Step growth polymerisation Flashcards

(18 cards)

1
Q

the prime difference that distinguishes step growth and chain growth polymerisation

A

reaction mechanism

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2
Q

during which stage are monomers gone

A

dimer, trimer

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3
Q

define conversion rate (p)

A

how many monomers have reacted to form polymers

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4
Q

draw the draw of Mn against conversion rate

q: how is Mn at 50% conversion rate?

A

very low Molecular weight

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5
Q

what are the three types of step growth polymerisation?

A

Poly-condensation

Poly-addition

Addition Condensation

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6
Q

which type of step growth polymerisation yields a small molecule

A

Poly-condensation
Addition Condensation

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7
Q

monomer type for step growth polym.

A

bifunctional
A-R-B or A-R’-A + B-R”-B
where A can react with B but not another A

A-R-B + A-R-B → A-[- R—BA—R-]-B
A-R’-A + B-R”-B → A-[-R’—AB—R”-]-B

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8
Q

3 examples under polycondensation

A
  1. polyester
  2. polycarbonate
  3. Polyamide
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9
Q

what are the two ways to make a polyester?

A

Reaction of hydroxyl (-OH) and carboxylic (-COOH) group

Reaction of hydroxyl (-OH) and ester (-COOR’) groups

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10
Q

write down a general equation for hydroxy and carboxylic group using the two types of bifunctional monomers

Q: what type of reaction is taking place for A-R-B

A

self-condensation ( A reaction where identical molecules (monomers) combine to form larger molecules (oligomers or polymers), releasing a small molecule like water or methanol as a byproduct.)

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11
Q

write down a general equation for hydroxy and ester group

Q: what type of reaction is taking place

A

transesterification(chemical reaction where an ester reacts with an alcohol, acid, or another ester, resulting in the exchange of the alkoxy group)

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12
Q

an example equation for the formation of polycarbonate

Q: functional group of carbonate and ester

A

carbonate: -O-CO-O-
ester: -CO-O-

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13
Q

two ways to make a polyamide

Q: is self condensation possible here

A
  1. amino (-NH2) and diacid chloride groups
  2. amino and carboxylic group

YES

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14
Q

two important examples of polyamide

A

Nylon 6-6
Kevlar

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15
Q

Nylon 6-6

  1. what are the two monomers?
  2. condition
  3. melting temp

Kevlar
1. condition
2. intermolecular force

A
  1. adipic acid and 1,6-hexanediamine
  2. interfacial polycondensation
  3. 200-280C
  4. interfacial polycondensation
  5. hydrogen bonds between the chains
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16
Q

how to achieve high molecular weight in polycondensation?

A
  1. monomers must be of high purity
  2. functionality >= 2 for each monomer unit
  3. the two mutually reactive functional groups are in exactly equal molar quantity(stoichiometric balance).
    If one of the group is in excess that group will remain unreacted at the chain ends resulting low molecular weight polymers( only oligomers present)

two means to achieve stoichiometric balance: high purity of monomers and equimolar monomer ratio

17
Q

explain nd derive the carother’s equation

18
Q

Mn Mw and PI based on carothers eqn