topic 2 - bonding Flashcards
(58 cards)
Ammonia and boron trifluoride react to form a compound NH3BF3 which contains a dative
covalent bond. Each of the molecules, NH3 and BF3, has a different feature of its electronic
structure that allows this to happen. Use these two different features to explain how a dative
covalent bond is formed.
(2)
- donation of lone pair of electrons from nitrogen / lone pair from ammonia
- to the boron atom which is electron deficient
State what is meant by the term electronegativity and hence explain the polarity, if any, of
the bonds in chlorine trifluoride, ClF3.
(3)
- electronegativity is the relative ability of an atom to attract the bonding electrons in a covalent bond
- flouring is more electronegative than chlorine/flourine is the most electronegative
- so flourine is delta negative and chlorine is delta positive
Explain why the melting temperature of silicon(IV) oxide is much higher than that of iodine,
even though the bonding in both is covalent.
(3)
- silicon(IV) oxide is a giant structure therefore contains many strong covalent bonds
- iodine only has weak intermolecular/ london forces
- more energy is required to break the stronger bonds in silicon(IV) oxide hence higher melting temperature
This is a question about water.
Explain why both water and carbon dioxide molecules have polar bonds but only
water is a polar molecule.
- oxygen is more electronegative than hydrogen and carbon
- which results in a polar bond with oxygen delta negative so carbon and hydrogen hydrogen delta positive
- carbon dioxide is a symmetrical/linear molecule and so the dipole moments cancel
- the lone pairs of electrons of oxygen and the shape of the water molecules mean that the dipole moments do not cancel
Explain, in terms of the structure and bonding of each element, the difference between these
values.
(3)
- silicon is a giant covalent structure and contains covalent bonds
- chlorine is a simple molecular structure and contains london forces
- covalent bonds in silicon are stronger than london forces in chlorine and covalent bonds take more energy to break than london forces
This question is about crystalline solids.
Iodine and diamond are crystalline solids at room temperature.
Explain why diamond has a much higher melting temperature than iodine.
(5)
- iodine is a simple molecular
- diamond is a giant covalent lattice structure with 4 covalent bonds per carbon atom
- iodine molecules are held together by weak london forces
- carbon atoms in diamond are held together by strong covalent bonds
- strong covalent bonds require more energy to break them than intermolecular forces
Boron and aluminium are in the same group of the Periodic Table. Both form compounds
with chlorine and with fluorine.
Aluminium fluoride and aluminium chloride are both crystalline solids at room temperature.
Aluminium fluoride sublimes to form a gas at 1291°C (1564 K), whilst aluminium chloride
sublimes at 178°C (451 K).
Use the Pauling electronegativity values in the Data Booklet to explain these differences in
sublimation temperature.
(6)
- aluminium and chlorine electronegativity difference 1.5 AND aluminimum and flourine electronegativity difference 2.5
- aluminium chloride mostly covalent small molecule
- aluminium flouride bonds are more polar
- aluminium chloride is molecular so weaker london forces
- aluminium flouride is a giant structure which has stronger electrostatic forces of attraction between the ions
- more energy needed to break the stronger bonds to cause sublimation in aluminium flouride
This is a question about water.
Water might be expected to have a lower boiling temperature than hydrogen sulfide
but it actually has a higher boiling temperature.
Comment on this statement by referring to the intermolecular forces in both these
substances.
A detailed description of how the intermolecular forces arise is not required.
(4)
- a lower boiling point is expected because water has fewer electrons than hydrogen sulfide
- water has weaker, less london forces
- a higher boiling point occurs because water has hydrogen bonding
- hydrogen bonding is stronger than london forces and requires more energy to break and results in a higher boiling temperature
This question is about compounds of Group 5 elements.
Nitrogen trichloride, NCl3, has a boiling temperature of 344 K, and
nitrogen trifluoride, NF3, has a boiling temperature of 144 K.
Explain this difference in boiling temperatures, by referring to all the
intermolecular forces present. (5)
- london forces are greater in NCl3
- as NCl3 has more electrons
- permanent dipole-dipole forces stronger in NF3 than NCl3
- as F is more electronegative than Cl
- london forces are more significant / more energy required to break the intermolecular forces between the NCl3 molecules than NF3
Explain why the boiling temperatures increase from chlorine to iodine.
(2)
- from chlorine to iodine, the number of electrons increases
- so the strength of the london / instantaneous dipole-dipole forces and more energy is needed to separate the molecules
The compounds hydrogen fluoride, water and methane, all have simple molecular
structures, but they have significantly different boiling temperatures.
Discuss the reasons for the differences in the boiling temperatures of the three compounds,
using the data in the table and the Pauling electronegativity values in the Data Booklet. (6)
- same number of electrons so similar london forces
-large electronegativity differences in HF and H2O and small in CH4 - only weak london forces in CH4
- hydrogen bonding in both HF and H2O but not CH4
- more hydrogen bonds/twice as many hydrogen bonds in H2O than in HF
- more energy needed to break stronger intermolecular forces
Explain why methanol and water are ‘soluble in all proportions’.
You must include a diagram in your answer.
(3)
- methanol hydrogen bonds to water
- at least one lone pair on an oxygen atom and an approximate 180 degrees OHO bond angle
- strength of all intermolecular forces between methanol and water is approximately the same as those in water and methanol
or strength/extent of H-bonding between methanol and water is the same
This is a question about hydrocarbons.
Explain why 2,2-dimethylpropane has a much lower boiling temperature than its isomer
pentane.
Detailed descriptions of the forces involved are not required.
