ROBex 2020 Flashcards
(142 cards)
2020-A1. The biological effects of radiation are dependent upon:
A. Only total dose
B. Total dose, dose-rate, and radiation quality
C. Only dose rate
D. Only dose rate and radiation quality
E. None of the above
Answer: B
The biophysical properties of radiation, including dose rate, ionization density, and total dose are all important determinants of radiation action on cells
2020-A2. Which radiation would produce energy depostions in cells that would result in the most lethal molecular damage?
A. 100 keV electron
B. 1 MeV photon
C. 10 MeV photon
D. 1.0 keV electron
E. 1 MeV neutrino
Answer: D
Low energy or track end electrons deposit their energy over relatively small volumes
2020-A3. The majority of the energy received by biologic material from x rays is transferred by:
A. Electrons
B. Degraded gamma photons
C. Protons
D. Spallation products
E. Neutrons
Answer: A
When x-rays are absorbed in biologic material, the photon first interacts with an orbital electron of an atom of the material by the photoelectric or compton process to produce a fast recoil electron.
The energy of this electron is lost through interactions with other atoms or molecules to produce bio molecular ions. The ensuing biochemical events may or may not lead to biologic effect.
Protons and spallation products are formed when neutrons are absorbed in tissue.
2020-A4. A photon with energy of 100 MeV encouters a calcium atom; identify likely interactions in order of probability:
A. Pair production > Compton scatter > Photoelectric absorption
B. Pair production = Compton scatter > Photoelectric absorption
C. Compton Scatter > Pair production > Photoelectric absorption
D. Photoelectric absorption > Compton Scatter > Pair production
E. Compton scatter > Photoelectric absorption > Pair production
Answer: A
Note that 100 MeV is a high energy photon. This favors pair production, especially in a high Z atom (Ca has a relatively high atomic number for biologic tissues).
By contrast compton scatter is important in intermediate energy photons - from hundreds of KeV to 10 MeV and photoelectric absorption is favored in lower energy interactions
2020-A5. Free radicals produced from the radiolysis of cellular water:
A. are formed primarily in the cell nucleus
B. play a minor role in the oxygen effect
C. contribute to both the “a” and “b” mechanism of cell killing
D. do not play a role in the cell killing by high LET radiations
E. typically exhibit “lifetimes” of approximately 10 seconds
Answer: C
The free radicals produced from the radiolysis of water molecules play a role in both the “A” (single track producing 2 breaks) and the “b” (2 tracks each producing a single break) mechanisms of cell killing.
Water radicals are formed randomly throughout the cell. A large component of oxygen modifiable damage in cells is produced by OH-.
Water radicals are involved in cell killing by both low-LET and high-LET radiations. The lifetimes of free radicals are on the order of microseconds.
2020-A6. It is known that oxygen levels strongly influence the indirect effects of radiation damage. Which observations would you expect in the following studies?
A. cells irradiated under hypoxic conditions exhibit higher levels of DNA strands by x-ray than serobic cells
B. cells grown under aerobic conditions exhibit higher levels of DNA strand breaks induced by low-LET radiation than cells irradiated in hypoxia
C. equal numbers of DNA strand breaks are observed in cells grown under aerobic or hypoxic conditions following treatment with low LET radiation
D. oxygen enhances the toxicity of high LET radiation but has less of an effect on low LET radiation
E. none of the above
Answer: B
High oxygen tensions >10 mm Hg are effective in producing much higher levels of DNA damage than in low oxygen tension
2020-A7. Ionizing radiation produces a number of lesions in DNA. The specific type of radiation-induced DNA damage that is most closely correlated with cell kill is:
A. DNA double stranded breaks
B. DNA single stranded breaks
C. Base damage
D. DNA protein crosslinks
E. Sister chromatid exchange
Answer: A
Unrepaired DNA double stranded breaks are potentially lethal lesions
1 Gy ->
40 DSBs
1000 SSBs
2020-A8. Which one of the following statements is true concerning formation of strand breaks?
