Topic 5 - Physical Chemistry and Transition Elements Flashcards

(627 cards)

1
Q

Kc =

A

[products] / [reactants]

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2
Q

[ ] =

A

equilibrium concentrations in moldm^-3

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3
Q

If the equation is aA + bB cC + dD, what is the Kc equation?

A

Kc = ([C]c x [D]d) / ([A]a x [B}b)

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4
Q

What is Kc?

A

Kc is a constant but is temperature dependent

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5
Q

How does temp do to Kc on an exothermic forward reaction?

A

Temp increase so concentration of reactants increase and products decrease so Kc drops
Temp decrease so concentration of reactants decreases and products increases so Kc rises

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6
Q

Size of Kc meaning?

A

Large Kc, equilibrium on the right

Small Kc, equilibrium on the left

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7
Q

If an equilibrium mixture is homogeneous, what does this mean? and what happens to Kc?

A

If an equilibrium mixture is homogeneous (all the reactants and products are in the same physical state) all the species go into the Kc expression

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8
Q

If an equilibrium mixture is heterogeneous, what does this mean? and what happens to Kc?

A

If an equilibrium mixture is heterogeneous (reactants and products are in different physical states) only gaseous and aqueous species go into the Kc expression

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9
Q

When writing Kc expressions for heterogeneous equilibria we leave out any species which are solid or liquid as …

A

… Their concentrations are essentially constant

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10
Q

For gaseous equilibria it is more convenient to use ______ ________ of reactants and products instead of equilibrium concentration in moldm-3

A

partial pressures

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11
Q

if aA(g) + bB(g) cC(g) + dD(g), then Kp =

A

((pC)c x (pD)d) / ((pA)a x (pB)b)

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12
Q

If N2(g) + 3H2)g) 2NH3(g), then Kp =

A

Kp = (pNH3)2 / ((pN2) x (pH2)3)

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13
Q

In Kp, what is ‘p’?

A

P = partial pressure in Pa/kPa

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14
Q

If Kp>1 there are …

A

… more of the products to reactants at equilibrium

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15
Q

If Kp<1 there are …

A

… more of the reactants to products at equilibrium

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16
Q

Partial pressure is the …

A

… individual pressures of the components in the mixture

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17
Q

Kp is a constant at …

A

constant temperature

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18
Q

How does temperature effect Kp in an exothermic reaction?

A

Suppose temperature increases, an increase in temperature favours the endothermic reaction, which in this case is the reverse reaction, so the equilibrium responds by moving to the left hand side, in other words the partial pressure of the products drop, this drops the value of Kp.
Suppose temperature decreases, a decrease in temperature favours the exothermic reaction, which in this case is the reverse reaction, so the equilibrium responds by moving to the right hand side, in other words the partial pressure of the reactants drops, this increases the value of Kp.

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19
Q

How do we know partial pressure is proportional to the mole fraction?

A

A(g) + B(g)  C(g) at a fixed volume and constant temperature
pV = nRT

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20
Q

Partial pressure =

A

mol fraction x total pressure

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21
Q

Mole fraction =

A

mol / total moles

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22
Q

What is Kp?

A

the equilibrium constant in terms of partial pressure

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23
Q

Why is equilibria involving gases are usually expressed in terms of Kp?

A

This is because it is easier to measure the pressure of gas rather than the concentration

