Semester 2 Final Flashcards
(66 cards)
Diatomics
H2 N2 O2 F2 Cl2 Br2 I2
5 types of reactions
- Synthesis (Composition or Combination)
- Decomposition
- Single Replacement
- Double
- Replacement
Combustion
Synthesis reaction
A + B = AB
Decomposition reaction
AB = A + B
Single replacement reaction
A + BC = AC + B
Double replacement reaction
AB + CD = BC + AD
(Inner + Outer)
Combustion reaction
Always produces CO2 & H20
Law of conservation of mass
Each side of a chemical equation must have the same amount of atoms of each element
Mole/Avogadro’s number
6.02 x 10^23
Molar mass
g/mol or mol/g
Atomic mass
Mass of an element on the periodic table Always has 2 decimals
Particles for monoatomic elements
1 mol = Avogadro’s number atoms
Particles for molecular compounds and diatomic elements
1 mol = Avogadro’s number molecules
Particles for ionic compounds
1 mol = Avogadro’s number formula units
Particle conversion
mol/Avogadro’s number particles
Avogadro’s number particles/mol
2 step mole conversion
Mass in grams > Moles > Particles
And vice versa
Percent composition
(Part/Whole) x 100
Percent composition by mass
(mass of element/ mass of compound) x 100
Percent composition by formulas
(molar mass of element/ molar mass of compound) x 100
Empirical formula
Smallest whole number ratio of atoms in a compound
Divide elements/compounds when in grams by their molar mass to determine their subscript
When you are only given percents, assume the sample is 100.0g
Hydrates
Compounds that are
chemically bonded to water molecules
Naming hydrates
Use molecular compound prefixes for the moles of water and attach the name “hydrate”
Molecular formula
“True Formula” - the actual number of atoms in a compound
Calculating molecular formula
- Find the empirical formula.
- Find the empirical formula mass.
- Divide the molecular mass by the empirical mass.
- Multiply each subscript by the answer from step 3.