topic 6 Flashcards

(23 cards)

1
Q

l

A

is the orbital angular momentum quantum number
- take any integer (n-1)
- vector quantity
- equation angular momentum = position vector x momentum vector
- only magnitude and one spatial component can be predicted simultaneously due to Heisenberg uncertainty principle
- describes the shape

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2
Q

ml

A

magnetic quantum number
- can be any number ranging from -l to l
- describes orientation of atomic orbitals

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3
Q

angular momentum

A
  • ## vector quantity
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4
Q

how to calculate the magnitude for orbital angular momentum

A
  • square root ( (l(l+1) x reduced planks constant)
  • l = orbital angular momentum principle number
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5
Q

how to calculate the orientation in orbital angular momentum

A
  • lz = ml x reduced planks constant
  • ml = magnetic quantum number
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6
Q

to completely describe state of an electron in atom we must

A

specify wavenumber mlml and its spin state -

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7
Q

spin angular momentum

A
  • spin angular momentum quantum number, s = 1/2
  • spin magnetic quantum number ms = +/- 1/2
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8
Q

quantises the magnitude of the spin angular momentum

A
  • (square root (3))/2 reduced planks constant
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9
Q

ms quantises its projections along z giving rise to

A

spin up and spin down states
sz = +/- 1/2 reduced planks constant

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10
Q

solving the SE for the equation for H atom means

A
  • a quantum of a description of the atom
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11
Q

what describes the size, shape and orientation of an orbital

A
  • size = principle quantum number n
  • shape = angular momentum quantum number l
  • orientation = magnetic quantum number ml
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12
Q

radial distribution functions

A
  • gives probability of finding an electron within a spherical shell at thickness dr at a distance of r from the nucleus of the atom though born approximation
  • r = 0, zero probability
  • radial nodes = values of r where there is zero probability of finding an electron
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13
Q

angular wave functions

A
  • angular component of wavefunction determines the shape of the orbitals
  • for s orbitals l=0, there is no angular dependence of the wavfunction and the orbitals are spherically symmetrical
  • therefore no angular nodes
  • psotivie and negative wave function are separated by the radial nodes (wave function =0)
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14
Q

angular nodes

A
  • nodal planes where wave function = 0
  • s orbitals have no angular nodes
  • p orbitals have one angular node
  • number of angular nodes = l
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15
Q

radial nodes

A
  • nodal surfaces where wavefucntion = 0
  • s orbitals have max in wave function at nucleus
  • other orbitals wave function = 0 at nucleus
  • all orbitals decay exponentially as r tends to infinity
  • number radial nodes = n-l-1
  • occur at p(r) = 0
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16
Q

total number of nodes

A

(angular + radial)
= n-1

17
Q

ionisation energy

A
  • energy required to move one electron of atom from ground state to infinite distance from the nucleus
18
Q

expect hydrogenic ions to have ionisation energjes and spectral lines to have …

A

wavenumbers that are Z^2 larger than hydrogen
- use equation for ionisation energy x (z^2/n^2)
- reality not always true, some assumptions become less valid for heavier atoms

19
Q

population factors rules effecting appearance of atomic spectrum

A
  • absoprtion and emission between two states can only occur if sufficient number of atoms in initial state
  • intensity of spectral lines associated with transition is proportional to ni/N
  • Given by Boltzmann distribution
  • greater population = more light absorbed
20
Q

selection rules for transitions

A
  • stem from conservation of angular momentum
  • electron angula momentum and magnetic quantum number need to change to compensate for loss or creation of angular momentum of a photon
  • change n no restrictions
  • change in l = +/- l
  • change in ml = 0, +/- 1
  • energy and mass conserved
21
Q

atomic spectrum of hydrogen

A
  • grotrian diagram
  • shows absoprtion transition from np level are allowed by selection rule l = +/- 1
  • only see Lyman series in absorption due to low Boltzmann population factor of n = 2
  • uv and em spectrum
  • allowed transitions for hydrogen with n = 2 as lower energy state can be observed in grotrian diagram in emission
22
Q

stern - gerlach experiment

A
  • diffraction expected one dot
  • observed appearance of 2 clear atom trajectories in applied field means must be another angular momentum with a quantum number 1/2
23
Q

key effect causing the deviation from the prediction of the SE

A
  • spin - orbital coupling
  • stems from fact electron posses own intrinsic angular momentum (spin)
  • discovered from Stern - Gerlach experiment