Space

Question 1

Intensity

Answer 1

I = P/A
I = Intensity
P = Power
A = Area

Question 2

Intensity

Answer 2

P/4Pid^2
P = Power
d = distance

Question 3

Flux

Answer 3

f = L/4Pid^2
f = Flux
L = Luminosity
d = distance

Question 4

Parsec definition?

Answer 4

A PARSEC is the distance to a star of which has a parallax angle of 1/3600 degrees ( arc second )

Question 5

What is a Cepheid Variable?

Answer 5

Cepheid variables are pulsating stars: their luminosity changes with time due to their instability

Question 6

Weins Law

Answer 6

Ymax T = 2.898x10-3
Y = wavelength
T = temperature in Kelvin

Question 7

Luminosity

Answer 7

L = ōAT^4
L = Luminosity
Ō = Boltzman constant (5.67x10-8)
A = Surface Area
T = Temperature

Question 8

Luminosity

Answer 8

L = 4Piōr^2T^4
L = Luminosity 
Ō = Boltzman Constant (5.67x10-8)
T = Temperature

Question 9

Doppler Effect

Answer 9

•Noise relative to your position.
•As a source moves closer, the distance is compressed, changing the speed.
•Resulting in a higher pitch.
•As a source moves further away, the distance is elongated, changing the speed(slower).
•As a result, the pitch is lower.
THE SAME APPLIES FOR WAVELENGTH WITH LIGHT FROM STARS

Question 10

Redshift

Answer 10

Y(observed) - Y(actual)
———————————
Y(actual)
Y = wavelength

Question 11

Future of the Universe answer (WARNING, VERY FUCKING LONG)

Answer 11

The universe is expanding. The only force we know of permeating the whole universe is gravity. This should slow the expansion. The rate of slowing is linked to the average DENSITY of MATTER in the universe, (Omega Symbol). To get an idea of that, we need to use the distance measured to give volume but also the amount of mass in the universe. It turns out that galaxies don’t have the mass we thought they should. Due to F=mv2/r, the velocities we observe using redshift are too fast if the data we have on distance etc is correct.

Question 12

Perfect response to Trigonometric Parallax

Answer 12

Angle measurements of a stars position against an unmoving background is taken over 6 months. That position would have changed, because of the earths motion around the sun. A right angle triangle is constructed and the distance (d) is calculated using trigonometry and the fact that the Earth-Sun distance, 1 AU, is 1.5x10^11 m:
Draw diagram

d = 1.5x10^11 / tan(p)   
1pc = distance when p = 1/3600 of a degree

Question 13

Lightyear (ly) to Metres (m)

Answer 13

1ly = 9.461x10^15m