Sista kap Flashcards

(21 cards)

1
Q

What is open channel flow?

A

Open-channel flow indicates flow in a channel open to the atmosphere.
It can be natural or man made channels or conduits where the liquid does not fill the conduit completely, and thus there is a free surface

involves liquids exposed to a gas

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2
Q

What is special about the Hydraulic grade line in open channel flow?

A

The HGL coincides with the free surface
(the pressure is constant among the free surface)

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3
Q

What is special about the Hydraulic grade line in open channel flow?

A

The HGL coincides with the free surface
(the pressure is constant among the free surface)

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4
Q

What assumptions do we use in open channel flow?

A

Flow is 1-dimensional
Flow is Steady
Uniform velocity at each cross section

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5
Q

How do you define flow depth?

A

The perpendicular distance measured from the lowest
point of the channel bed to the free surface

h

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6
Q

What is uniform flow?

A

The flow depth remains constant with distance along the channel

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7
Q

When can you expect to have unifiorm flow conditions?

A

Uniform flow can occur only in long and prismatic channels (man made)

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8
Q

What is the difference between gradually varied flows and rapidly varied flows?

A

Changes in the geometry of the riverbed create nonuniform flows
GVF is when the rate of variation of depth with respect to distance is small
RVF is when this rate of variation is large

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9
Q

How can you estimate Q, discharge, in uniform flow conditions?

A

Using the Chezy equation
V = C (R i)^(1/2)

we can create the manning equation
Q = 1/n R^(2/3) A i^(1/2)

n is the roughness coefficient

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10
Q

Write an expression for the total energy in open channel flow conditions, rita bild med

A

H = z + h + v^2 /2g

h = flow depth

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11
Q

Write an expression for the total energy in open channel flow conditions, rita bild med

A

H = z + h + v^2 /2g

h = flow depth

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12
Q

What is the difference between total energy and specific energy?

A

E = h + v^2 /2g = h + [Q/A(h)]^2 /2g
E = H - z
specific energy is the sum of potential and kinetic head

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13
Q

Why does specific energy have a minimal value?

A

If h decreases and tends to zero, then the
velocity head increases and tends to infinity, thus
E = V^2 /2g

If h increases and tends to infinity, then the velocity head decreases and tends to zero; thus E = h

In both extremes E tends to infinity which means that somewhere between the values there exists a minimum.

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14
Q

What is the critical depth?

k

A

Critical depth is the flow depth at which the minimal value for the specific energy is achived.
At the critical depth the following equation satisfied:
Q^2 / g = A^3 / B

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15
Q

What is the alternate depth?

A

For every depth in subcritical flow conditions there are a corresponding depth in supercritical flow conditions.
These two depths are called alternate depths

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16
Q

What is the Froude number (Fr)?

A

Fr = V/sqrt(gh) = inertia force/ gravity force
This is a way to determine whether the flow regime is:
1. critical (Fr =1),
2. sub-critical (Fr<1) or
3. super-critical (Fr>1)

17
Q

What happens when the flow regime change from sub-critical flow to super-critical flow in an open channel?

A

The flow transitions smoothly from a higher flow depth to a lower flow depth

18
Q

What happens when the flow regime change from super-critical flow to sub-critical flow in an open channel?

A

The flow transition happens turbulently through a hydraulic jump

19
Q

What are the assumptions for hydraulic jump?

A

Hydrostatic pressure distribution
Uniform velocity distribution
No air entrainment
Steady flow
Horizontal rectangular channel
Constant channel width, B

20
Q

What defines conjugate depths?

A

The different depths before and after a hydraulic jump.
The conjugate depths have equal momentum fluxes for a given discharge which distinguishes conjugate depths from alternate depths. This allows for new possible calculations.

the flow depth at supercritical and the at subcritical conditions

21
Q

How do you calculate the head loss lost in the hydraulic jump?

A

ΔH = (h2-h1)^3 /(4h1h2)
A large Δh = h2-h1 leads to a big dip in the Energy grade line during the hydraulic jump