Squares And Cubes 8

Question 1

A perfect square cannot end in

Answer 1

2,3,7,8

Question 2

If a no is 5m where m is in the units place and 5 is in the tens place

Answer 2

Then it's square is equal to 
((25 + m) x 100) + m sq
Eg 56 sq         where m is equal to 6
So it's square is (25 + 6) + m
= 31 + 36
=3136

Question 3

(N + 1) sq - n sq is equal to

Answer 3

2n+1

Question 4

Sum of first n odd nos

Answer 4

N sq

Question 5

11 sq = 121
111 sq = 12321
1111 sq = 1234321
111111111 sq = 12345678987654321

Answer 5

Just read the unique pattern

Question 6

Next square number is

Answer 6

M + 2√m + 1

Question 7

If a perfect square ends in 6 then the digit at the tens place would be

Answer 7

Odd

Question 8

A perfect square ending in 5 would be followed by

Answer 8

2

Question 9

In 11 sq sum of digits would be

Answer 9

2 sq and this is a pattern

Question 10

Is 0 a perfect square

Answer 10

Yep

Question 11

Digital sum of a number is

Answer 11

The sum of all digits

Question 12

Digital sum use

Answer 12

It can be used to verify equations that include multiplication.

Question 13

The digital sum of a perfect square would be

Answer 13

0,1,4,7,9

Question 14

A perfect square cannot end in

Answer 14

2,3,7,8

Question 15

11 sq * sum of its digits = 22 sq
111 sq * sum of its digits = 3333 sq
1111 sq * sum of its digits = 4444 sq

Answer 15

Read the pattern

Question 16

Sum of digits in -
11 sq = 2 sq
111 sq = 3 sq
1111 sq = 4 sq

Answer 16

Read

Question 17

Squares of numbers greater than one can be expressed by

Answer 17

Either by
3 or 3 plus 1
OR
4 or 4 plus 1

Question 18

If the number is 5ab then it’s square is

Answer 18

((250 + ab) x 100) + ab sq

Question 19

If a perfect square ends in 1,4,9 then it’s tens digit will be

Answer 19

Even

Question 20

No of prime factors of a perfect square is

Answer 20

Odd in number

Question 21

A perfect square when divided by 3 always leaves remainders

Answer 21

1 or 0

Question 22

Square of any odd number can be expressed as the sum of

Answer 22

2 consecutive numbers

Question 23

To know the no of perfect squares present below a number

Answer 23

Take the approximate square root of the number and leave the decimal place

Question 24

If the number of digits in a perfect square is odd then the number of digits in the square root is

Answer 24

N + 1/ 2 where n stand for the number of digits

Otherwise if it is even then the number of digits is n/2

Question 25

Square of 105

Answer 25

10 x 11 + 5 sq

Question 26

Sum of consecutive square numbers is

Answer 26

n(n+1)(2n+1)/6

Question 27

Square root of 2

Answer 27

1.414

Question 28

Hardy Ramanujan numbers

Answer 28

1729 , 4104, 13832

Question 29

Hardy Ramanujam numbers

Answer 29

Numbers expressed as sum of two positive cubes in two different ways

Question 30

Smallest hardy Ramanujam

Answer 30

1729