Topic 24: Aqueous Chemistry Flashcards
(39 cards)
Hexaaqua complexes
6 water molecules acting as ligands around a transition metal
Fe^2+ and Fe^3+ hexaaqua solutions acidity difference why?
Fe^3+ much more acidic than Fe^2+
3+ smaller and higher charged than 2+ so more polarising. Strongly attracts electrons from O weakening the OH bonds which will release a H+ making it acidic.
Fe^3+ in water equation
Hydrolysis
[Fe(H2O)6]^3+(aq) <===> [Fe(H2O)5(OH)]^2+ + H+
M3+ adding OH- equations
[M(H2O)6]^3+(aq) + OH-(aq) —> [M(H2O)5(OH)]^2+(aq) + H2O(l)
[M(H2O)5(OH)]^2+(aq)
+ OH-(aq) —> [M(H2O)4(OH)2]^+(aq) + H2O(l)
[M(H2O)4(OH)2]^2+(aq) + OH-(aq) —> M(H2O)3(OH)3(s) + H2O(l)
Mg2+ adding OH- equations
[M(H2O)6]^2+(aq) + OH-(aq) —> [M(H2O)5(OH)]^+(aq) + H2O(l)
[M(H2O)5(OH)]^+(aq)
+ OH-(aq) —> M(H2O)4(OH)2(s) + H2O(l)
M^2+ with ammonia full eq’n
[M(H2O)6]^2+(aq) + 2NH3 —> M(H2O)4(OH)2(s) + 2NH4+
M^3+ with ammonia full eq’n
[M(H2O)6]^3+(aq) + 3NH3 —> M(H2O)3(OH)3(s) + 3NH4+
Fe^3+ and CO3^2-
DOESN’T FORM Fe₂(CO₃)₃ - doesn’t exsist???
Fe^3+ and CO3^2- overall equation
2[Fe(H2O)6]^+3(aq) + 3CO3^2-(aq) —> 2Fe(H2O)3(OH)3 + 3CO2(g) + 3H2O(l)
Fe^3+ and CO3^2- overall equation DERVIVED???
Fe^2+ and CO3^2- overall equation
[Fe(H2O)6]^+2(aq) + CO3^2-(aq) —> FeCO3(s) + 6H2O(l)
Fe^3+ in water colour
purple solution
may look yellow-brown due to some
[Fe(H2O)5(OH)]2+(aq)
Fe^2+ in water colour
green solution
Fe^2+ in OH- colour and in exess
green ppt goes brown on standing in
air
nvc in excess
Fe^3+ in OH- colour and in excess
brown ppt (ppt may look
orange-brown)
nvc in excess
Al3+ in water colour
[Al(H2O)6]^3+(aq)
colourless solution
Chelation
Water ligands being replaces by bidentate or multidentate ligands
Ammonia replacing water ligands in M2+
One at a time
[M(H2O)6]^2+ + NH3 <===> [M(NH3)(H2O)5]^2+ + H2O
AND SO ON AND SO ON LIKE 6 TIMES!!!!
Overall:
[M(H2O)6]^+2 + 6NH3 <===> [M(NH3)6]^2+ + 6H2O
What else could happen during NH3 substitution?
Ammonia is a base so in solution forms OH- ppt may form and redissolve
[M(H2O)6]^2+(aq) + 2OH-(aq) —> M(H2O)4(OH)2(s) + 2H2O(l)
M(H2O)4(OH)2(s) + 6NH3(aq) <===> [M(NH3)6]^2+(aq) + 4H2O(l) + 2OH-(aq)
hexaaqua complex of Cu2+ with excess NH3 equation
[Cu(H2O)6]2+ + 4NH3 <===> [Cu(NH3)4(H2O)2]^2+ + 4H2O
hexaaqua complex of Cu2+ with excess NH3 explanation
Ammonia acts as a base removing protons from 2 of the water ligands producing ppt
Then the ppt dissolves as the ammonia has replaced both OH- and two H2O ligands
hexaaqua complex of Cu2+ with little NH3 equation
[Cu(H2O)6]2+ + 2NH3 —> Cu(H2O)4(OH)2(s) + 2NH4+
hexaaqua complex of Cu2+ with little NH3 colour
Blue ppt
hexaaqua complex of Cu2+ with excess NH3 colour
Deep blue solution