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24
Q

The mole fraction of a gas is the same as its …

A

… proportion by volume to the total volume of gases in a gas mixture

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25
``` For gas A in a mixture: Mole fraction (A) = ```
moles (A) / total number of moles in gas mixture
26
Mole fraction of gases in the air?
Air has approx. 78% N2 , 21% O2 and 1% other gases Mole fraction of N2 x(N2) = 78/100 = 0.78 Mole fraction of O2 x(O2) = 21/100 = 0.21 Mole fraction of other x(other) = 1/100 = 0.01
27
Sum of mole fractions always =
1
28
Calculating Mole Fraction from Gas Volumes?
Volume = moles x 24 | This shows that volume is proportional to the moles of gas
29
Sum of partial pressures =
total pressure
30
How are the units for Kp found?
in the same way as Kc
31
Nitrogen, hydrogen and ammonia coexist in a homogeneous equilibrium ; N2 (g) + 3 H2 (g)  2 NH3 (g) An equilibrium mixture at 400 oC contains 18 mol N2, 54 mol H2 and 48 mol of NH3. The total equilibrium pressure is 200 atms. Use this information to calculate the value of Kp.
Step 1 : find the mole fraction of N2, H2 and NH3. Total number of gas moles = 18+54+48 = 120 mol x(N2) = 18/120 = 0.15 x(H2) = 54/120 = 0.45 x(NH3) = 48/120 = 0.40 Step 2 : find the partial pressures of each gas. p(N2) = 0.15 x 200 = 30 atms p(H2) = 0.45 x 200 = 90 atms p(NH3) = 0.40 x 200 = 80 atms Step 3 : Calc Kp Kp = p(NH3)2 = 802 = 2.9 x 10-4 atms-2 p(N2) x p(H2)3 30 x 903 Units = (atm)2 = 1 = atm-2 (atm) x (atm)3 atm2
32
Describe and explain how you find kP in heterogeneous equilbria
Equilibrium contains different phases (solid and gas) Equilibrium: CaCO3(s) ⇌ CaO(s) + CO2(g) Kp expression contains only gaseous species Kp = p(CO2) Solid species are omitted (solids have no gas pressure) Therefore, if a question arose that said: In the equilibrium mixture, CO2 has a partial pressure of 2.5 x 10-2 atm at 600oC. Calculate Kp. Kp = p(CO2) = 2.5 x 10-2 atm.
33
K is a constant and only changed by
A change in temperature
34
Equilibrium is achieved within a system when
the concentrations/partial pressures of the species at equilibrium give the value of K for that temperature when placed in the equilibrium constant expression
35
For forward exothermic reactions what happens when temp increases in terms of Kp?
As temperature increases, Kp values decrease, showing that the equilibrium position shifts to the left
36
For forward endothermic reactions what happens when temp increases in terms of Kp?
As temperature increases, Kp values increase, showing that the equilibrium position shifts to the right
37
Why is there no change in K for changes in concentration or pressure?
as the equilibrium moves to keep the equilibrium constant at the same value
38
Explain how a change in pressure effects Kp?
For a change in pressure, if the pressure is increased, when looking at K equation, the part of the fraction that will be most affected by a change in the system will be the part with the highest powers. This increase in pressure will increase the value of Kp and mean that the system is no longer in equilibrium, to restore Kp to its value for that temperature, the partial pressure of the substance with less powers need to increase so the equilibrium shifts in that direction.
39
What is a reaction rate?
Chemists define the rate of reaction as the rate at which a reactant(s) is used up or the rate at which a product formed
40
when we look at concentration and rates of reaction it is important to state which substance we are following, why?
.For example if we consider the reaction A + 2B C .The concentration of reactants A and B decrease with time and the concentration of product C increases with time .The reaction tells us that for every A that reacts two Bs are required .So the concentration of B decreases twice as fast as the concentration of A
41
.We talk about the amount of reactants or products in terms of their what?
Concentration
42
.Concentration is measured in what?
mol dm-3
43
.We use the symbol [ ] to write about what?
Concentration
44
if we were looking at the concentration of A we would write what?
[A]
45
.Chemical equations tell us what?
what is involved in the reaction
46
the stoichiometric values tell us what?
the quantitative relationship between the different reactants and products
47
chemical equations gives us no information about what?
whether the reaction will actually happen or how fast it will occur
48
.The rate of a chemical process can depend on several factors, what are they?
``` – temperature of the reaction – concentration of the reactants – the surface area • only relevant with solid reactants – the presence of a catalyst ```
49
.The chemical kinetics of a reaction allow chemists to what?
control reactions by altering the conditions
50
.The reaction rate is what?
the change in concentration of a reactant (or product) per unit time
51
The reaction rate describes what?
– describes how quickly reactants are used up | – or how quickly products are formed
52
.We can look at the __________ for an entire reaction or look at the rate a specific point during the reaction – __________________
Average rate | the instantaneous rate
53
.The average rate is what?
the total change in concentration of reactants (or products) divided by the time taken for the reaction to take place
54
.The instantaneous rate of a reaction is what?
the rate of change occurring at a specific time in the reaction
55
.One method to calculate the rate of change at a given point is to what?
find the gradient of the tangent at the point you are interested in
56
The units for a rate of reaction is
mol dm-3s-1
57
Rate of reaction =
change in concentration / time
58
.In the reaction: A → B, we can calculate either ...
... the average rate of A being used or the average rate of B being produced
59
.Rate is always a positive value so a minus sign can be added to [A] as the change in concentration is ...
... negative
60
.The instantaneous rate of reaction is ...
... the amount of change in concentration of a product or reactant at a specific time during a reaction
61
.A graph can be used and the rate determined by ...
... drawing a tangent to the graph at any time and finding the slope of that tangent
62
.Calculate the gradient by
dividing the change in y by the change in x
63
.Changing the concentration often changes the what?
rate of a reaction
64
.The rate of reaction is proportional to the ...
... concentration of a particular reactant raised to a power
65
.For example, for reactant [A] and power n, rate is proportional to ...
... [A]^n
66
.For each reactant, the power is (in reference to order of reaction)
the order of reaction for that reactant
67
.In a reaction, different reactants can have different orders and each may affect the rate in different ways .Common orders are:
zero order (0), first order (1), second order (2)
68
Tell me about the zero order
.When the concentration of a reactant has no effect on the rate, the reaction is zero order with respect to the reactant .With zero order, rate is proportional to [A]0 .In a zero order reaction: - Any number raised to the power zero is 1 - Concentration does not influence the rate
69
Tell me about the first order
.A reaction is first order with respect to a reactant when the rate depends on its concentration raised to the power of one .With first order, rate is proportional to [A]1 .In a first order reaction: - If the concentration of A is doubled, the reaction rate increases by a factor of 21 = 2 - If the concentration of A is tripled, the reaction rate increases by a factor of 31 = 3
70
Tell me about the second order
.A reaction is second order with respect to a reactant when the rate depends on its concentration raised to the power of two .With second order, rate is proportional to [A]2 .In a second order reaction: - If the concentration of A is doubled, the reaction rate increases by a factor of 22 = 4 - If the concentration of A is tripled, the reaction rate increases by a factor of 32 = 9
71
.The rate equation gives the what?
mathematical relationship between the concentrations of the reactants and the reaction rate
72
.For two reactants, A and B, the rate equation is:
- Rate = k [A]m [B]n
73
.The rate constant k is the what?
proportionality constant, it is the number that mathematically converts between the rate of reaction and concentration and orders
74
Outline the principles in Le Chatelier’s principle
- Conc increase of a species, equilibrium moves in direction to reduce that concentration - Pressure increase favors side with the least number of molecules - Temperature increase favors the endothermic direction
75
- At constant temperature, K does not change if you change ...
... pressure, concentration or use a catalyst
76
- K will only change if ...
... the temperature is changed
77
For an exothermic reaction, Kp decreases with increasing temperature and the equilibrium position shifts to the left, why?
an increase in temperature favors the endothermic backward reaction
78
Essentially, why does temperature cause the equilibrium to shift?
A change in the K value, which is caused by a change in temperature, has to be met by a change in the concentrations or partial pressures of the reactants and products - which means the equilibrium is shifting
79
Effect of Increasing Temperature on Equilibrium | Exothermic
K decreases | Equilibrium shifts to the left
80
Effect of Increasing Temperature on Equilibrium | Exothermic Endothermic
K increases | Equilibrium shifts to the right
81
Explain Why K Doesn’t Change with Concentration using : .N2O4 (g)  2 NO2 (g) .At constant temperature, [NO2] = 0.4 moldm-3 [N2O4] = 0.01 moldm-3 as an example
Kc = [NO2 (g)]2 = 0.4002 = 16.0 mol dm-3 [N2O4 (g)] 0.010 If [N2O4] increased to 0.02 then Kc = 0.4002 = 8.0 mol dm-3 0.02 The system is now no longer in equilibrium. .To return the value of Kc ratio back to 16.0 mol dm-3 then [NO2] must increase & [N2O4] must decrease (top bigger bottom smaller) .N2O4 (g)  2 NO2 (g) the equilibrium shifts to the right .Using Le Chatelier’s principle, we would expect the equilibrium to shift to the right so that the equilibrium can decrease the [N2O4] if extra is added. .Le Chatelier’s principle only works because Kc controls the relative concentration of reactants and products present at equilibrium to maintain a constant value.
82
Explain Why K Doesn’t Change with Pressure by using : .N2O4 (g)  2 NO2 (g) .Le Chatelier : increase in pressure favours shift to the left due to lower number of molecules .At constant temp; p(NO2) = 9.6 atms p(N2O4) = 0.24 atms as an example
.Kp = p(NO2)2 = 9.62 = 384 atms p(N2O4) 0.24 .If total pressure doubled p(NO2) doubled to 19.2 atms and p(N2O4) = 0.48 then Kp = 19.22 / 0.48 = 768 atms .To reduce Kp back to 384, p(NO2) must decrease and p(N2O4) must increase (top smaller / bottom bigger), so equilibrium shifts from right to left .The shift to the left (fewer gaseous molecules) is directed by the value of Kp being restored
83
Increasing Pressure on Ammonia Production, explain what happens with reference to K values?
.N2 + 3 H2  2 NH3 .Increase pressure favors shift from left to right . Kc = [NH3]2 If pressure increased at constant temperature, then Kc must remain constant [N2] x [H2]3 .As pressure increased then the concentration of N2, H2 and NH3 will increase (same moles in smaller volume) .As denominator (bottom) power x4 / numerator (top) x2 then value of Kc will decrease as [ ]’s increase .To restore Kc back to original value i.e., maintain constant Kc then equilibrium will shift to increase top [NH3] and reduce bottom [N2][H2] – shift from left to right
84
Effect of catalysts on K values
.Equilibrium constants are unaffected by catalysts | .They affect the rate of a reaction, not equilibrium position (speed up both forward and back reaction by same factor)
85
If a species is zero order:
- It means that changing the concentration of a substance has no effect on the rate - If the concentration doubles, the rate stays the same - If the concentration triples, the rate stays the same
86
If a species is first order:
- It means that changing the concentration of a substance changes the rate to the power 1 - If the concentration doubles, the rate doubles (21 = 2) - If the concentration triples, the rate triples (31 = 3)
