Transition metals Flashcards

(44 cards)

1
Q

Fe 2+ in aqueous solution

A

[Fe(H2O)6]2+ green solution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Cu 2+ in aqueous solution

A

[Cu(H2O)6]2+ blue solution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Fe 3+ in aqueous solution

A

[Fe(H2O)6]3+. pale violet solution but appears orange due to hydrolysis to some [Fe(H2O)5(OH)]2+

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Al 3+ in aqueous solution

A

[Al(H2O)6]3+ colourless solution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Add aqueous NaOH dropwise to Fe2+

A

[Fe(H2O)4(OH)2] green precipitate (darkens on standing due to oxidation to [Fe(H2O)3(OH)3]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Add aqueous NaOH dropwise to Cu 2+

A

[Cu(H2O)4(OH)2] blue precipitate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Add aqueous NaOH dropwise to Fe3+

A

[Fe(H2O)3(OH)3] brown precipitate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Add aqueous NaOH dropwise to Al3+

A

[Al(H2O)3(OH)3] white precipitate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

addition of excess aqueous NaOH to Fe2+

A

no further reaction form when was added dropwise

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

addition of excess aqueous NaOH to Cu2+

A

no further reaction form when was added dropwise

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

addition of excess aqueous NaOH to Fe3+

A

no further reaction form when was added dropwise

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

addition of excess aqueous NaOH to Al3+

A

[Al(H2O)2(OH)4]- re-dissolved to give colourless solution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

adding aqueous NH3 dropwise to Fe2+

A

[Fe(H2O)4(OH)2] green precipitate which darkens on standing due to oxidation causing [Fe(H2O)3(OH)3]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

adding aqueous NH3 dropwise to Cu2+

A

[Cu(H2O)4(OH)2] blue precipitate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

adding aqueous NH3 dropwise to Fe3+

A

[Fe(H2O)3(OH)3] brown precipitate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

adding aqueous NH3 dropwise to Al3+

A

[Al(H2O)3(OH)3] white precipitate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Adding excess aqueous NH3 to Fe2+

A

no further reaction form when it was added dropwise

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Adding excess aqueous NH3 to Cu2+

A

[Cu(H2O)2(NH3)4]2+ deep blue solution

19
Q

Adding excess aqueous NH3 to Fe3+

A

no further reaction form when it was added dropwise

20
Q

Adding excess aqueous NH3 to Al3+

A

no further reaction form when it was added dropwise

21
Q

adding aqueous Na2CO3 to Fe2+

A

FeCO3 green precipitate

22
Q

adding aqueous Na2CO3 to Cu2+

A

CuCO3 blue-green precipitate

23
Q

adding aqueous Na2CO3 to Fe3+

A

[Fe(H2O)3(OH)3] brown precipitate and bubbles of CO2 gas

24
Q

adding aqueous Na2CO3 to Al3+

A

[Al(H2O)3(OH)3] white precipitate and bubbles of CO2 gas

25
adding concentrated HCl to Fe2+
[FeCl4]2- yellow solution
26
adding concentrated HCl to Cu2+
[CuCl4]2-green solution
27
adding concentrated HCl to Fe3+
[FeCl4]-yellow solution
28
adding concentrated HCl to Al3+
[AlCl4]- colourless solution
29
reaction between iodide ions and S2O8 2- catalysed by Fe
S2O8 2- + 2Fe2+ - --> 2 SO4 + 2Fe3+ 2I- + 2Fe3+ - --> I2 + 2Fe2+ all arrows are reversible reactions can occur either way round which is why Fe2+ or Fe3+ can be the catalyst overall: 2 I- + S2O8 2- --> I2 + 2 SO4 2-
30
contact process
-catalysed by V2O5 V2O5 + SO2 --> V2O4 + SO3 V2O4 + 0.5O2 --> V2O5 overall: 2 SO2 + O2 --> 2 SO3
31
colours of vanadium ions oxidation state = +5
VO2 + yellow
32
colours of vanadium ions oxidation state = +4
VO 2+ blue
33
colours of vanadium ions oxidation state = 3+
V 3+ green
34
colours of vanadium ions oxidation state = 2+
V 2+ violet
35
haber process
3 H2 + N2 --> 2 NH3 reversible reaction arrow
36
reaction of ethanedioate ions and manganate ions
2 MnO4- + 16H+ + 5C2O42- --> 2 Mn2+ + 8 H20 + 10 CO2 catalysed by Mn2+ ions
37
reaction of manganate ions and iron ions
MnO4- + 8 H+ + 5 Fe 2+ --> Mn2+ + 4 H2O + 5 Fe 3+
38
role of iron as a catalyst in the haber process
Heterogeneous catalysts: -heterogeneous catalyst which is in a different physical state to reactants -catalyst speeds up rate of reaction by lowering activation energy by providing an alternative reaction pathway (left unchanged) How to works on the haber process: -hydrogen and nitrogen adsorb onto the surface (active sites) of the iron -the bonds weaken and the reaction takes place -the products desorb and leave the surface of the iron How to increase/what affects efficiency: -large surface area by using a powder or small pellets (or support medium/mesh) -the catalyst is poisoned as the sulfur binds to the catalyst -the active sites are blocked
39
what is an autocatalyst
a type of homogenous catalyst where the product is also a catalyst
40
how do heterogenous catalysts work
-different physical state to the reactants -adsorbed onto the molecules active site and weakens the covalent bonds so reaction can occur more easily and rate is increased -they can be poisoned by impurities which blocks the active site and prevents adsorption (so the bonds remain strong) -reaction impurities increase chemical production costs as the catalyst has to be replaced or cleaned regularly -rate can be increased by using a powder as increases surface area
41
why might there be impurities in the heterogeneous catalyst iron in the haber process
-the H2 is made from methane which contains sulfur impurities -the sulfur will adsorb to the surface forming iron sulfide -this makes the catalyst less efficient so needs to be cleaned or replaced often which is expensive
42
how do homogenous catalysts work
-same physical state as the reactants -the catalyst combines the reactants to produce a reactive intermediate -this changes the reaction pathway as the activation energy is initially high as two negative ions repel , so the enthalpy change for the formation of the intermediate is lower than the original reaction, so it is more feasible
43
oxidation of iodide ions catalysed by the homogenous catalyst iron
S2O8 2- + 2Fe 2+ --> 2Fe 3+ + 2SO4 -the intermediate Fe£+ produced catalyses 2I- + 2Fe 3+ --> 2 Fe 2+ + I2
44
reduction of VO2 (+) to V (3+) by Zn charges in ()
2 VO2(+) + Zn + 4H(+) --> 2VO(2+) + Zn(2+) + 2H2O yellow --> blue 2VO(2+ )+ Zn + 4H(+) --> 2V (3+) + Zn(2+) + 2H20 Blue --> green 2V(3+) + Zn --> 2V(2+) + Zn(2+) green --> violet