Semester 1 Final Flashcards
(68 cards)
If: B is between A and C
Then: AB=BC=AC
Segment Addition Postulate
If: AB=CD
Then: Line AB is congruent to Line CD
Definition of Congruent Segments
If: D is in the interior of Angle ABC
Then: m < ABD + m < CBD = m < ABC
Angle Addition Postulate
If: m < A = m < B
Then: < A is congruent to < B
Definition of Congruent Angles
If: M is the midpoint of Line AB
Then: Line AM is congruent to Line MB
Definition of Midpoint
If: Segment Bisector
Then: Intersects at the midpoint
Definition of Segment Bisector
If: Angle Bisector
Then: 2 congruent (equal) adjacent angles
Definition of Angle Bisector
If: 2 lines are perpendicular
Then: Form a right angle
Definition of Perpendicular
If: Right Angle
Then: 90 degrees
Definition of Right Angle
a=a
Reflexive Property
If: a=b
Then: b=a
Symmetric Property
If: a=b
Then: b=a
Transitive Property
If: < 1 and < 2 are right angles
Then: < 1 is congruent to < 2
Right Angle Congruence Theorem
All right angles are congruent
If: < 1 and < 2 form a linear pair
Then: < 1 and < 2 are supplementary
Linear Pair Postulate
If: < 1 and < 2 are vertical angles
Then: < 1 is congruent to < 2
Vertical Angles Theorem
If: < 1 and < 2 are supplementary
< 2 and < 3 are supplementary
Then: < 1 is congruent to < 3
Congruent Supplements Theorem
If: < 1 and < 2 are complementary
< 2 and < 3 are complementary
Then: < 1 is congruent to < 3
Congruent Complements Theorem
If: Lines g and h intersect to form a linear pair of congruent angles
Then: g is perpendicular h
(theorem)
If: 2 sides of 2 adjacent acute angles are perpendicular
Then: Angles are complementary
(theorem)
If: 2 lines are perpendicular
Then: They form 4 right angles
(theorem)
perpendicular lines for 4 right angles
If: Parallel lines
Then: Corresponding angles are congruent
CA Postulate
If: Parallel lines
Then: Alternate Interior Angles are congruent
AIA Theorem
If: Parallel lines
Then: Alternate Exterior Angles are congruent
AEA Theorem
If: Parallel lines
Then: Consecutive Interior angles are supplementary
CIA Theorem