87
If a species is second order:
- It means that changing the concentration of a substance changes the rate to the power 2 - If the concentration doubles (x2), the rate quadruples (x4) (22 = 4) - If the concentration triples (x3), the rate increases by 9 (32 = 9)
88
A + 2B + C  D + E [A] is zero order, [B] is 1st order, [C] is 2nd order Rate = Overall rate =
K [B] [C]2 1 + 2 = 3
89
What does ICE stand for?
Initial Change Equilibrium
90
2NO2 2NO + O2 0.56 moles of NO2 are left to decompose in a vessel with a volume of 0.5dm3. 0.48 moles of NO are formed. What is the value of Kc?
17.28M
91
How to work out K and the units for K
Rearrange the rate equation and input values from the table to work out the value of K Write the units of each part of the equation for K and work out the units by cancelling etc.
92
What is Kc?
a mathematical representation of the ration of products:reactants
93
What do homogeneous and heterogenous mean?
Homogeneous – same state | Heterogeneous – different states
94
The concentrations of pure solid and pure liquids are excluded from equilibrium expressions, why?
as their concentrations are constant
95
What is the unit of rate constant for an overall order of reaction of 0
Mol dm-3 s-1
96
What is the unit of rate constant for an overall order of reaction of 1
s-1
97
What is the unit of rate constant for an overall order of reaction of 2
Mol-1 dm3 s-1
98
What is the unit of rate constant for an overall order of reaction of 3
Mol-2 dm6 s-1
99
What is the unit of rate constant for an overall order of reaction of 4
Mol-3 dm9 s-1
100
.For gaseous equilibria, it is more convenient to use ________ of reactants and products instead of equilibrium concentrations in mol dm-3
partial pressures
101
Generic Kp formula – | aA + bB cC + dD
Kp = ((pC)c x (pD)d) / ((pA)a x (pB)b)
102
Haber process equation and Kp formula
N2 + 3H2 2NH3 | Kp = (pNH3)2 / ((pN2) x (pH2)3)
103
What is p in Kp?
p = partial pressure in Pa/kPa
104
If Kp > 1 there are
more products than reactants
105
If Kp < 1 there are
more reactants than products
106
What is partial pressure
The partial pressure is the pressure of an independent component of the equilibria
107
Like Kc, Kp is constant at what?
a constant temperature
108
In the haber process, Suppose the pN2 is doubled, how does the equilibrium respond?
The denominator will be bigger, so Kp will get smaller, so to get bigger again it increases the numerator, so pNH3 increases, so the equilibrium moves to the right
109
Effect of temperature – Delta H = -92 kJmol-1 what would happen in a temperature increase?
Suppose a temperature increase, it would favour the endothermic reaction, so the equilibrium would shift to the left, so Kp would get smaller
110
Effect of temperature – Delta H = -92 kJmol-1 what would happen in a temperature decrease?
Support a temperature decrease, it would favour the exothermic reaction, so the equilibrium would shift to the right, so Kp would get larger
111
A + B C Fixed volume at a constant temperature Why is partial pressure proportional to the number of moles?
pV = nRT
112
Partial pressure is proportional to the what?
mole fraction
113
The sum of the mole fractions equals what?
1
114
Partial pressure =
mol fraction x total pressure
115
Kp is what?
The equilibrium constant in terms of partial pressures
116
Equilibria involving gases are usually expressed in terms of what?
Kp
117
.It is easier to measure ____ of gas rather than concentration
pressure
118
.Concentration & pressure are __________ to each other
directly proportional
119
.Under the same conditions, the same volume of different gases will contain the same number of __________
moles of gas molecules
120
.The mole fraction of a gas is the same as its proportion by volume what?
to the total volume of gases in a gas mixture
121
mole fraction x(A) =
number of moles of A / total number of moles in gas mixture (N)
122
Partial pressure, p, is what?
the contribution of a gas towards the total pressure
123
Why do mol fractions have no units?
1. Mol fractions are calculated with moles on the top and bottom of the equation, so the units cancel out
124
Partial pressure, p, is the what?
contribution of a gas towards the total pressure
125
Partial pressure (p) =
mole fraction x Total pressure (P)
126
To work out the order of the reaction for the concentration, you have to use experimental data, to get this you have two options, what are they?
1. Continuously monitor the change in concentration of A against time 2. Use initial rates method to find out how the initial rate changes as you vary the concentration of A
127
Concentration-time graphs can be plotted by ______________________________________________________________________, it is called continuous monitoring
continuously monitoring the concertation of a reactant through the course of the reaction
128
How can you gain the concentration of a reactant through the course of the reaction?
Can use loss in mass, gas syringe, or measuring cylinder Also can use pH changes or colorimetry Can’t use every method for every experiment
129
What can the shape of concentration time graphs tell us?
The shape can be used to tell you the order for that particular reactant
130
For concentration time graphs, a zero order reaction produces ....
a straight line with a negative gradient, the reaction rate does not change at all through the course of the reaction
131
For concentration time graphs, a first order reaction produces ...
a downward curve with decreasing gradient over time, as the gradient decreases with time, the reaction gradually slows down
132
For concentration time graphs, a second order reaction has a ...
downward curve but steeper at the start and tailing off more slowly
133
For concentration-time graphs, you can find the rate using: gradient =
delta (y) / delta (x)
134
How to find gradient of concetration-time graphs
.For zero orders, draw a triangle to the start and end | .For first order, draw a triangle touching the curve at one point (a tangent)
135
Apart from rate, what else can you find from conc-time graphs?
K
136
How can you tell between first and second order conc-time graphs?
.We can tell if we have a first order curve by measuring half life Half life (t1/2) is the time taken for half of the reactant to be used up First order reactions have a constant half-life independent of the initial concentration This pattern is called exponential decay
137
what does ln(2) / t1/2 equal?
k
138
Equilibria involving gases are usually expressed in terms of what?
Kp – constant in terms of partial pressure
139
Easier to measure pressure of ___ rather than concentration
gas
140
_________ and pressure are directly proportional to each other
concentration
141
Mole fraction x(A) =
number of moles of A / total number of moles in gas mixture (N)
142
Volume = mole x __
24
143
Partial pressure is what?
the contribution of a gas towards the total pressure
144
Partial pressure (p) =
mole fraction x total pressure (P)
145
Kp is similar to Kc but ...
... partial pressures are used instead of concentration
146
Briefly explain le Chatelier
.Conc increase of a species equilibrium moves in direction to reduce that conc .Pressure increase favours side with the least number of molecules .Temperature increase favours the endothermic reaction
147
.Le Chatelier works because of what?
equilibrium constants
148
k=1, k<1, k>1 meaning
.k=1 equilibrium half way .k=100 equilibrium lies will over to products (to the right) .K=0.01 equilibrium lies well over to the reactants (to the left)
149
.At constant temperature, K does no change if
you change pressure, conc, or use a catalyst
150
.K will only change if
the temperature is changed
151
How changes in conc and pressure affect equilibrium constants
.The value of the equilibrium constant K is unaffected by changes on concentration and pressure. .This may seem strange as you know from Le Chatelier’s principle that the position of the equilibrium can be shifted by changing concentration or pressure. .The equilibrium shift actually takes place from the very fact that the equilibrium constant does not change
152
Increasing pressure on ammonia production exam answer
.Increase pressure favors shift from left to right. If pressure increased at constant temp, then Kc must remain constant. As pressure increased then the concentration of N2, H2 and NH3 will increase (same moles in smaller volume). As denominator (bottom) power x4 / numerator (top) x2 then value of Kc will decrease as [ ]’s increase. To restore Kc back to original value i.e., maintain constant Kc then equilibrium will shift to increase top [NH3] and reduce bottom [N2][H2] – shift from left to right.
153
.Equilibrium constants are _________ by catalysts. ...
unaffected .... they affect the rate of a reaction, not equilibrium position (speed up both forward and back reaction by same factor).
154
Define acid
dissociates in water and releases H+ ions
155
Define alkali
dissociates in water to release OH- ions
156
Neutralisation equation
H+ + OH-1  H2O
157
Bronsted Lowry Acid:
Proton donor
158
Bronsted Lowry Base:
Proton acceptor
159
pH = 1 (x 10 the concentration of H+ ions) pH =
2
160
What makes an acid strong?
It fully dissociates
161
As a Strong acid fully dissociates, pH of a strong acid can be calculated from
concentration of acid
162
pH =
-log10[H+]
163
Sulphuric acid is dibasic, what does this mean?
H2SO4  2H+ + SO42-
164
[H+] =
10-pH
165
Weak acids form an acid dissociation constant called
Ka
166
Ka =
[products] / [reactants]
167
[H+] = for weak acids
root([HA] Ka)
168
[HA] is what?
concentration of weak acid
169
A+B C What happens when you Increase pressure?
equilibria moves to the side with fewer molecule/moles, 2 moles on RHS and 4 on LHS, equilibria moves to the right
170
A+B C What happens when you Lowering Temperature?
Forward reaction is exothermic (negative energy change), lowering temperature moves equilibria to exothermic reaction (RHS)
171
A+B C What happens when you Increase A and B?
Equilibria removes addition of A and B, equilibria moves to RHS to remove this extra concentration of A and B
172
A+B C What happens when you Decrease C?
Equilibria moves to make more of what is removed, equilibria moves to RHS to make more C
173
Meaning of Kc>1?
means more products, equilibria is towards the RHS
174
Meaning of Kc<1?
means more reactants, equilibria towards the LHS
175
Meaning of Kc=1?
means LHS=RHS
176
.When a reversible reaction establishes an equilibria at a certain temperature, K will not change if, ________, _______, ____________ are changed/added
concentration, pressure, or a catalyst
177
.K is only changed by ________
temperature
178
In the equation 2SO2 + O2 2SO3 delta H = -197 As temperature increases Kp decreases, why does this happen?
Kp = p(SO3)2 / ( p(SO2)2 x p(O2) ) Partial pressure of products decrease and reactants increase Equilibria moves to the left
179
Using N2O4 2NO2 as an example, explain why Kc and Kp do not change due to concentration, pressure or addition of a catalyst?
.If N2O4 concentration was increased at same temperature, Kc value would be lowered (denominator increased), equilibria moves to the RHS and Kc returns to normal (numerator increase, denominator decrease) .If we increased partial pressure then the numerator would be increased more than the denominator due to the difference in powers, this would cause Kp value to increase (system not at equilibria), equilibria moves left to increase value of the denominator (N2O4) and restore the value of Kp, system would be back in equilibrium .Catalyst does not change equilibria (Kc/Kp = same) as both forward and reverse reaction rates are changed the same, this means position of equilibria does not move
180
What does the Arrhenius theory define bases and acids as?
The Arrhenius theory of acids and bases defines acids as a substance that releases protons in solution, and bases as a substance that releases hydroxide ions.
181
How can we test for acids?
We can test for acids using universal indicator paper which turns red or orange depending on the strength of the acid Blue litmus paper also turns red in the presence of an acid
182
HCl + H2O -->
H3O+ + Cl-
183