A. Single strand breaks are the most common lesion formed by ionizing radiation
B. UV irradiation forms primarily double strand breaks
C. DNA double strand breaks are repaired by mismatch repair
D. Single strand breaks are the most cytotoxic lesions formed by ionizing radiation
E. DNA double strand breaks are repaired in S-phase
Answer: A
Single stranded breaks are the most common lesion formed by ionizing radiation but the yare not the most cytotoxic lesion
2020-B1. According to the linear quadratic model of cell survival, beta-type damage to the DNA molecule means that:
A. Irreparable single strand breaks are produced by the passage of single charged particles
B. Irreparable double strand breaks are produced by the passage of a single charge particle
C. Irreparable double strand breaks are produced by the passage of 2 charged particles
D. Repairable single strand breaks are produced by the beta particles emitted after photonuclear interactions
E. Irreparable double strand breaks are produced by the beta particles emitted after photonuclear interactions
Answer: C
Beta type interactions refer to interactive single strand breaks caused by independent charged particles. Each is considered reparable but when they combine to produce a double strand break, irreparable damage can occur
2020-B2. Clustered lesions in DNA:
A. include strand breaks but not base damages
B. decrease in complexity with increasing LET
C. are more readily and accurately repaired than base damages
D. are produced because of the nanometer scale in-homogeneities in energy depositions in DNA from ionizing radiation
E. are not relevant for cell survival after exposure to ionizing radiation
Answer: D
Clustered DNA lesions (multiply damaged sites) which are produced because of inhomogeneous energy depositions in DNA, include base damages and strand break (and presumably cross-links, although those have not yet been measured).
Clusters increase in complexity with increasing LEt and are important for cell killing because they are more difficult to repair accurately than single lesions.
2020-B3. Irradiation of mammalian cells with 1 to 5 Gy can produce the following types of damage (which one of the following is true):
A. both blunt and staggered double strand DNA break
B. a higher frequency of double strand DNA breaks relative to single strand DNA breaks
C. DNA protein crosslinks
D. significant de-naturation of various proteins
E. Both A & C are true
Answer: E
Both direct and indirect action of radiation can produce an array of blunt and staggered DSBs.
Single strand DNA breaks are always generated at much higher frequency than double strand breaks. Although less frequent than SSB and DSBs, DNA protein crosslinks can be detected after 1-5 Gy of irradiation.
Protein de-naturation requires extremely high radiation doses.
2020-B4. It is known that oxygen levels strongly influence the indirect effects of radiation damage. Which observation would you expect in the following studies?
A. cells irradiated under hypoxic conditions exhibit higher levels of DNA strand breaks by x-rays than aerobic cells.
B. cells grown under aerobic conditions exhibit higher levels of DNA strand breaks induced by low-LET radiation than cells irradiated in hypoxia.
C. equal numbers of DNA strand breaks are observed in cells grown under aerobic or hypoxic conditions following treatment with low LET radiation.
D. oxygen enhances the toxicity of high-LET radiation but has less of an effect on low-LET radiation.
E. none of the above
Answer: B
High oxygen tensions >10 mm Hg are effective in producing much higher levels of DNA damage than in low oxygen tension
2020-B5. Which type of DNA damage listed below is formed by UV radiation?
A. Pyrimidine dimers
B. Double strand breaks
C. Single strand breaks
D. Interstrand bross-links
E. B&C
Answer: A
Pyrimidine dimers are formed by UV radiation
Note: Xeroderma Pigmentosum is linked to a nucleoside excision repair deficit in removing these pyrimidine dimers.
Mnemonic: “X” pigmentosum is “Nude” excision repair

2020-B7. Following irradiation with 3 Gy of 250 kVp x-rays, the number of:
A. single strand DNA breaks > double strand DNA breaks > altered DNA bases
B. altered DNA bases > single strand DNA breaks > double strand breaks
C. double strand DNA breaks > altered DNA bases > single strand DNA breaks
D. altered DNA bases > double strand DNA breaks > single strand DNA breaks
E. single strand DNA breaks > altered DNA bases > double strand DNA breaks
Answer: B
Following a dose of 1 Gy, per cell:
- >1000 base damages
- 800 ssDNA breaks
- 40 dsDNA breaks
2020-C1. Which of the following gene protein products is involved with homologous rejoining?
A. rad50, rad51, and rad 57
B. rad59, rad51, and MRE11
C. XRCC1, MRE11, rad50
D. ku70, rad51, MRE11
E. Only rad50, rad51, and ku70
Answer: A
Several gene products are associated with repair.
Homolorous repair requires the below and other proteins to recognize, signal, and initiate repair of DNA damage:
- rad 50, rad 51, rad 52, rad 54, rad 55, rad57
- ATM, XRCC2, XRCC3, NBS1, and MRE 11
Remember that the MRN complex is MRE11, rad50, NBS1 - this recognized dsDNA breaks

2020-C2. Which techniques are used to characterize DNA repair?
