topic 1: principles of chemistry Flashcards

(96 cards)

1
Q

states of matter

A

solid liquid gas

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2
Q

possible state changes

A

boiling
condensing
sublimation
disposition
melting
freezing

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3
Q

diffusion

A

movement of particles through a liquid/gas from a high concentration to a low concentration

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4
Q

potassium manganate and water (diffusion)

A

potassium manganate (vii) is bright purple

in a beaker of water, add potassium manganate

it efficiently portrays diffusion as the purple colour slowly spreads out to fill the beaker

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5
Q

bromine gas and air (diffusion)

A

bromine is a brown, strongly smelling gas

fill half a gas jar of bromine gas and the other half filled with air and separate the gases using a gas plate. once plate is removed you see bromine gas diffusing through the air

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6
Q

ammonia and hydrogen chloride (diffusion)

A

ammonia (NH3) gives off ammonia gas. hydrochloric acid (HCl) gives off hydrogen chloride gas

in a glass tube, insert cotton wool soaked in aqueous ammonia, another in hydrochloric acid

both gases are suppose to diffuse from one end to another to form ammonium chloride

observe that the ring doesnt form in the middle, but it forms nearer to the hydrochloric acid

this is because ammonia has a smaller and lighter particle meaning that it diffuses through the air quicker

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7
Q

solution

A

mixture of a solute and a solvent

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8
Q

solute

A

substance being dissolved

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9
Q

solvent

A

liquid its dissolving into

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10
Q

saturated solution

A

a solution where the maximum amount of solute has been dissolved, so no more solute will dissolve in the solution AT A SPECIFIC TEMPERATURE

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11
Q

solubility

A

a measure of how much solute will dissolve in a solute will dissolve in a solvent per 100g of solvent

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12
Q

investigate how temperature affects solubility

A

using ammonium chloride

make a saturated solution by using an excess of ammonium chloride to 10cm^3 of water in a boiling tube + stir

place the boiling tube in a water bath set to 25°C

check that all the excess solid has sunk to the bottom and check that the solution has reached 25°C

weigh an empty evaporating basin. pour some solution into the basin, making sure not to pour any undissolved solute

gently heat with a bunsen burner to remove all water

youre left with pure ammonium chloride once water evaporates. reweigh the evaporating basin and its contents

repeat experiment with differing temperatures

calculate solubility

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12
Q

solubility graph

A

y axis solubility
x axis temperature

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12
Q

solubility formula with units!!!!!

A

solubility (g per 100g of solvent) = mass of solid (g) / mass of water removed (g)

^ answer is then multiplied by 100

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13
Q

atoms contain

A

protons
neutrons
electrons

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14
Q

mass charge location (protons)

A

mass of 1
+1 charge
nucleus

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15
Q

mass charge location (neutrons)

A

mass of 1
no charge
nucleus

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16
Q

mass charge location (electrons)

A

mass of 1/1836
-1 charge
moves around nucleus in energy levels called shells

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17
Q

molecules

A

atoms joined together

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18
Q

mass number

A

neutrons + protons

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19
Q

isotope

A

different forms of the same element with the same number of protons but different numbers of neutrons

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20
Q

atomic number

A

number of protons (+ electrons)

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21
Q

relative atomic mass

A

relative atomic mass (Ar) = (relative mass x percentage abundance) + (relative mass2 x percentage abundance 2)/100