What is H3O+
A hydronium ion, also known as an oxonium ion
184
What is water acting as in the equation: | HCl + H2O  H3O+ + Cl-
a base
185
What is a bronsted-lowry base?
A Bronsted Lowry base is a substance which accepts protons in solution
186
What is a bronsted-lowry acid?
A Bronsted Lowry acid is a substance which releases or donates protons in solution
187
What does a bronsted-lowry acid-base reaction involve?
the transfer of a proton from one base to another
188
What does ammonia do in water? include equation
Ammonia, in water, accepts a proton | NH3 + H2O  NH4+ + OH-
189
In the equation, | NH3 + H2O  NH4+ + OH-, what is water acting as?
An acid
190
For a bronsted-lowry base, what is the pH of an acid?
So for the Bronsted Lowry theory, a base does not need to have a pH>7
191
What are substances that can act as either a base or an acid called?
Substances that can act as either an acid or a base are amphoteric
192
What are some old defnitions of acids?
.The definition of acids has developed since the time of the ancient Greeks .Simpler ideas involved substances that had a sour taste, contained hydrogen, hydrogen ions or had a pH lower than 7
193
.When a chemical reacts with an acid it is the __________ from the acid which is driving the reaction forward
hydrogen ion, H+,
194
HCl (aq) + NaOH (aq) 
NaCl (aq) + H2O (l)
195
How did the Bronsted-Lowry name come about?
Johannes Nicolaus Bronsted and Martin Thomas Lowry did not work together but both chemists formulated the idea that acids are proton donors and bases are protons acceptors
196
The Brønsted–Lowry acid–base theory is a development of these earlier ideas and states that:
.An acid is a proton donor | .A base is a proton acceptor
197
.How many protons, neutrons and electrons does a Hydrogen ion, H+ have?
.A hydrogen ion is just a proton
198
We know that HCl forms a covalent bond between the hydrogen and chlorine so what happens when it dissolves in water to become hydrochloric acid?
.HCl(g) + aq  H+(aq) + Cl-(aq)
199
HCl(g) + aq  H+(aq) + Cl-(aq) | .On closer inspection is?
HCl(g) + H2O(l)  H3O+(aq) + Cl-(aq)
200
.H3O+(aq) is known as the hydronium ion, also known as _______ ion
hydroxonium
201
.In this equation: HCl(g) + H2O(l)  H3O+(aq) + Cl-(aq) what is HCl and H2O acting as?
The HCl is a proton donor (a Brønsted–Lowry acid) | .The H2O is a proton acceptor (a B-L base)
202
In the reverse equation of HCl(g) + H2O(l)  H3O+(aq) + Cl-(aq) what happens to the roles?
.In the reverse equation, the roles reverse: | H3O+(aq) + Cl-(aq)  HCl(g) + H2O(l)
203
once an acid has ‘donated’ a proton it would become able to ‘accept’ a proton back and hence act as a base, what is this called?
We call these pairs of chemicals conjugate acid-base pairs
204
Give an example of a conjugate acid-base pair?
HCl and Cl- = Acid and conjugate base
205
What are the acid base pairs in HCl + H2O H3O+ + Cl-
``` HCl = acid 1 Cl- = base 1 ``` ``` H2O = base 2 H3O+ = acid 2 ```
206
What are the acid base pairs in CH3COOH + H2O CH3COO- + H3O+?
``` CH3COOH = acid 1 CH3COO- = base 1 ``` ``` H2O = base 2 H3O+ = acid 2 ```
207
What are the acid base pairs in NH3 + H2O NH4+ + OH-?
Base 2 Acid 1 Acid2 Base 1
208
What are the acid base pairs in HCO3- + HCl H2CO3 + Cl-?
Base 2 Acid 1 Acid 2 Base 1
209
Complete the equation for the conjugate acid-base pair: CH3CH(OH)COOH + CH3CH2CH2COOH
CH3CH(OH)COO- + CH3CH2CH2COOH2+
210
List the roles of H+ in reactions
spectator ions: Acid + metal  salt + hydrogen Solid carbonates and soluble carbonates: Acid + carbonate  Water + carbon dioxide base (metal oxides): Acid + base  salt + water Alkali: H+ + OH-  H2O
211
What did Soren Sorenson do?
introduced simple numbers to represent the colours of indicators using an electrochemical cell to measure the hydrogen content
212
What did Soren Sorenson find?
.He found the ion concentration had a very large range of values of powers of 10 (10-1 to 10-14)
213
What is a strong acid? With general equation
.A strong acid is one which completely dissociates into ions in a solution HA  H+ + A-
214
So for a strong acid, [H+] =
concentration of the acid ([HA])
215
pH =
-log10[H+]
216
What does the equation pH = -log10[H+] tell us?
.It tells us the relative hydrogen ion concentration of a given solution
217
What must we remember with the equation pH = -log10[H+]?
.THIS ONY WORKS FOR STRONG ACIDS
218
.An increase in H+ x10, it reduces the pH by how much?
1
219
What is pH of 1M HCl?
0
220
What is Sorenson's pH scale?
.The logarithmic scale means that a shift of one pH unit means a 10x change in the acidity and alkalinity of the solution .Theoretically there is no limit to the pH scale
221
What type of acid is HCl, what does this mean?
monobasic = [H+]
222
What type of acid is H2SO4, what does this mean?
dibasic = 2[H+]
223
What type of acid is H3PO4, what does this mean?
tribasic = 3[H+]
224
[H+] =
10-pH
225
What is the [HCl] of a solution with pH 1.8?
0.016 moldm-3
226
What is the [H2SO4] of a solution with pH 1.8?
0.008 moldm-3 as dibasic acid
227
50cm^3 of 0.1M HCl is diluted to 100cm^3 with water, what is the change in pH?
Before dilution, pH = 1 0n dilution, HCl conc is halved to 0.05M After dilution, pH = 1.30 Change = 0.3
228
rate-concentration graphs can be plotted using two different methods, what are they?
1. Continuously monitor the change in concentration of a substance over time and work out the gradient at set point on the graph 2. Use initial rates method to find out how the initial rate changes as you vary the concentration of A
229
We can produce a rate-concentration graph by producing a concentration time graph for the experience at different concentrations and then what?
using a tangent to work out the initial rate (the rate at t=0)
230
We can also use an initial rate reaction called a what?
clock reaction
231
The shape of rate-concentration graph can tell us what?
the order of the reaction
232
Describe a zero order rate-concentration graph
.Produces a horizontal line with zero gradient .This shows the rate doesn’t change .Rate = k .To work out the rate constant, it is the intercept on the y axis
233
Describe a first order rate-concentration graph
.Produces a straight line through the origin .This shows the rate is directly proportional to the concentration .Rate = k[A] .To work out the rate constant you should work out the gradient of the straight line
234
Describe a second order rate-concentration graph
.Produces an upward curve with increasing gradient .Rate = k[A]2 .This curve doesn’t actually confirm its second order, just that it’s not 0 or 1 .You have to plot another graph from this one to show its 2nd order .This means you can’t work out the rate constant directly from this curve
235
How to work our rate constant from second-order rate-concentration graph?
.To work out the rate constant you would need to plot a second graph of rate against concentration squared .If I is truly second order it should produce a straight line .To work out the rate constant you would work out the gradient of the line (like first order)
236
What is a clock reaction?
.A clock reaction is a more convenient way of obtaining initial rate .We use a reaction with a visual change – usually a colour change .We time from the start of the experiment to the visual change .We repeat the experiment each time with different concentration meaning the time for the colour change each time
237
For a clock reaction, what is assumed?
.We assume that the average rate of the reaction is the same as the initial rate
238
For a clock reaction, the initial rate is proportional to what?
.The initial rate is proportional to 1/t
239
What is an iodine clock?
.This is a clock reaction which relies on the formation of iodine .Aqueous iodine is orange brown so we can measure the colour change .We usually use an indicator (starch) as that is a intense black-blue colour with iodine so it is very easy to see the colour change
240
How can you work out the order of hydrogen perioxide in a reaction using an iodine clock?
.Hydrogen Peroxide (H2O2) reacts with iodide ions in an acid solution to form iodine H2O2 + 2I- + 2H+  I2 + 2H2O .Lets say we start with 0.05M of H2O2 .We would add some acid (to provide the H+ ions) and some KI to provide the I ions .We would also add some starch (for the indicator) and some sodium thiosulfate, Na2S2O3, to provide S2O32- ions Reaction 1: H2O2 + 2I- + 2H+  I2 + 2H2O Reaction 2: 2S2O3 2- + I2  S4O6 2- + 2I- .We time how long it takes to see a colour change (the blue-black to start to appear), this occurs when all of the sodium thiosulfate has been used up .We would then repeat this for the next concentration (e.g. 0.04 mol dm-3 and so on) You would end up with a table of results with concentration of H2O2 and time .You can then use the principle that initial rate = 1/t .So we work this out and add to the table You can then plot a graph of [H2O2] against 1/t, and from that work out its order
241
How accurate is the iodine clock?
.In the clock reaction we are measuring the average rate over a period of time, the shorted the amount of time, the less the rate will change over that time .The clock reaction is classed as accurate as long as less than 15% of the reaction has taken place (in terms of time)
242
What is a reaction mechanism?
A reaction mechanism describes the one or more steps involved in a reaction in a way which makes it clear how certain bonds are broken and made
243
What is the rate determining step?
The slowest step is called the rate determining step
244
What is The overall rate of reaction (the one you could measure if you did some experiments) controlled by?
the rate of the slowest step
245
What can the rate equation tell you in terms of rate determining steps?
.If the species is in the rate equation it is taking part in the rate determining step .If the species is not in the rate equation it is not taking part in the rate determining step .The power on the substance in the rate equation is the number of that substance in the rate equation
246
The steps involved in the reaction must add up to what?
the overall equation in the reaction
247
``` Rate = k[NO2]2 Overall = NO2 + CO  NO + CO2 ``` what are the two steps involved?
R.D.S = NO2 + NO2  NO3 + NO | Other step = NO3 + CO  NO2 + CO2
248
In any chemical reaction, some bonds are broken and new ones are made Often these changes are too complicated to happen in one single stage, instead, the reaction may involve what?
a series of smaller steps one after the other
249
BrO3- + 6H+ + 5Br-  3Br2 + 3H2O why must this reaction take multiple steps?
it is unlikely that all the ions will collide at the same time
250
This reaction happens in two steps, the steps also happen at different rates, one step is slow and one step is _____
fast
251
Rate = k [Cl.][O3] Overall equation = O3 + O  2O2 what are the two steps involved?
RDS = Cl. + O3  ClO. + O2 | Other Step = ClO. + O  O2 + Cl.
252
What is a strong acid?
A strong acid is one which completely dissociates into ions in a solution
253
WHat does pH = -log10[H+] only work for?
ONLY WORKS FOR STRONG ACIDS
254
[H^+] equation for changing concentraation
[H+] = [H+]old x (old volume / new volume)
255
How are weak acids different to strong ones?
.Weak acids do not dissociate fully like strong acids
256
What happens when a weak acid dissociates?
An equilibrium is established between the ions and the acid
257
As an equibrlium is established when weak acids dissociate, what can we calculate?
we can calculate an equilibrium constant Ka (Acids dissociation cons tat)
258
What does Ka equal for, HA H+ + A-?
Ka = ( [H+] [A-] ) / [HA]
259
For the Ka equation what two assumptions need to be made?
.A pure acids will split evenly into equal quantities of [h+] and [A-] .The concentration of the acid doesn’t change as the equilibrium lies so far to the left it can be considered equal
260
does [H+] = [H+ aq]?
yes
261
.A sample of ethanoic acid of concentration 0.04 moldm-3 | .What is the value of Ka?
2.5x10-9 moldm-3
262
Steps to calculating pH of weak acid
.Step 1: Calculate [H+] from ka and [HA] | .Step 2: Calculate pH
263
Are the approximations for weak acids justified?
