shapes of molecules Flashcards

(34 cards)

1
Q

what is the charge of an electron

A

negative

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2
Q

why do groups of electrons repel each other

A

electrons are negatively charged so they repel each other and they arrange themselves to be as far away from each other in space as possible

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3
Q

why do electron pairs arrange themselves to be as far away from each other as possible

A

to minimise repulsion

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4
Q

what determines the shape of simply covalently bonded substances

A

electron pair repulsion theory

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5
Q

what is the electron pair repulsion pair theory

A

the shape of a molecule is determined by the number of groups of electrons around the central atom. the groups might be a non bonding or bonding pair of electrons. these electron groupings repel to make the angles between them as wide as possible

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6
Q

what are the different repelling effects

A

bonding pair/bonding pair
bonding pair/lone pair
lone pair/lone pair

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7
Q

which pairs cause the most repulsion

A

lone pair/lone pair

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8
Q

what does the straight line in a 3D shape represent

A

represents a bond in the plane of the paper

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9
Q

what does the dashed line in a 3D shape represent

A

a bond in the direction behind the plane of the paper

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10
Q

what do the wedged lines in a 3D shape represent

A

a bond in the direction in front of the plane of the paper

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11
Q

what is the shape and angle of two bonding pairs

A

linear - bond angle 180°

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12
Q

BeF₂ - bond angle and shape

A

consider the central atom - Be is in group 2 so has 2 outer electrons
in bonding each outer atom contributes 1 electron
so fluorine donates 2 electrons altogether
2xF = 2e-
Be = 2e-
4e - = 2 pairs
so LINEAR BOND ANGLE 180°

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13
Q

what is the bond angle and shape of 3 bonded pairs

A

trigonal pair 120°

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14
Q

BF3 bond angle and shape

A

3 x F = 3e-
B is in group 3 so 3e-
3 + 3 = 6e-
6e- = 3 pairs
so TRIGONAL PLANAR 120°

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15
Q

what is the bond angle and shape of 4 bonding pairs

A

tetrahedral 109.5°

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16
Q

CCl4 bond angle and shape

A

4 x Cl = 4e-
C is in group 4 so 4e-
4 + 4 = 8e-
8e- = 4 pairs
TETRAHEDRAL 109.5°

17
Q

what is the bond angle and shape of 5 bonding pairs

A

trigonal bipyramid 120° and 90°

18
Q

PF5 bond angle and shape

A

5 x F = 5e-
P is in group 5 so 5e-
5 + 5 = 10e-
10e- = 5 pairs
TRIGONAL BIPYRAMID 120° and 90°

19
Q

what is the bond angle and shape of 6 bonding pairs

A

octahedral 60°

20
Q

SF6 bond angle and shape

A

6 x F = 6e-
S in group 6 so 6e-
6 + 6 = 12e-
12e- = 6 pairs
OCTAHEDRAL 90°

21
Q

what is the shape and bond angle of 3 bonded pairs and 1 lone pair

A

trigonal pyramid - bond angle 107°

22
Q

NH3 bond angle and shape

A

N = group 5 so 5e-
H x 3 = 3e-
3 + 5 = 8e-
8e- = 4 pairs
there are only 3 electron bonded pairs (4-3=1)
so 1 lone pair
TRIGONAL PYRAMID - 107°

23
Q

what is the shape and bond angle of 2 bonded pairs and 2 lone pairs

24
Q

H₂O shape and bond angle

A

O = group 6 = 6e-
H x 2 = 2e-
8e- = 4 pairs
only 2 bonded pairs so must be 2 lone pairs
BENT 104.5°

25
what do lone pairs give
extra repulsion
26
why are double and triple bonds considered to be single bonds
for repulsion purposes
27
what determines the shape
groups of electrons NOT THE NUMBER OF ELECTRON PAIRS
28
what does it mean by electron density
concentration of electrons in one area
29
how many regions of electron density in C2H4 and why
3 regions of electron density at each carbon - double bond is 1 area - two C-H bonds is 2 areas
30
3 regions of electron density = ..
trigonal bipyramid
31
suggest a value for the HCH bond angle in ethene and explain this in terms of electron pair repulsion theory
3 areas of electron density around the central carbon atom. these areas repel each other and move as far away from each other as possible in order to minimise repulsion. this gives it the shape trigonal bipyramid with bond angle 120°
32
how do we work out the shapes of ions
include any extra electrons that have been added or taken away - add one electron for -ve charge - take away one electron for +ve charge
33
NH4+ bond angle and shape
N = group 5 so 5e- H x 4 = 4 e- 9e- but you take away one e- to give 8e- 8e- = 4 pairs TETRAHEDRAL 109.5°
34
NH2- bond angle and shape
N = 5e- H x 2 = 2e- = 7e- add one electron so 8e- 8e- = 4 pairs 2 are bonded so 2 must be lone BENT 104.5°