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22
Q

compounds

A

two or more different elements chemically bonded

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23
elements
consists of one type of atom only
24
mixture
no chemical bonds between the different components in a mixture unlike a compound
25
pure substance
completely made up of a single element or compound has a specific melting/boiling point unpure stuff boils gradually over a range of temperature
26
filtration
separates an insoluble solid from a liquid put some filter paper into a funnel and your mixture into it. the liquid part of the mixture runs though the paper leaving behind a solid resid
27
crystallisation
separates a soluble solid from a solution pour the mixture into an evaporating dish and gently heat the solution once some of the water has evaporated/you see crystals forming, remove the dish from the heat and leave the solution to cool the salt should form crystals as it becomes insoluble in the cold, more concentrated solution filter the crystals out and leave in a warm place to dry (or a drying oven)
28
how to separate rock salt
rock salts simply consist of salt and sand grind up the rock salt with a pestle and mortar dissolve in a beaker and stir filter through filter paper in a funnel to get rid of insoluble sand crystallisation!!!
28
rf value
distance travelled by solute/distance travelled by solvent
28
chromatography
separates out mixtures draw a line near the bottom of a sheet of filter paper using a pencil add spots of different inks to the line at regular intervals + loosely roll up and put it in a beaker of solvent e.g water or ethanol ensuring the level is below the baseline place a lid to prevent the solvent from evaporating the solvent will seep up the paper to carry the inks with it when the solvent has nearly reached the top of the paper, take the paper out of the paper and leave it to dry
29
stationary phase
provides surface for the solvent+inks to travel up
30
mobile phase
the solvent that travels
31
simple distillation
separates solutions heat the solution. the one with the lower boiling point evaporates the vapour is then cooled, condenses, and is collected the rest of the solution is left behind the flask
32
why simple distillation sucks ass
can only use it to separate things with very different boiling points
33
fractional distillation
used to separate a mixture of liquids put the mixture in a flask and stick a fractioning column on top. then heat it the different liquids all have different boiling points, so they are able to evaporate at different temperatures the liquid with the lowest point evaporates first, reaching the top of the column. it will then condensed to be collected all the other liquids will also evaporate, however they will only manage to make it halfway before condensing since the top is cool repeat with different temperatures
34
what do periods and groups portray
periods: amount of shells groups: amount of electrons in the outer shell
35
non metals
more located on the right poor conductors of electricity non metal oxides are acidic. they neutralise bases. they dissolve in water to form solutions with a pH less than 7
36
metals
more located on the left conduct electricity as they allow charge to pass through them easily basic - they neutralise acids. dissolvable metal oxides form solutions with a pH more than 7
37
group 0 (noble gases)
inert, colourless gas they contain 8 electrons on the outer shell, meaning that they are stable
38
cations
positive ions formed when atoms lose electrons
38
anions
negative ions formed when atoms gain electrons
38
ions
charged particles
38
ionic bonding
strong, electrostatic attractions the metal atom loses electrons to form a positive ion (cation) the non metal atom gains electrons to form a negative ion (anion)
39
Ag ion (silver)
(+)
39
Cu ion (copper)
(+2)
40
Fe ion (II) (iron)
(+2)
41
Fe ion (III) (iron)
(+3)
42
Pb ion (lead)
(+2)
43
Zn ion (zinc)
(+2)
44
H ion (hydrogen)
+
45
OH ion (hydroxide)
-
46
NH4 ion (ammonium)
+
47
CO3 ion (carbonate)
-2
48
NO3 ion (nitrate)
-
49
SO4 ion (sulfate)
-2
50
giant ionic structures
ions are held together in a closely packed 3d lattice arrangement by the attraction between oppositely charged ions electrostatic attraction is supa strong high melting + boiling point due to the high amount of energy to overcome the attraction can conduct electricity only when melted/dissolved
51
covalent bonding
these bonds are formed through sharing pairs of electrons with other atoms strong electrostatic attraction between the negatively charged shared electrons and the positively charged nuclei of the atoms involved
52
simple molecules
strong covalent bonds which lead to weak intermolecular forces low melting and boiling points
53
giant covalent structures
dont conduct electricity except graphite insoluble bonded with strong covalent bonds requires a lot of energy to break the bonds due to the number of them, meaning a high melting+boiling point
54
diamond
made up of a network of carbon atoms that form four covalent bonds these strong covalent bonds take lots of energy to break, so diamond has a high melting point holds it in a rigid lattice structure, making diamond hard does not conduct electricity because there is no free electrons or ions
54
fullerene
simple molecular substance shaped as a hollow sphere made up of 60 carbon atoms held together by intermolecular forces so they slide over each other. this makes it soft has one delocalised electron that cant move, making it a poor conductor of electricity
54
graphite
forms three covalent bonds, creating layers of carbon atoms held weakly by intermolecular forces, so the layers slide over each other. this makes it soft and slippy high melting point due to strong covalent bonds delocalised electron that is free to move. this means it can conduct electricity
55
relative formula mass (Mr)
all the relative atomic masses of the elements it contains added together
55
mols formula
mass = mr x mol
55
how to calculate the amount of product from a mass of reactant
using the provided Ar, calculate the Mr of the reactant and the products calculate the number of mols of the substance that has a mass provided look at the ratio of the moles in the equation calculate the mass using the ratio of the mols
55
percentage yield
actual yield (g) / theoretical yield (g) x 100
56
why is a percentage yield never 100%
a reaction may not go to completion some product may be lost during transfer or purification. side reactions can occur, forming byproducts. reactants may not be pure. reactions may be reversible.