.The first approximation assumes that the dissociation from water is negligible .[H+(aq)]eqm = [A-(aq)]eqm - if pH>6 then water dissociates and [H+] from water will be more significant than from dissociation of acid .This approximation breaks down for very weak acids or very dilute solutions .Second approximation assumes that the concentration of the acid [HA] is much greater than the [H+] concentration at equilibrium .[HA]start >> [H+]eqm [HA]eqm = [HA]start – [H+]eqm so [HA]eqm = [HA]start .Not valid as acid gets stronger as [H+] becomes more significant and real difference between [HA]eqm = [HA]start – [H+]eqm .Not justified for stronger weak acids / very dilute solutions.
264
.The value of Ka for weak acids is almost always very small and difficult to compare numbers with negative indices, how do we get around this?
create a scale of more useable numbers we often use the value of pKa, when talking about the aciditing of weak acids
265
What is pKa often used for?
to compare acids in biological systems
266
pKa equation
pKa = -log10Ka
267
What do the values of pKa mean?
The higher the value of pKa, the weaker the acid | The lower the value of pKa, the stronger the acid
268
How does wine show behaviour of typical dibasic and tribasic acids?
Wines often contain traces of sulphurous acid, H2SO3, added as a preservative .Sulphurous acid is dibasic and its dissociation is shown as: H2SO3 H+ + HSO3 - (pKa = 1.92) HSO3 - H+ + SO3 2- (pKa = 7.18) .For the first dissociation, H2SO3, acts as a weak acid .From the pKa values, HSO3, is a far weaker acid than H2SO3 .The behaviour is typical of dibasic and tribasic acids
269
What can increase the rate of a reaction?
``` .Increase temperature .Increase concentration/pressure .Increase surface area .Catalyst .Increase temperature .Increase concentration/pressure .Increase surface area .Catalyst ```
270
What needs to happen for a successful reaction?
.The particles must collide .Have sufficient energy .Be in correct orientation
271
What must you remember when drawing a maxwell-boltzman distribution?
SHOULD NEVER TOUCH X AXIS
272
Why should the maxwell-boltzman distribution go through the origin?
no molecules with no energy
273
Is the rate constant actually a constant?
.The rate constant is only actually constant if we change the concentration of reacantn .If we change other factors then it changes
274
How can we show that the rate constant can change?
This can be shown mathematically with an equation, called Arrhenius: K = A(e^(-Ea/RT))
275
What are the different parts of the Arrhenius equation?
``` .K = rate constant .A = pre-exponential frequency factor .e = natural log constant .Ea = activation energy .R = gas constant (8.31) .T = temperature (K) ```
276
what is e^(-Ea/RT) called?
the exponential factor
277
what does e^(-Ea/RT) represent?
This represents the proportion of particles that exceed Ea and have sufficient energy to take place
278
In the Arrhenius equation, what does A do?
‘A’ takes into account the frequency of collisions with the correct orientation, it does increase slightly with temperature but is essentially constant over a small temperature change
279
How can we show the effect of temperature by using the Arrhenius equation?
.You can use the arrhenius equation to describe the effect of temperature on the rate equation .Make up some numbers plug them into the equation to get a value for the exponential factor .Increase the temperature value by 10 .State the effect that this has had on K, and consequently the rate .This links to the Boltzmann distribution, as the increase in temperature shifts to distribution to the right, the number of particles above Ea increases, the particles move faster and they collide more frequently at the correct orientation.
280
Increasing temperature effects reactions by increasing the number of particles above Ea, but also increasing the number of collisions - which has the larger effect?
.There is more effect of temperature caused by more particles exceeding Ea than from increased collisions
281
How can we show the effect of a catalyst by using the Arrhenius equation?
.You can use the arrhenius equation to describe the effect of a catalyst on the rate equation .Make up some numbers plug them into the equation to get a value for the exponential factor .Decrease the activation energy value (as catalysts offer an alternate pathway, and so lower the Ea) .State the effect that this has had on K, and consequently the rate
282
Summarise how using the Arrhenius equation can show the effect of changing temperature and catalyst presence
.Increasing the temperature increases the rate constant and therefore increases the rate .Decreasing the activation energy (by using a catalyst) increases the rate constant and therefore increases the rate
283
What is the logarithmic form of Arrhenius?
ln(k) = -Ea/RT + ln(A)
284
What is a major use of the Arrhenius equation?
We can use this equation to determine Ea and A graphically | If we plot a graph of ln(k) against 1.T we will get a straight line of the type y=mx+c
285
How does the Arrhenius equation link to y=mx+c
``` ln(k) = -Ea/RT + ln(A) ln(k) = y -Ea/R = m 1/T = x Ln(A) = c m = gradient so working it out gives -Ea/R c = intercept on the y axis ```
286
Steps to plotting an Arrhenius graph
.Work out ln(k) and 1/T .Plot a graph of ln(k) against 1/T .Workout the gradient, and consequently the activation energy .Calculate A from the intercept ( ln(A) )
287
How to work out stuff from Arrhenius graph if its a broken scale?
Use the equation
288
Where strong acids completely dissociate to release all H+ ions into solution, weak acids only partially dissociate, explain this in terms of equations
Strong: HA → H+ + A- Weak: HA ⇌ H+ + A-
289
As weak acids form an equilibrium their dissociation can be represented by the acid dissociation constant, Ka, whats the equation for this?
Ka = "[H+(aq)][A-(aq)]" /"[HA(aq)]"
290
Explain why a larger value for Ka means a lower pH
.The larger the value for Ka the more the equilibria lies to the right and so the lower the pH i.e. higher [H+]
291
What alters Ka?
Temperature
292
.As the values for Ka are very small it is easier to give their negative logarithm, pKa, instead, what is the equation for this?
pKa = - logKa
293
pKa = - logKa, what is the inverse equation for this?
The inverse for this equation is: Ka = 10-pKa
294
This means that the weaker an acid the: ._____ Ka ._____ pKa
.Smaller Ka | .Larger pKa
295
.The [H+] of a weak acid depends on the value of what?
Ka and [HA]
296
.The equilibrium concentrations, [ ]eqm, can be used to determine a value for Ka, what is the equation for this?
Ka = "[H+]eqm [A-]eqm" /"[HA]eqm"
297
There are two approximations that need to be made when calculating Ka, what are they?
.HA dissociation forms equal [H+] and [A-] | .The change in [HA] is negligible so [HA]eqm = [HA]start
298
Using the approximations, Ka can be determined by what equation?
Ka = "[H+]eqm 2" /"[HA]start"
299
How can pH be calculated for a weak acid?
[H+] = √("Ka x [HA]" ) → pH = -log[H+]
300
.A value for Ka can be determined experimentally, how?
by using a pH meter to get the pH of a standard solution
301
.The larger the value for Ka, the greater the _________
dissociation
302
When calculating values for Ka there are issues with the approximations made, what are these issues?
• At pH values >6 water dissociation is significant Therefore doesn’t work for very weak acids or very dilute solutions • If [H+] concentration is significant there will be a difference between [HA]eqm and [HA]start Therefore doesn’t work stronger weak acids with Ka > 10-2 mol dm-3 or very dilute solutions
303
All aqueous solutions contain which ions?
H+ and OH- ions
304
H2O
H+ + OH-
305
In ____ [H+] > [OH-] In ____ [OH-] > [H+] In ____ [H+] = [OH-]
In acids [H+] > [OH-] In alkalis [OH-] > [H+] Neutral [H+] = [OH-]
306
For every 500,000,000 H2O molecules, only _ dissociates
1
307
For every 500,000,000 H2O molecules, only 1 dissociates, what does this mean for the equilbrium?
the equilibrium is on the left hand side
308
Do the Kc equation for water equilibrium
Kc = ([H+][OH-]) / [H2O]
309
[H2O] x Kc =
[H+] x [OH-]
310
[H2O] is such a large excess it can be classed as a ____
constant
311
What is Kw?
ionic product of water
312
Kw = [H2O] x Kc, so replace [H2O] x Kc with Kw in the correct equation
Kw = [H+] x [OH-]
313
At 298K, Kw =
1x10-14 mol2dm-6
314
Why is the pH of pure water at 298K, 7?
``` Kw = [H+] x [OH-] 1x10-14 = [H+] x [OH-] The concentrations are the same and so it can be written as: 1x10-14 = [H+]2 1x10-7 = [H+] pH = 7 ```
315
Effect of temperature on Kw
The dissociation of water is endothermic Temperature increase will move the equilibrium to the right, and so Kw will increase Temperature decrease will move the equilibrium to the left, and so Kw will decrease Water will always remain neutral at all temperatures, pH may change with temperature, but [H+] = [OH-] all the time and so it is neutral
316
.Water ionises very slightly, acting as both an acid and as a base – setting up an ________
equilibrium
317
.Water dissociates a very, very small amount according to the equation – it must do, otherwise it would not _____________
conduct electricity
318
.1 dm3 (1000g) of water is mainly ________ H2O
undissociated
319
. [H2O(l)] = 1000/18 = 55.6 mol dm-3 (a constant), why?
.1 dm3 (1000g) of water is mainly undissociated H2O
320
.If we know the concentration of hydroxide ions we can rearrange Kw to give us the value of what?
[H+]
321
What is the pH of 0.4 mol dm-3 NaOH?
``` Kw = [H+][OH-] = 1.00 × 10–14 mol2dm–6 (1.00 × 10_14 )/([0.4])=[H+] = 2.5 x 10-14 mol dm-3 pH = -log10[H+] = -log10[2.5 x 10-14 ] = 13.60 ```
322
What is the pH of a solution with [OH-] = 2 x 10-2 mol dm-3 at 25oC ?
Step 1 : calculate [H+] from Kw and [OH-] Kw = [H+][OH-] = 1.00 x 10-14 [H+] = Kw = 1.00 x 10-14 = 5.00 x 10-13 mol dm-3 [OH-] 2.00 x 10-2 Step 2 : Use calculator to find pH pH = - log [H+] = -log (5.00 x 10-13) = 12.30
323
What are the concentrations of H+ (aq) and OH- (aq) in a solution of pH 3.25 at 25oC ?
Step 1 : Use calculator to find [H+(aq)] [H+] = 10-pH = 10-3.25 = 5.62 x 10-4 mol dm-3 Step 2 : Calculate [OH-] from Kw and [H+] Kw = [H+][OH-] = 1.00 x 10-14 [OH-] = Kw = 1.00 x 10-14 = 1.78 x 10-11 mol dm-3 [H+] 5.62 x 10-4
324
For pH values that are whole numbers, it is easy to work out the [H+] and [OH-] concentrations as the indices add up to what?
-14
325
.The pH of weak bases can be calculated via a similar method to that used for ______
weak bases
326
.In an aqueous solution, there will always be both H+ (aq) and OH- (aq) ions present such that ________
[H+ (aq)][OH- (aq)] = Kw
327
.A solution is ______ when [H+ (aq)] > [OH- (aq)] .A solution is ______ when [H+ (aq)] = [OH- (aq)] .A solution is ______ when [OH- (aq)] > [H+ (aq)]
.A solution is acidic when [H+ (aq)] > [OH- (aq)] .A solution is neutral when [H+ (aq)] = [OH- (aq)] .A solution is alkaline when [OH- (aq)] > [H+ (aq)]
328
.So a solution that is acidic will still contain __ ions, it is just that there are more __ions (and vice versa in an ______ solution)
OH- H+ Alkaline
329
.The value of Kw controls the ______ of each ion
Concentrations
330
• Kw can also tell us the pH of ______
pure water
331
• As the water splits into equal concentrations of OH- and H+ ions we can make what assumption?
``` Kw = [H+][OH-] = 1.00 × 10–14 mol2dm–6 = [H+]2 = 1.00 × 10–14 = [H+] = 1.00 × 10–7 pH = -log10[H+] = -log10[1.00 x 10-7 ] = 7 ```
332
When is neutral not neutral?
.A neutral solution is defined by a equal number of moles of H+ ions and OH- NOT by a pH of 7 as you may have been taught .Whilst this value is 7 at approximately 298K, the value of Kw increases with temperature
333
.The pOH scale measures what?
the concentration of hydroxide ions
334
.Therefore you can solve fpr pH, pOH and [OH-] given just ___
[H+]
335
pH + pOH =
14
336
.Kw = [H+][OH-] =
1x10-14
337
Define Enthalpy of reaction ΔrH
enthalpy change that accompanies a reaction in the molar quantities shown in a chemical equation under standard conditions, with all reactants and products in their standard states
338
Define Enthalpy of formation ΔfH
enthalpy change when one mole of compound is formed from its constituent elements under standard conditions
339
Define Enthalpy of combustion ΔcH
