test 7 Flashcards
(40 cards)
Three renal processes
Glomerular filtration
Tubular reabsorption
Tubular secretion
Excretion =
Filtration – Reabsorption +
Secretion
Filtration only
Excretion = Filtration
Waste products (creatinine)
Filtration and partial reabsorption
Excretion = Filtration – Reabsorption
Electrolytes (sodium, chloride)
Filtration and complete reabsorption
Nothing excreted
Nutritional substances (amino acids, glucose)
Filtration and secretion
Excretion = Filtration + Secretion (no reabsorption)
Organic acids & bases
Excretion Rate
Filtration, reabsorption, & secretion closely regulated based on needs of the body
Increased sodium -> increased filtration -> decreased reabsorption = increased excretion
Most substances see a high filtration AND a high reabsorption rate
Small changes in filtration and/or reabsorption will produced significant changes in excretion rate
Why High Filtration Rate??
Allows rapid removal of waste products
These substances depend on filtration for adequate removal (i.e. not reabsorbed or secreted)
Allows multiple passes of the blood volume through the kidneys each day
GFR = 180 L/day versus 3 to 4 liters of plasma volume
Allows complete filtering of plasma volume 60 times each day
Allows rapid and precise control of body fluid volume and composition
Renal blood flow (RBF) amount
22% of total cardiac output
Glomerular Filtration Rate (GFR) amount
180 Liters/day OR 125 mls/minute
Filtration Fraction =
GFR / Renal Plasma Flow
Each minute how much of the plasma flowing through the kidneys is filtered (i.e. enters renal tubules)?
20% of the plasma
percentage of plasma in the blood
RBF x (1 - HCT) = Renal Plasma Flow
If GFR goes up with no change in plasma flow
Filtration fraction is going up
Normal reabsorption ≈
178.5 Liters/day (124 mls/minute)
Normal urine output ≈ (L/day)
180 – 178.5 ≈ 1.5 Liters/day
Normal urine output ≈ (mls/min)
125 -124 ≈ 1 mls/minute
Small Change in GFR Could Produce Large Change in what?
Urine output
10% increase in GFR would produce a 13-fold increase in urine output
Three major layers (not 2) of the Glomerular Capillary
Membrane
Endothelial cell layer
Basement membrane layer
Epithelial cell layer
Glomerular Capillary Membrane
Filters significantly more volume than normal capillaries – Thicker but more porous
Endothelial layer perforated by thousands of fenestrations (small holes)
Protein passage prevented by negative charge on surface of endothelial cells
Basement membrane allows movement of water and small solutes
Protein passage prevented by proteoglycan mesh and negative charge
Epithelial layer not continuous
Slit pores present between adjacent podocytes – allow free movement of water and small solutes
Negative charge of surrounding epithelial cells hinders protein filtration
Overall pore size approximately 8 nanometers (80 angstroms)
Filterability of Solute
Filterability of 1.0 means freely filtered (at the same rate as water)
Concentration in filtrate = plasma concentration
Filterability of 0.75 means filtered 75% as quickly as water (more water than solute is filtered
Filtrate concentration < plasma concentration
Albumin smaller than pore size (6 nm vs. 8 nm) but negative charge prevents passage
Myoglobin (not usually found in blood) filterability
if plasma concentration was 54 ug/dL, what is the glomerular filtrate
filterabilty = .75
54(.75)= 40.5 ug/dL
-more water filtered at a faster rate
Albumin filterability if plasma concentration was 5 gm/dL, what is the glomerular filtrate
filterability = .005 5(.005) = .025 gm/dL
Filterability – Effect of Charge
-positively charged ions will be favorably filtered
-a negative charge filterability decreases significantly
In some renal diseases, the negative charge of basement membrane is lost before any histological changes are seen – appearance of albumin
in urine is an early indicator