = 1:10
You have performed pulmonary function tests on a dog and have obtained the following data: VT= 350 mL Ppl (end of inspiration) = -2 cmH2O Peak air flow = 0.50 L/sec Airway pressure at peak airflow = 5 cmH2O Determine a) compliance of the lung, CL b) airway resistance, RAW
a) must be @ 0 flow for compliance CL = change V/ change PPL CL = 350 mL/2 cmH2O = 175 mL/cmH2O = 0.175 L/cmH2O (normal lung compliance = 0.20 L/cmH2O) b) RAW= change PA/change V = change P airway/change airflow RAW= 5 cmH2O /0.50 L/sec = 10 cmH2O/L/sec
You are asked to examine a Florida panther in your clinic that has been injured. The animal, though restrained, is frightened in your examining room and is in pain. This causes the animal to hyperventilate. What will happen to PAO2 and PACO2 if the minute ventilation doubles
PAO2 will increase due to the increase of net inflow of air and O2 PACO2 will decrease because CO2 is removed quicker than can be added to the blood
Define: TLC
Total lung capacity TLC = VC + RV TLC = FRC + IC TLC = RV + ERV + IC
Define: FRC
Functional residual capacity, resting lung volume FRC = TLC - IC FRC = ERV + RV FRC = (TLC-VC) + ERV
Define: VC
Vital capacity, inspiration to maximum capacity VC = TLC - RV VC = IC + ERV
Define: VT
Tidal volume, normal breath above FRC Volume of air inspired per breath Units usually in mL
Define: RV
Residual volume, volume of air remaining in the lung after full expiration (forced); amount of air left in lungs if lungs are removed from the chest cavity RV = TLC - VC RV = FRC - ERV RV = TLC - (IC+ERV)
Define: ERV
expiratory reserve volume, maximal volume of air that can be expired by forceful expiration after the normal tidal expiration ERV = FRC - RV ERV = TLC - (IC+RV)