enthalpy change when one mole of substance is burnt completely in excess oxygen under standard conditions
340
Water slightly ionises, what equation will show this?
H2O(l) H+(aq) + -OH(aq)
341
Ka of : H2O(l) H+(aq) + -OH(aq) =
[H+][-OH] / [H2O]`
342
Ka x [H2O] =
Kw
343
Kw =
[H+][-OH]
344
What is Kw?
Kw is the ionic product of water, at 25’C it equals 1x10-14 mol2dm-6
345
How does ionic bonding work?
1. Loss of an electron(s) by an element 2. Gain electrons by a second element 3. Attraction between positive and negative ions
346
Na + Cl, ionisation electron addinity and latice equations
``` Ionisation Energy – Na  e- + Na+ +496kJmol-1 Electron Affinity – e- + Cl  Cl- -349kJmol-1 Lattice Enthalpy – Cl- + Na+  NaCl -766kJmol-1 ```
347
What is electron affinity?
.The enthalpy change when one mole of electron is added to one mole of atoms in the gaseous phase to form one mole of -1 ions
348
Is repulsion between two electrons exothermic or endothermic, why?
.Repulsion between two negatively charged things requires energy so exothermic
349
What is lattice enthalpy?
.ΔHlatt is the enthalpy change when 1 mole of ionic substance is formed from its gaseous ions under standard conditions
350
.The strength of the ionic bond is related to the lattice enthalpy, how?
more exothermic the greater the ionic bonding
351
Lattice enthalpy can't be measured, why?
Cannot be measured directly as cannot form one mole of ionic lattice from gaseous ions
352
What are the factors affecting lattice enthalpy? How?
Charge – .The greater the charge on the ions, the stronger the attraction – therefore, more exothermic lattice enthalpy Size – .Smaller ions can pack together more tightly, therefore there is greater attraction and more exothermic lattice enthalpy
353
Why, when moving down group two, do the temperatures required to break the lattice increase?
.They have decreasing charge densities .Mg2+ is a smaller ion than Ba2+ , so the +2 charge occupies a smaller volume – this means Mg2+ has a higher charge density than Ba2+ .Mg2+ can distort the electron clouds within the CO32- ion (called polarisation), this weakens the covalent bonding in the ion and reduces its decomposition temperature
354
What is a buffer?
a solution that minimises pH change when a small amount of acid or alkali is added
355
What two types of buffers are they?
Weak Acid and Salt of Weak Acid Excess Weak Acid and Strong Base
356
Suggest and explain a Weak Acid and Salt of Weak Acid buffer
Weak Acid – Ethanoic Acid – CH3COOH(aq) CH3COO-(aq) + H+(aq) Salt of Weak Acid – Sodium Ethanoate – CH3COONa(s) + (aq) CH3COO-(aq) + Na+(aq) ¬Buffer Contains – CH3COOH(aq) CH3COO-(aq) + H+(aq) When add H+, H+ reacts with conjugate base, equilibrium will move to the left to reduce the amount of H+, pH is constant Adding –OH (alkali) – -OH + H+  H2O Conc of H+ decreases, equilibrium moves to the right to increase the conc of H+, pH is constant
357
Suggest and explain an excess Weak Acid and strong base buffer
CH3COOH(aq) + NaOH(aq) --> CH3COONa(aq) + H2O(l) CH3COONa(aq) CH3COO-(aq) + Na+(aq) CH3COOH(aq) CH3COO-(aq) + H+(aq) When add H+, H+ reacts with conjugate base, equilibrium will move to the left to reduce the amount of H+, pH is constant Adding –OH (alkali) – -OH + H+  H2O Conc of H+ decreases, equilibrium moves to the right to increase the conc of H+, pH is constant
358
Excess methanoic acid is reacted with potassium hydroxide, explain how a buffer solution is produced and how pH is controlled when 5cm3 of HCl is added.
The solution now contains HCOOK(aq) HCOO- (aq) + K+(aq) and HCOOH(aq) HCOO-(aq) + H+ equilibriums in solution – the buffer. When 5cm3 of HCl is added, it dissociates into H+ and Cl-, the H+ ions increase the concentration of the H+ already in the solution, so the HCOOH(aq) HCOO-(aq) + H+ point of equilibrium moves to the right – decreasing the conc of H+ in solution, and so keeping the pH constant.
359
Ka x ( [HA]/[A-] ) = ? what does each part mean?
``` [H+] = Ka x ( [HA]/[A-] ) [HA] = concentration of weak acid [A-] = concentration of conjugate base ```
360
50cm3 of 1.2M NaOH reacts with 250cm3 of ethanoic acid (1M), Ka = 1.74x10-5, what is the pH?
``` CH3COOH CH3OO- + H+ CH3COOH + NaOH  CH3COO- + Na+ + H2O 1. Moles weak acid = 250x1 / 1000 = 0.25mol 2. Moles NaOH = 50x1.2 / 1000 = 0.06mol 3. Moles A- = 0.06mol 4. Moles HA = 0.19mol 5. [H+] = Ka ([HA] / [A-]) = 1.74x10-5 x (0.19/0.06) = 5.51x10-5 6. pH = 4.26 ```
361
Equation to work out lattice enthalpy from born haber cycle
L.E = FORMATION – sum(ATOM + I.E + E.A) or L.E = FORMATION – sum(REST)
362
What are Born Haber Cycles used for?
Born Haber cycles can be used to calculate a measure of ionic bond strength based on experimental data
363
Draw the born haber cycle for NaCl
check notes or google
364
Draw the born haber cycle for MgCl2
check notes or google
365
Draw the born haber cycle for CuO
check notes or google
366
Blood must contain a pH of what?
Blood must contain a pH of 7.40 +- 0.05
367
What is the most important buffer in blood?
the carbonic acid – hydrogencarbonate
368
Carbonic acid dissociation equation
H2CO3 H+ + HCO3-
369
If blood becomes too acidic (acidosis), what presents?
fatigue, shortness of breath, shock, death
370
If blood becomes too alkaline (alkalosis), what presents?
spasms, light-headed, nausea
371
What happens if the body produces more acidic products?
.The H+ concentration in the blood will increase, the equilibrium of the hydrogencarbonate dissociation will shift to the left, the H+ ions will be used up to form more hydrogencarbonate, the H+ concentration will return to normal, the pH will have had minimal change .If the acid level continued to rise, fatigue, shortness of breath, shock, or death would eventually set in .This would occur when we have ran out of HCO3- ions
372
Carbon dioxide dissolves in water to form what? What is the equation for this?
carbonic acid: | CO2 + H2O H2CO3
373
Inhalation of high levels of CO2 means what?
Inhalation of high levels of CO2 mean that the equilibrium in the blood must shift to the right to form more H2CO3, this means that the level of H2CO3 in the blood increase, so in the equilibrium H2CO3 H+ + HCO3- the equilibrium shifts to the right to counter this, this forms more H+ ions in the blood, making it more acidic, and resulting in acidosis which would lead to fatigue, shortness of breath, shock, and eventual death. Increased [H+] means enzymes would also be denatured.
374
Define enthalpy of solution, with an example
DeltasolutionH is the enthalpy change when one mole of ionic compound is completely dissolved in water under standard conditions. e.g. NaCl(s)  Na+(aq) + Cl-(aq)
375
What is enthalpy of hydration with example
- Delta Hhydration¬ is the enthalpy which takes place when one mole of gaseous ions is dissolved in water forming one mole of aqueous ions under standard conditions - Na+(g) + aq  Na+(aq)
376
Why is enthalpy of hydration always exothermic?
These are exothermic as bonds are formed between the ions and water molecules
377
Factors Affecting Enthalpy of Hydration
Charge – the higher charge on the ion, the greater the attraction for the H2O molecules, therefore a more exothermic hydration Size – smaller ions have a greater charge density compared to the larger ions, this creates a greater attraction for H2O molecules, therefore a more exothermic hydration
378
Draw the general cycle of enthalpy of solution, hydration and lattice enthalpy
check notes
379
Equation that links lattice enthalpy, enthalpy of solution, and enthalpy of hydration
lattice enthalpy + enthalpy of solution = sum of the enthalpy of hydrations
380
Draw the titration curve for when HCl is added to NaOH
check notes
381
Draw the titration curve for when NaOH is added to HCl
check notes
382
Draw strong acid strong base titration curve
check notes
383
Draw strong acid weak base titration curve
check notes
384
Draw weak acid strong base titration curve
check notes
385
Draw weak acid weak base titration curve
check notes
386
The shape of the titration curve depends on what?
- Substance being titrated i.e. acid or base | - Type of acid or base i.e. strong or weak
387
Describe and explain parts of titration curve
1. Excess of base: pH decreases as acid added 2. Vertical section: acid base concentration similar, pH alters rapidly 3. Excess of acid: pH decreases slightly as acid is added 4. The equivalence point: halfway up the vertical section
388
What is the equivalence point?
The point halfway between the two horizontal lines on the titration curve The equivalence point is the volume required to have completely reacted the acid and base toetehr, stoichiometric volumes The pH at the equivalence point depend son the type of acid and base
389
Where is the equivalence point on each titration curve?
Equivalence point = 7 on SA-SB Equivalence point < 7 on SA-WB Equivalence point > 7 on WA-SB No equivalence point on WA-WB
390
Why is the equivalence point 0 on SASB titration curves?
- H+ ions completely neutralised by OH- ions, so only water and salt present, neutral
391
Why is the equivalence point < 7 on SAWB titration curves?
- A weak base, like NH3, will have a strong conjugate acid, NH4+ , which will react with water to produce H3O+ so the pH is less than 7
392
Why is the equivalence point > 7 on WASB titration curves?
- A weak acid, HA, will have a strong conjugate base, A-, which can react with water to produce OH- ions, so the pH is more than 7
393
What are acid-base indicators?
Acid-Base indicators are weak acids that have different coloured conjugate bases In acidic conditions the indicator equilibrium is shifted towards the weak acid (HIn) As the system becomes more basic the equilibrium shifts towards the conjugate base (In-), altering the colour
394
What is the end point?
The end point is when equal [HIn] and [In-] are present, the colour will therefore lie between both extremes Each indicator will have a different pH value for the end point as they each have different ka values
395
HIn
H+ + In-
396
How is an acid-base indicator chosen?
The indicator required for a titration must have a colour change that lies within the vertical section of a titration curve
397
A chemical reaction will proceed when?
A chemical reaction will proceed if the products are energetically more stable than the reactants
398
What is entropy?
Entropy is a measure of the dispersal of energy in a system, the more disordered a system the greater the dispersal of energy = higher entropy we define entropy as a measure of disorder
399
What happens to entropy over time?
Entropy must increase over time
400
When is a system in a state of high entorpy?
When its degree of disorder is high
401
As order within a system increases, its entropy decreases, why?
This can be explained in terms of probability: disordered states are simply more likely to exist (or emerge) than ordered states. The spontaneous direction of change is from a less probable to a more probable state
402
What does entropy always do?
The total entropy always increases, and the process is irreversible
403
What is the unit for entropy
S in JK^-1mol^-1
404
Why is S (entropy) alwasy potisive?
All substances process some degree of disorder because particles are always in constant motion
405
How does the entropy of each state differ?
Solid has lowest entropy, and gas has the highest
406
Draw a graph of waters change in enthalpy as temperaurer increases
check notes
407
Systems that are more chaotic have a _____ entropy value
higher
408
(s)  (s) + (g) , what is delta S
+
409
(g)  2(g) , what is delta S
+
410
What is delta S? | C2H5OH(l)  C2H5OH(g)
+
411
What is delta S? | C2H2(g) + 2H¬2(g)  C2H6(g)
-
412
What is delta S? | NH4Cl(s) + aq  NH4Cl(aq)
+
413
What is delta S? | 4Na(s) + O2(g)  2Na2O(s) deltaS
-
414
Define the standard entropy change
The standard entropy change is the entropy change that accompanies a reaction in the molar quantities expressed in the equation, under standard conditions
415
Sum for delta S^theta
delta S^theta = sum(S^theta products) – sum(S^theta reactants)
416
Why are exothermic reactions more preferable in nature?
as the products are more stable than reactants the key is not the decrease in energy but the associated increase in entropy of the surroundings.
417
deltaSsurroundings is proportional to what?