(2)
- branching results in fewer/weaker london forces
- due to less surface area / points of contact
This question is about some halogens and their compounds.
The intermolecular attractions between halogen molecules are London forces.
(i) Describe how London forces form between halogen molecules.
(3)
setting up of the dipole
- uneven distribution of electrons
type of dipole
- results in an instantaneous dipole in the first molecule
induction od a second dipole
- causes/induces a second dipole on other molecule
Methanol, CH3OH, is miscible with water in all proportions.
Sodium chloride is much less soluble in methanol than in water.
Explain these statements using your knowledge of the interactions between solutes and
solvents.
You must use diagrams to illustrate your answers.
(6)
- hydrogen bonding between water/solvent and methanol/solvent
- suitable diagram
- same strength/comparable to bonding in either component on its own OR hydrogen bonding is present in methanol and in water
- hydration of Na+ and Cl-
- suitable diagram of at least one ion
- the ionic bonding is stronger than the bonding between sodium and/or chloride ions and methanol
Explain why hydrogen bonding causes ice to be less dense than liquid water.
(2)
- more open /more space between molecules making it less dense
- due to 3D lattice/ ring structure on ice
- hydrogen bonds longer than covalent bonds
In Stage 1, phenol is nitrated using dilute nitric acid.
The nitration of benzene requires concentrated nitric acid at 55°C with a catalyst of
concentrated sulfuric acid.
Both these reactions are electrophilic substitution.
(i) Explain why phenol can be nitrated using milder conditions than benzene.
(2)
- the electron density of the benzene ring is greater in phenol than in benzene
- because the lone pair of electrons on oxygen and overlaps with the pi cloud/ delocalised system
A mixture of 2-nitrophenol and 4-nitrophenol is produced in Stage 1.
They are separated by steam distillation.
The boiling temperature of 2-nitrophenol is 215°C and that of 4-nitrophenol is 279°C.
Explain, in terms of intermolecular forces, why 4-nitrophenol has a higher boiling
temperature than 2-nitrophenol.
You may include a diagram in your answer.
(2)
- they both form hydrogen bonds
- in 4-nitrophenol the hydrogen bonds join molecules in a straight chain OR 2-nitrophenol forms intermolecular hydrogen bonds so fewer intermolecular hydrogen bonds
This question is about chlorine and its compounds.
In many swimming pools, sodium chlorate(I) has replaced chlorine gas as a disinfectant.
Sodium chlorate(I) is an ionic compound. It is very soluble in water.
(i) Describe, using diagrams to illustrate your answer, the interactions between
each of the ions and the solvent when sodium chlorate(I) dissolves in water.
(2)
- diagram showing both Na+ ion and ClO- ion surrounded by water molecules/solvated
- correct orientation of the water molecules around both ions with a relevant dipole shown on at least one water molecule for each ion
Ethanol is very soluble in water whereas chloroethane is almost insoluble in water.
Explain this observation by comparing the types of intermolecular forces formed
by each of these molecules with water.
(2)
- ethanol forms hydrogen bonds with water
- chloroethane forms permanent dipole-dipole attractions and london forces with water
Nitrogen forms several hydrides. In addition to ammonia, NH3, it forms hydrazine, N2H4, in
which the two nitrogen atoms are covalently bonded together.
Hydrazine is very soluble in water.
Explain, using a labelled diagram and naming the relevant intermolecular interactions, why
hydrazine is very soluble in water.
(3)
- hydrogen bonds in water , hydrazine
- diagram showing hydrogen bond between the correct atoms
- lone pair on either nitrogen or oxygen and bond angle shown on diagrams as approximately 180 degrees.
This question is about dissolving different compounds.
The solubility of two compounds in different solvents was investigated.
A summary of the findings is shown.
Explain the findings of the investigation by considering the interactions between the
compounds and each of the solvents.
(6)
- 2-methylpentane is insoluble in water as it cannot hydrogen bond to water as non of the hydrogen atoms are electronegative
- 2-methylpentane is soluble in hexane as london forces in both compounds are similar in strength and size
- so resultant force in mixture are similar in magnitude to those in each liquid
- potassium bromide is soluble in water as its ions are hydrated when dissolved
- the enthalpy change of hydration is greater than the energy needed to break apart the lattice
- potassium bromide is insoluble in hexane as any london forces that form between hexane would be smaller in magnitude than the forces between the atoms
This question is about structure and bonding.
Water has two significant anomalous properties:
* it has a higher melting temperature than hydrogen sulfide, H2S, even though it has
fewer electrons in its molecules
* the density of ice at 0 °C is less than that of water at 0 °C.
Explain these properties.
You should include a labelled diagram to show the intermolecular forces between two
molecules of water.
(6)
- lone pair and dipole lone pair on oxygen in hydrogen bons and dipole shown with delta + on any one H and delta - on any one O
- shape hydrogen bond labelled / shown as a dotted line and hydrogfen bonds shows as approximately linearor O-H-O bond angle labelled as 180 degrees
- london forces
hydrogen sulfide has stronger london forces because it has more electrons - comparison
hydrogen bonding is stronger than london forces and requires more energy to overcome - ice at 0 degrees
water molecules are arranged in a lattice or hydrogen bonds are longer than covalent bonds - water at 0 degrees
water molecules get closer/have less distance between them so more molecules in the same volume
This question is about catalytic converters.
Catalytic converters contain metals such as platinum.
Describe the bonding in platinum.
You may include a diagram in your answer.
(2)
- regular arrangement / lattice of positive ions/metal cations in a sea of delocalised electrons
- metallic bonding is the strong electrostatic force of attracted between cations and electrons