Transition Metals

Question 1

Purple colours

Answer 1

• Ti3+= purple + Mn04-

Question 2

Violet colours

Answer 2

• Ti2+, V2+

Question 3

Green colour

Answer 3

• V3+ , Cr3+, Ni2+, mnO4 2-, fe 2+( pale)

Question 4

Orange colour

Answer 4

• Cr2072-

Question 5

Yellow colour

Answer 5

VO2+ , Fe3+

Question 6

Pink colour

Answer 6

• Mn2+(pale), Co2+

Question 7

[cu(H20)6]2+ + 4NH3 = [Cu(NH3)4(H20)2]2+ + 4H20

Answer 7

Colour change of octahedral pale blue to octahedral deep blue

Question 8

[cu(H20)6]2+ 4CL- = [CuCL4)2- + 6H20

Answer 8

Octahedral pale blue to tetrahedral yellow

Question 9

[cu(H20)6]3+ + 6NH3= [Cr(NH3)6]3+ + 6H20

Answer 9

-octahedral dark green to octahedral purple

Question 10

Inconversions between Fe2+ ( paks green) and Fe3+ (yellow)

Answer 10

• Fe2+ can be oxidised with H+/Mn04- and Fe3+ reduced with Zn/H+

When writing half equation. Electrons on left for reduction right for oxidation. A

Question 11

Inconversions between Cr3+( dark green) to yellow cr2072-

Answer 11

Cr3+ oxidised with H202/OH- and cr2072- reduced with Zn/H+

Question 12

Reduction of Cu2+ and Cu+

Answer 12

• uses iodide ion.

-Cu+ is disproportionated to cu2+ and CU

Question 13

Transition metal coloured preticipate

Answer 13

• reaction with OH- and NH3 preticipates just forms a darker colour of the original elements.
• test with sodium hydroxide can test for this

E.g. Cu2+ (pale blue) forms a blue precipitate

Question 14

Identifying ligand tests

Answer 14

• C032-= nitric acid and bubble gas through limewater= limewater clear to cloudy
• halogens = silver nitrate. White, cream, yellow
• sulfate= barium ions. White preticipate formed
• ammonium(NH4+) = add NaOH warm. Turns red litmus paper blue