-deltaHsystem
418
deltaSsurroundings =
(-deltaHsystem)/T
419
deltaStotal =
deltaSsystem + deltaSsurroundings
420
deltaStotal >
0
421
What can we learn about the entropy of the sun by the photosynthesis equation?
6CO2(g) + 6H2O(l)  UV light  C6H12O6(s) + 6O2(g) Negative entropy change Entropy change in sun must be so positive it outweighs every plant on earth
422
What is gibbs free energy equation?
deltaG = deltaH – T deltaS < 0
423
How do you get to gibbs free energy equation?
deltaStotal¬ = deltaSsystem + deltaSsurroundings > 0 deltaStotal¬ = deltaSsystem – (deltaHsystem)/T > 0 T deltaStotal = T deltaSsystem – deltaHsystem > 0 -T deltaStotal = -T deltaSsytem + deltaHsystem < 0 deltaG = deltaH – T deltaS < 0
424
Using deltaG explain when a reaction is and is not feasible
deltaG must be negative (<0) for a reaction to be feasible i.e. proceed If deltaG is positive (>0) then a reaction is not feasible
425
What is deltaG at the points of feasibility?
At the point of feasibility, we can say deltaG = 0 (assume that deltaH and deltaS don’t vary with temperature)
426
At low temperatures what does deltaGsystem equal? why?
- At low temperatures, deltaGsystem = deltaH (-T deltaS becomes negligible) so for a reaction to occur it needs to be exothermic
427
At high tempertaures deltaGsystem ewuals what? why?
- At high temperatures, deltaGsystem = -T deltaS (deltaH becomes negligible) so for a reaction to occur it needs to have a positive deltaS as – T deltaS needs to be less than 0
428
Limitations to deltaG equation
just because the value is negative and so feasible it doesn’t mean it occurs, the reaction rate might be incredibly slow or the activation energy too high
429
What is an oxidation number?
An oxidation number shows the charge of an atom if all of its bonds were considered totally ionic
430
What are the oxidation number rules?
1. Elements in their natural state = 0 2. The total oxidation states in a molecule = 0 3. The total oxidation states in an ion = the charge Groups 1, 2, 3 - State +1, +2, +3 Fluorine - State -1 Hydrogen - State +1 -1 in metal hydrides Oxygen - State -2 -1 in peroxides Chlorine - State -1 + (varies) in chlorates
431
What is an oxidising agent?
takes electrons from what is oxidised
432
What is a reducing agent?
gives electrons to what is reduced
433
Write the half equations and full equation for | 4Na + O2  2Na2O
4Na  4Na+ + 4e- O2 + 4e-  2O2- 4Na + O2  4Na+ + 2O2-
434
Write the half equations for | Cu2O + H2SO4  Cu + CuSO4 + H2O
Cu+  Cu2+ + e- | 2Cu+  Cu + Cu2+
435
Steps of a redox titration using iron sulphate and sulphuric acid and potassium manganate (VII)
1. Make up a 150cm3 standard solution using 7g of iron sulphate by weighing by difference in a volumetric flask, record your mass measurements in a table 2. a. Pipette 25cm3 of the standard solution into a conical flask b. Add 10cm3 of 1M H2SO4 to the conical flask c. Fill the burette with a standard solution of 0.02M potassium manganate (VII) d. Carry out the titrations until the ed point is reached, the first permanent pink colour, record your results in a table e. Repeat until you have two concordant results f. Calculate the mean titre
436
Reduction: MnO4- + 8H+ + 5e-  Mn2+ + 4H2O Oxidation: Fe2+  Fe3+ + e- or 5Fe2+  5Fe3+ + 5e- MNO4- + 8H+ + 5Fe2+  Mn2+ + 4H2O + 5Fe3+ What is the oxidising and reducing agent?
Fe2+ is the reducing agent | MnO4- is the oxidizing agent
437
Mass of impure hydrated iron II sulphate = 6.97g 25cm3 of hydrated iron (II) sulphate used taken from a 250cm3 volumetric flask full of the dissolved iron tablets Mean titre of 0.02M potassium manganate (VII) = 23.4cm3 Calculate the percentage purity of the impure sample of FeSO4.7H2O
93.3%
438
What are the redox equations for the iodine/thiosulphate titrations?
I2 + 2e-  2I- 2S2O32-  S4O62- + 2e- I2 + 2S2O32-  2I- + S4O62-
439
What colour is iodine?
Iodine is a yellow brown solution
440
What colour is iodide?
Iodide is a straw colour
441
How do you know when an iodine/thiosulphate titration is complete?
Iodine is a yellow brown solution Iodide is a straw colour The above colour change is the indication for the redox reaction to be complete
442
Is an anode positive or negative?
Positive
443
Is a cathode positive or negative?
Negative
444
Draw a general cell
check notes
445
What is a cell? What is it made of? What does it do?
- A cell has two half cells - The two half cells must be connected with a salt bridge - Simple half cells will consist of a metal (acts as an electrode) and a solution of a compound containing that metal o For example, Cu and CuSO4 - These two half cells will produce a small voltage if connected into a circuit (become a battery or cell)
446
Draw the standard hydrogen half-cell
Check notes
447
What is the standard hydrogen half-cell?
- H+/H2 half-cell is chosen to produce standard potentials - H+ + e-  ½H2 - 1/2H2  H+ + e- - Conditions o 298K o 1atm o 1M H+ - Both equations have a voltage of 0.0 volts
448
Why is platinum used in the standard hydrogen half-cell?
Platinum is inert and so does not take part in the reaction
449
How can you find the value of any electron potential?
If the standard hydrogen half-cell is connected to another cell, you can find the value of any electron potential (as the standard is 0.0 volts).
450
Why a salt bridge? Using potassium chloride and copper as an example
- The salt bridge is used to connect up the circuit - The free moving ions conduct the charge - A salt bridge is usually made from a piece of filter paper (or material) soaked in a salt solution, usually potassium nitrate - The salt should be unreactive with the electrodes and electrode solutions o For example, potassium chloride would not be suitable for copper systems as chloride ions can form complexes with copper ions, a wire is not used because the metal wire would set up its own electrode system with the solutions
451
What is standard electrode potential?
The emf of a half cell compared with a standard hydrogen electrode at standard conditions of 298K, concentration 1.0M and 1 atm of pressure.
452
What is emf?
The emf is the difference in the positive and negative sides of the cell.
453
Describe a two ion cell system?
Both of the ions in the equation will be at a concentration of 1M, platinum electrode is used as it is INERT. 2 aqueous ions in a half equation, means they both have to be 1.0M solutions in the same half cell
454
Draw a manganese/lead system
check notes
455
General properties of d-block elements
The d-block elements have high melting and boiling points. | The d-block elements are good conductors of both electricity and heat.
456
What elements have been used in coinage for many years?
copper, silver, nickel, and zinc
457
What element is used extensively in construction and production of tools?
Iron
458
What element is used for electrical cables and water pipes?
Copper
459
Titanium has great strength, what are the elements applications?
It has many aerospace and medical applications (for example joint replacement).
460
Sc orbital configuration
[Ar] 4s2 3d1
461
Fe orbital configuration
Fe – [Ar] 4s2 3d6
462
Ni orbital configuration
Ni – [Ar] 4s2 3d8
463
Zn orbital configuration
Zn – [Ar] 4s2 3d10
464
Cr orbital configuration
Cr – [Ar] 4s1 3d5
465
Cu orbital configuration
Cu – [Ar] 4s1 3d10
466
How do copper and chromium minimize repulsions?
Copper and chromium minimize repulsions by being half full or full, chromium has 4s and 3d orbitals half full, copper has 3d full
467
Fe2+ orbital configuration
Fe2+ - [Ar] 4s0 3d6
468
Fe3+ orbital configuration
Fe3+ - [Ar] 4s0 3d5
469
Cu2+ orbital configuration
Cu2+ - [Ar] 4s0 3d9
470
Cr3+ orbital configuration
Cr3+ - [Ar] 4s0 3d3
471
Mn2+ orbital configuration
Mn2+ - [Ar] 4s0 3d5
472
Mn4+ orbital configuration
Mn4+ - [Ar] 4s0 3d3
473
Sc3+ orbital configuration
Sc3+ - [Ar] 4s0 3d0
474
Zn2+ orbital configuration
Zn2+ - [Ar] 4s0 3d10
475
Define a transition element
A transition element is a d-block element that forms at least one ion with an incomplete d sub-shell.
476
Which 'd' block elements do not fit the transition element definition?
- Scandium and zinc
477
What are some characteristic properties of transition metals and there compounds, with examples. (not conduction, melting, boiling etc.)
- They form compounds in which the transition element has different oxidative states o Fe2+ = +2 o Fe3+ = +3 - They form colored compounds - The elements and their compounds can act as catalysts o Fe in Haber process o Ni in hydrogenation of alkenes
478
A species containing a transition element in its highest oxidation state is often a what?
strong oxidizing agent
479
What does the observed colour of a solution depend on?
The observed colour of a solution depends on the wavelengths absorbed
480
Why does copper sulphate solution appear blue?
Copper sulphate solution appears blue because the energy absorbed corresponds to red and yellow wavelengths, wavelengths corresponding to blue light aren’t absorbed.
481
Draw the exam colour chart
check notes
482
If the colour we observe is red, what colour has been absorbed?
Cyan
483
What colour is cu2+
white
484
What colour is [Cu(H2O)6]2+
blue
485
Transition metals form complex ions or ?
coordination compounds
486
WHat do transition metals form when they make complex ions?
ligand forms bonds with the central transition metal ion
487
Examples of complex ions
[Cr(H2O)6]3+ [CuCl4]2-
488
What is a ligand?
a molecule or ion that can donate a pair of electrons with the transition metal ion to form a coordinate bond
489
What does monodentate mean?
Monodentate ‘one tooth’ means each ligand donates just one pair of electrons.
490
Examples of ligands and how many loan pairs they have
H2O (oxygen has two loan pairs) NH3 (nitrogen has a loan pair) Cl- (chloride has a loan pair) CN- (carbon has a loan pair) OH- (oxygen ha a loan pair)
491
Draw [Cu(H2O)6]2+
check notes
492
Describe the structure and bonding in [Cu(H2O)6]2+
- The central ion is Cu2+ - The ligands are water molecules o Each molecule donates a pair of electrons from the O atom to the Cu2+ to form a co-ordinate bond - The co-ordination number is 6 o This indicates the number of coordinate bonds to the central metal ion
493
What is the oxidation of Co in [Co(H2O)5Cl]+
+2
494
How to name complex ions?
- The name gives the metal ions and its oxidation state last, and the name/number of ligands before - Pre-fixes di, tri, tetra, penta, hexa used - Ligands are listed alphabetically, with prefixes not allowed to alter this order
495
[Cr(H2O)4Cl2]+ name
¬¬Tetraaquadichlorochromium (III) ion
496
[Co(H2O)5Cl]+ name
Pentaaquamonochlorocobalt (II) ion
497
If the complex ion is an anion, what do you do?
the suffix ‘-ate’ follows the metal
498
Name of [Fe(CN)6]4-
Hexacyanoferrate (II) ion
499
What does cobalt become in an anion complex ion?
cobaltate
500
What does aluminium become in an anion complex ion?
aluminate
501
What does chromium become in an anion complex ion?
chromate
502
What does vanadium become in an anion complex ion?
vanadate
503
What does copper become in an anion complex ion?
cuprate
504
What does iron become in an anion complex ion?
ferrate
505
What does nickel become in an anion complex ion?
nickelate
506
What does the value of pKa show?
The higher the value of pKa, the weaker the acid | The lower the value of pKa, the stronger the acid
507
Equation for finding hydrogen ion concentration in buffer
[H+] = ka x ([HA]/[A-])
508
In an electrochemical cell, where does oxidation happen?
the half-cell with the most negative standard electrode potential
509
What is the relationship between electrode potential and metal reactivity?
More negative electrode potential = more reactive the metal
510
Which equation links E (cell), E(positive electrode), and E(negative electrode)
E (cell) = Eo (positive electrode) – Eo (negative electrode)
511
The more reactive a metal is, the more likely it is to what?
to lose electrons and form a positive ion
512
More reactive metals have more negative electrode potentials and vice versa for what?
Non-metals
513
in general if the electrode potential for the reaction is positive it is regarded as being what?
feasible
514
What is the problem with predicting the feasibility of electrode reactions?