57
empirical formula
smallest whole number ratio of atoms in a compounds
58
how to calculate the empirical formula
find the mols of each element by dividing each mass by the relative atomic mass for that particular element divide those numbers by the smallest number of mols, creating a ratio
59
find empirical formula through combustion (practical)
get a crucible and heat until its red hot. this ensures that it is clean with 0 traces of oil or water leave the crucible to cool then weigh it along with the lid add some clean magnesium ribbon to the crucible. reweigh the crucible, lid and magnesium ribbon heat the crucible containing the magnesium. put the lid to stop bits of solid from escaping, but leave a small gap enabling oxygen to enter the crucible for 10 minutes, or until the ribbon turns white allow the crucible to cool and reweigh with the lid and contents. find the mass by taking this away from the mass of the initial lid and crucible
60
find empirical formula through reduction (practical)
place a rubber bung with a hole in the middle into a test tube with a small hole in the end and weigh them using a mass balance take the bung out of the test tube and spread out a small amount of copper (II) oxide in the middle of the tube reinsert the bung and weigh the test tube again. expel the air from the test tube by gently turning on the gas. after like 5 seconds light the gas by holding a burning splint next to the hole in the end of the test tube. you can control the size of the flame by changing the amount of gas thats flowing through the test tube use a bunsen burner to heat the copper (II) oxide for about 10 minutes (or until the black turns into a brownish pink colour) turn off the bunsen burner and leave it to cool weight the test tube with the bung and its contents
61
anhydrous salt
when a salt doesnt contain any water of crystallisation
62
hydrated salt
when salt contains water of crystallisation
63
how to calculate the amount of water of crystallisation a salt contains
work out the mass of both substances by subtracting the crucible mass calculate the number of mols of water lost by taking away the anhydrous mass of the hydrated one + calculating the mols calculate the number of mols anhydrous salt has made work out the ratio of anhydrous salt to mols of water x has to be a whole number meaning that some errors are expected in an experiment. round it to the nearest whole number
64
electric current
flow of electrons or ions
65
metallic bonding
where metals have a giant structure of positive ions surrounded by delocalised electrons
66
malleable
the layers of ions in a metal can slide over each other, making metals malleable - this means that they can be hammered or rolled into flat sheets
67
ionic compounds + their conductivity
generally they cant conduct electricity because the ions cant move around when ionic compounds are dissolved /molten the ions separate and are able to move + conduct electricity
68
why are metals good conductors
metals contain delocalised electrons, meaning that they are free to move through the structure because they can move, this also provides as efficient means of energy transfer, making metals a good conductor
69
concentration
concentration (mol/dm^3) = number of mols (mol) / volume of solution (dm^3)
70
mols/dm^3 -> g/dm^3
work out the relative formula mass + mols/dm^3 of the chemical find the mass to find out the g/dm^3!!!
71
avogadros law
one mol of any gas always occupies 24dm^3 at room temperature and pressure (RTP)
72
RTP
room temperature = 20°C pressure = 1 atmosphere
73
volume (dm^3) formula
moles of gas x 24
74
calculate volumes in reactions (masses provided)
write out the balanced formula work out the relative formula mass of the substance with the provided mass + then calculate the moles look at the ratio of the moles in the equation calculate the volume using the ratio of the mols + formula for volume
75
electrolysis
the breaking down of substances using electricity
76
electrolyte
a molten/dissolved ionic compound
77
electrolysis oxidation + reduction
the positive ions (cations) in the electrolyte move towards the cathode (negative electrode) and are reduced the negative ions (anions) in the electrolyte move towards the anode (positive electrode) and are oxidised as the ions gain/lose electrons they form the uncharged substances and are discharged from the electrolyte
78
ionic half equations
show how electrons are transferred during reactions put one of the things being oxidised/reduced on one side of an arrow, and the thing it gets oxidised/reduced to on the other balance up the number of atoms like a normal equation add the electrons to balance out the charges
79
why can ionic compounds be electrolysed
they can be electrolysed due to the ions being free to move + are usually broken up into their elements
80
electrolysis of molten lead bromide
the positive Pb+2 ions are attracted to the negative cathode. at the cathode, a lead ion accepts 2 electrons and is reduced to a lead atom (Pb^2+ + 2e- -> Pb) the negative Br- ions are attracted to the positive anode. at the anode, a bromine ion loses 1 electron and is oxidised to a bromide molecule (2Br- -> Br2 + 2e-) the electrodes are made of an inert material so they dont take part in the reaction
81
electrochemical cell
they are circuits made up of the anode, cathode, electrolyte, a power source and the wires that connect the two electrodes
82
how to set up an electrochemical cell
get two inert electrodes, e.g graphite or platinum clean the surface of the electrodes using sandpaper + from now on, handle them with care to avoid transferring grease onto the strips place both electrodes into a beaker filled with your electrolyte connect the electrodes to a power supply using crocodile clips and wires when you turn the power supply on, a current will flow through the cell
83
electrolysis in aqueous solutions
in aqueous solutions, as well as the ions from the ionic compound, there will be hydrogen ions and hydroxide ions from the water at the cathode, if H+ ions and metal ions are present, hydrogen gas will be produced if the metal is more reactive than hydrogen (e.g sodium). if not (e.g copper + silver), then a solid layer of the pure metal will be produced instead at the anode, if OH- and halide ions (Cl-, Br-, I-) are present, molecules of chlorine, bromine or iodine will be formed. if no halide ions are present, then oxygen is formed instead