A. Southern blot analysis
B. Alkaline/neutral filter elutions
C. Comet assay
D. Pulsed-field gel electrophoresis
E. All of the above
Answer: E
Southern blotting was used to detect preferential DNA repair of active compared to inactive genes. Mnemonic: SNOW DROP (Southern-DNA, Northern-RNA, Western-Protein)
Alkaline/neutral filter elutions are used to detect single and double strand DNA breaks respectively. (Alk = ssDNA, Neutral = dsDNA) . Mnemonic - To be neutral, you need to see both sides
The comet assay is an electrophoresis separation of DNA fragments from whole cells and thus measures strand breaks
Pulsed field gel electrophoresis (PFGE) is used to separate DNA pieces of relatively high molecular weight. The technique essentially measures dsDNA breaks and can measure repair if cells are exposed to radiation and then allowed to recover over time.

2020-C3. With regard to cell survival after 1.8 Gy of X-rays, which repair process is the least important?
A. Homologous re-combinational repair
B. Base excision repair
C. Mismatch repair
D. Non-homologous end joining
E. Single strand annealing
Answer: C
Mismatch repair does not play a role in the repair of ionizing radiation induced DNA damage
2020-C4. Which process is almost never involved in the repair of DNA damage induced by ionizing radiation:
A. Ligation
B. Recombination repair
C. Double strand break repair
D. Base excision repair
E. Nucleotide excision repair
Answer: E
The nucleotide excision repair pathway primarily repairs UV photoproducts. Little occurs after ionizing radiation as evidenced by the relatively small amount of repair synthesis detected after exposure.
2020-C5. Which repair pathway is responsible for repair for DNA double strand breaks in the G1 phase of the cell cycle:
A. Mismatch repair
B. Interstrand cross-link repair
C. Nucleotide excision repair
D. Non homologous end joinging
E. Homologous recombination
Answer: D
NHEJ is responsible for primarily repairing dsDNA breaks in the G1 phase.
Homologous repair is primarily reponsible for repairing dsDNA breaks in S-phase
2020-C6. Which one of the proteins is involved in nucleotide excision repair?
A. Ku 80
B. DNA PKs
C. ERCC1
D. BRCA1
E. RAD51
Answer: C
ERCC1 is involved innucleotide excision repair
Ku80 is part of the ku70/80 dsDNA repair complex for NHEJ
DNA-PKcs are also used in NHEJ for dsDNA break repair. breaks. DNA-PKcs knockout mice have severe combined immunodeficiency due to their V(D)J recombination defect.
BRCA1 protein interacts with RAD51 during repair of dsDNA breaks (BRCA2 also interacts with RAD51)

2020-C7. Of the following, the DNA repair mechaism that most often results in a mutation is:
A. Non-homologous end joining
B. Mismatch repair
C. Nucleotide excision repair
D. Homologous recombination
E. Base excision repair
Answer: A
NHEJ involves the direct rejoining of free DNA after the removal of damaged nucleotides and therefore nearly always results in the loss of some DNA sequence
2020-C8. Which protein is necessary for NHEJ?
A. BRCA1
B. RAD51
C. XLF
D. MRE11
E. NBS1
Answer: C
Non-homologous end-joining factor 1 (NHEJ1) is also known as Cernunnos or XRCC4-like factor (XLF). It is required for NHEJ.
XLF interacts with DNA ligase IV and XRCC4 and is thought to be involved in the end-bridging or ligation steps of NHEJ.
BRCA1 and RAD51 work together in both HR and NHEJ for dsDNA repair
MRN complex (MRE11/rad50/NBS1) works in initial processing of dsDNA breaks for either HR or NHEJ. The MRN complex also participates in activating the checkpoint kinase ATM in response to DNA damage.
2020-D1. Two hit aberrations:
A. Increase linearly as a function of dose
B. do not exhibit a dose rate/ dose fractionation effect
C. decrease in frequency with increasing dose rate
D. account for the “b” coefficient of dose response curves
E. result from single lethal hits
Answer: D
Two hit aberrations (or DNA breaks) are dependent on the square of the dose; hence they are the “b” component of the dose response curve and will decrease with dose fractionation or decreasing dose rate, both of which allow time for repair.
2020-D2. Which type of chromosome aberration predominates following exposure to low doses of ionizing radiation?
A. Dicentrics
B. Translocations
C. Rings
D. Terminal deletions
E. Interstitital deletions
Answer: D
Single hit kinetics predominates at low doses of ionizing radiation. Terminal deletions involve a single dsDNA break and therefore follow single-hit kinetics.
All of the other chromosome abberations listed involve 2 dsDNA breaks and therefore follow 2 hit kinetics.
