- The value of E says something about the feasibility of the reaction under standard conditions only - The value of E says something about the feasibility of the reaction, but does not say anything about the rate of the reaction
515
What is the anticlockwise rule?
Arrange the redox half equations so that: - The electrons are on the left - The largest negative electrode potentials are at the top - The reaction will then take place anticlockwise around the half equations - E (cell) = E (bottom) – E(top)
516
When does predicting feasibility of electrode reactions go wrong?
When the conditions are not standard, this includes: - A change in concentration - If the half equations are in equilibrium If the kinetics are not favorable: - The rate of reaction may be slow so reaction does not appear to happen - If the reaction has a high activation energy
517
Define catalyst
a substance that increases the rate of a chemical reaction by providing an alternative reaction pathway of lower activation energy (Ea)
518
What happens when Al3+, Ca2+, Mg2+ | Add NaOH or KOH or NH4OH
white precipitate
519
Description of solution, observation with NaOH, and equation for Copper Cu2+
Transparent blue Pale blue precipitate | Insoluble in excess Cu2+(aq) + 2OH-(aq)  Cu(OH)2(s)
520
Description of solution, observation with NaOH, and equation for Iron(II) Fe2+
Pale green Dark green precipitate Turns brown on contact with air Insoluble in excess Fe2+¬(aq) + 2OH-(aq)  Fe(OH)2(s)
521
Description of solution, observation with NaOH, and equation for Iron(III) Fe3+
Orange/brown Orange/brown precipitate | Insoluble in excess Fe3+(aq) + 3OH-(aq)  Fe(OH)3(s)
522
Description of solution, observation with NaOH, and equation for Chromium(III) Cr3+
Violet Grey-green precipitate Soluble in excess giving dark green solution Cr3+ + 3OH-(aq)  Cr(OH)3(s) Cr(OH)3(s) + 3OH-(aq)  [Cr(OH6]3-(aq)
523
Description of solution, observation with NaOH, and equation for Manganese(II) Mn2+
Pale pink Off white precipitate Rapidly turning brown on contact with air Insoluble in excess Mn2+(aq) + 2OH-(aq)  Mn(OH)2(s)
524
- Cu2+(aq) + 2e- Cu(s) | If we increase the concentration of Cu2+ ions then:
- Equilibrium moves to oppose the charge - Electrons are removed from the system - The electrode potential becomes more positive
525
What shape are four coordinate complex ions usualy? with examples
- Tetrahedral is the most common shape | - E.g. [CuCl4]2- and [CoCl4]2-
526
When not tertrahedral, what shape are 4 coordinate complexes, with examples
- Some 4 co-ordinate complex ions are square planar in shape, with the ligands arranged at the corners of a square - E.g. [Ni(NH3)2Cl2] (cis and trans)
527
When does a square planar shape take place in complex ions? example
- These occur in complexes with 8-d electrons in the d subshell. - E.g. Pt(II), Pd(II), Au(III)
528
What is cis platin used in?
- Cancer treatment in testicular cancer and useful for ovarian, head and neck, and lung cancer - Extremely toxic
529
Why did they change from cisplatin to carboplatin?
- Improved chemical stability relative to cisplatin due to chelation by cyclobutane dicarboxylic acid - Essentially equivalent antitumour activity to cisplatin
530
WHat is oaplatin used in?
treatment of colorectal cancer
531
Types of cancer therapy
- Surgery - Radiotherapy - Chemotherapy o Cytotoxic o Targeted  Anti-endocrine  Novel targeted agents - Immuno-therapy - Gene therapy
532
What is mustard Gas? What came about because of mustard gas?
- Potent vesicant agent that burns eyes, skin and respiratory tract Mustard Gas = war gas Nitrogen Mustard = anticancer drug
533
How does cisplatin treat cancer?
- The cisplatin binds to DNA and causes a critical structural change n the DNA – a bend of 45 degrees - This stops cell replication and leads to apoptosis (cell death)
534
Key points of lactic acid
- 2-hydroxy propanoic acid - Also known as lactic acid - The second carbon is a chiral center - The mirror image is non-superimposable o One is found in sour milk o The other is found in anaerobic respiration
535
What is a fuel cell?
a fuel cell is a device that converts chemical energy into electrical energy, water, and heat through electrochemical reactions.
536
How ddoes a fuel cell work? Are there many or one usually and why?
• Fuel and air react when they come into contact through a porous membrane (electrolyte) which separates them • This reaction results in a transfer of electrons and ions across the electrolyte from the anode to the cathode • If an external load is attached to this arrangement, a complete circuit is formed and a voltage is generated from the flow of electrical current The voltage generated by a single cell is typically rather small (< 1 volt), so many cells are connected in series to create a useful voltage.
537
Differences between a fuel cell and a battery
Hydrogen Fuel Cell – • Open system • Anode and cathode are gases in contact with a platinum catalyst • Reactants are externally supplied, no recharging required Galvanic Cell (Battery) – • Closed system • Anode and cathode are metals • Reactants are internally consumed, need periodic recharging
538
Differences between a fuel cell and an internal combustion engine
``` Fuel Cell – • Output is electrical work • Fuel and oxidant react electrochemically • Little to no pollution produced Internal Combustion Engine – • Output is mechanical work • Fuel and oxidant react combustively • Use of fossil fuels can produce significant pollution ```
539
Similarities between a fuel cell and in internal combustion engine
* Both use hydrogen-rich fuel * Both use compressed air as the oxidant * Both require cooling
540
Draw an alkaline fuel cell
check notes
541
What are the half equations, volatages, cell potential, and overall equation for an alkaline fuel cell?
Half Equations – 2H20 (l) + 2e-  H2 (g) + 2 OH- (aq) E = -0.83V ½ O2 (g) + 2e-  2 OH- (aq) E = +0.40V Cell Potential – = 0.4- -0.83 = 1.23V Overall Equation – H2 + ½ O2  H2O
542
Why Methanol not Hydrogen?
Some new fuel cells use methanol rather than hydrogen as the fuel because - Liquid methanol is easier to store then hydrogen gas - Methanol can be generated from biomass
543
Define electrochemical reaction
A reaction involving the transfer of electrons from one chemical substance to another
544
Define electrode
An electrical terminal that conducts an electric current into or out of a fuel cell (where the electrochemical reaction occurs).
545
Define electrolyte
A chemical compound that conducts ions from one electrode to the other
546
What is an electrochemical cell consisted of?
An electrochemical cell consists of 2 electrodes + 1 electrolyte
547
What is rhe equation for the number of optical isomers
- The number of isomers follows the equation: 2n, where n is the number of chiral centres
548
Why are optical isomers called such?
The isomers are called optical isomers as they can rotate plane-polarized light (light which only travels in one plane)
549
WHat makes a 6 co-ordinate compound cis or trans?
The bond angle between the two ligands which are different, e.g. 90' cis, 180' trans
550
What is a bidentate ligand? Example
Bidentate – ‘two tooth’ ligands | Most common is ethane-1, 2-diamine
551
Draw [Ni(NH2CH2CH2NH2)3]2+
Check notes
552
Describe and explain EDTA4-
A Hexadentate Ligand - EDTA4- has 6 lone pairs, each of which can form a co-ordinate bond - 1 EDTA ion reacts with 1 metal ion - Ethylenediaminetetraacetic acid (EDTA)
553
What is ligand substitution?
The addition of another ligand to a solution containing the aqua transition metal ion results in a substitution reaction
554
What occurs for ligand substitution?
- One or more ligands is exchanged for another - A change in colour of the solution is observed - Sometimes the complex ion changes shape/coordinate number
555
Colour of [Cu(H2O)6]2+, and its colour with dropwise and excess, ammonia and hydrochloric acid
Complex Ion [Cu(H2O)6]2+ Pale blue solution Addition of Ammonia Dropwise: Pale blue precipitation of copper(II) hydroxide Excess: Blue precipitate redissolves, forming a deep blue solution Addition of Concentrated HCl Dropwise: Begins to turn green Excess: Begins to turn yellow
556
Colour of [Cr(H2O)6]3+, and its colour with dropwise and excess, ammonia
Complex ion [Cr(H2O)6]3+ Violet solution Ammonia Dropwise: Grey/green precipitate Excess: Precipitate redissolves to produce a purple solution
557
Equation for addition of NaOH to [Cu(H2O)6]2+
[Cu(H2O)6]2+ + 2OH-  [Cu(H2O)4(OH)2]2+ + 2H2O
558
Equation for addition of NH3 to [Cu(H2O)6]2+ in dropwise and excess
[Cu(H2O)6]2+ + 2NH3  [Cu(H2O)4(OH)2]2+ + 2NH4+ | [Cu(H2O)6]2+ + 4NH3  [Cu(NH3)4(H2O)2]2+ + 4H2O
559
Equation for addition of HCl to [Cu(H2O)6]2+
[Cu(H2O)6]2+ + 4Cl- [CuCl4]2- + 6H2O
560
Equation for addition of ammonia to [Cr(H2O)6]3+
[Cr(H2O)6]3+ + 6NH3  [Cr(NH3)6]3+ + 6H2O
561
What is the stability constant?
Kstab – the equilibrium constant existing between a transition metal ion surrounded by water ligands and the complex formed when the same ion has undergone a ligand substitution reaction Like KC but for equilibrias including complex ions
562
Colour of Sc3+
Colourless
563
Colour of Ti2+
colourless
564
Colour of Ti3+
lilac
565
Colour of Ti+4
colourless
566
Colour of Ti5+
colourless
567
Colour of V2+
lilac
568
Colour of V3+
green
569
Colour of V4+
blue
570
Colour of V5+
yellow
571
Colour of Cr2+
blue
572
Colour of Cr3+
green
573
Colour of Cr4+
colourless
574
Colour of Cr5+
colourless
575
Colour of Cr6+
orange
576
Colour of Mn2+
pale pink
577
Colour of Mn+3
colourless
578
Colour of Mn4+
dark purple
579
Colour of Mn5+
colourless
580
Colour of Mn6+
green
581
Colour of Mn7+
lilac
582
Colour of Fe2+
pale green
583
Colour of Fe3+
pale yellow
584
Colour of Fe4+
colourless
585
Colour of Fe5+
colourless
586
Colour of Fe6+
colourless
587
Colour of Co2+
Pink
588
Colour of Co3+
green
589
Colour of Co4+
colourless
590
Colour of Co5+
colourless
591
Colour of Ni2+
green
592
Colour of Ni3+
colorless
593
Colour of Ni4+
colourless
594
Colour of Cu1+
colourless
595
Colour of Cu2+
blue
596
Colour of Cu3+
colourless
597
Colour of Zn2+
colourless
598
[Cu(H2O)6]2+ colour
blue solution
599
Cu(OH)2 colour
Blue precipitate
600
[Cu(NH3)4(H2O)2]2+ colour
Deep blue solution
601
[CuCl4]2- colour
Yellow solution
602
HCl + Cu2+(aq) reaction colour and why
the complex can look green as the reaction is reversible so both blue and yellow species present
603
[Fe(H2O)6]2+ colour
pale green solution
604
Fe(OH)2 colour
Green precipitate, if left in air a reddy brown colour appears (Fe2+ oxidizes to Fe3+)
605
[Fe(H2O)6]3+ colour
Yellow solution
606
Fe(OH)3 colour
Reddy brown precipitate
607
[Mn(H2O)6]2+ colour
Very pale solution
608
Mn(OH)2 colour
Light brown precipitate which darkens in air
609
[Cr(H2O)6]3+ colour
Violet solution
610
Cr(OH)3 colour
Grey/green precipitate
611
[Cr(OH)6]3- colour
Green solution
612
[Cr(NH3)6]3+
Purple solution
613
[Cu(H2O)6]2+ + 4NH3
[Cu(H2O)6]2+ + 4NH3  [Cu(NH3)4(H2O)2]2+ + 4H2O | Blue solution Deep blue solution
614
[Co(H¬2O)6]2+ + 6NH3
[Co(H¬2O)6]2+ + 6NH3  [Co(NH3)6]2+ + 6H2O
615
[Cu(H2O)6]2+ + 4Cl-
[Cu(H2O)6]2+ + 4Cl-  [CuCl4]2- + 6H2O | Blue solution Yellow/green solution
616
[Co(H2O)6]2+ + 4Cl-
[Co(H2O)6]2+ + 4Cl-  [CoCl4]2- + 6H2O | Pink solution Blue solution
617
Cu2+ + 2OH-  Cu(OH)2 colours
Cu2+ + 2OH-  Cu(OH)2 | Blue solution  blue precipitate
618
Mn2+ + 2OH-  Mn(OH)2 colours
Mn2+ + 2OH-  Mn(OH)2 | Very pale pink solution  pale brown precipitate
619
Fe2+ + 2OH-  Fe(OH)2 COLOURs
Fe2+ + 2OH-  Fe(OH)2 | Green solution  green precipitate
620
Fe3+ + 3OH-  Fe(OH)3 colours
Fe3+ + 3OH-  Fe(OH)3 | Yellow/brown solution  brown precipitate
621
Cr3+ + 3OH-  Cr(OH)3 colours
Cr3+ + 3OH-  Cr(OH)3 | Green solution  green precipitate
622
[Mn(H2O)6]2+ + 2NH3
[Mn(H2O)6]2+ + 2NH3  Mn(H2O)4(OH)2 + 2NH4+
623
[Fe(H2O)6]3+ + 3NH3
[Fe(H2O)6]3+ + 3NH3  Mn(H2O)3(OH)3 + 3NH4+
624
Cr(H2O)3(OH)3 + 3OH-
Cr(H2O)3(OH)3 + 3OH-  [Cr(OH)6]3- + 3H2O | Green precipitate  green solution
625
Cr(H2O)3(OH)3 + 3H+
Cr(H2O)3(OH)3 + 3H+  [Cr(H2O)6]3+ | Green precipitate  green solution
626
Cr(OH)3(H2O)3 + 6NH3
Cr(OH)3(H2O)3 + 6NH3  [Cr(NH3)6]3+ + 3H2O + 3OH- | Green precipitate  purple solution
627
Cu(OH)2(H2O)4 + 4NH3
Cu(OH)2(H2O)4 + 4NH3  [Cu(NH3)4(H2O)2]2+ + 2H2O + 2OH- | Blue precipitate  deep blue solution